Biology: Genetics and Cell Biology: cram pack

Formula sheets, the key method steps for every topic and 4 practice problems, with full solutions at the back.

New problemsBack to the course

In the print window, choose “Save as PDF” to keep a copy on your device.

1Formulas and methods

Genetics

Monohybrid cross (Aa × Aa)
genotypes 1 : 2 : 1, phenotypes 3 : 1
Dihybrid cross
phenotypes 9 : 3 : 3 : 1
Hardy–Weinberg
p + q = 1, p² + 2pq + q² = 1
Independent genes
multiply the probabilities

2Practice problems

1.GeneticsMedium
♂♀XD​YXd​XD​

Duchenne muscular dystrophy is X-linked recessive (allele d). A carrier mother, XDXd, has children with an unaffected father, XDY. The mother's gametes run down the side. Click the cell for a carrier daughter.

♀ XDXd♂ XDY
  1. 1Xd × XD
  2. 2Xd × Y
  3. 3XD × XD
  4. 4XD × Y
2.GeneticsHard
AA?AaAaaap (A)q (a)p (A)q (a)q² = 0.01N = 1000

In a population of 1000 in Hardy–Weinberg equilibrium, 1% show a recessive trait. How many individuals N are expected to be homozygous dominant?

N = 1000q² = 0.01
N =
3.Cell biologyMedium

How do large proteins such as transcription factors enter the nucleus?

  1. AThrough nuclear pore complexes, guided by a nuclear localisation signal
  2. BBy diffusing freely through the nuclear membrane lipids
  3. CBy exocytosis from the endoplasmic reticulum
  4. DThey are made inside the nucleus by nuclear ribosomes, so they never enter
4.Cell biologyHard

In eukaryotic mRNA processing, splicing removes:

  1. AExons
  2. BIntrons
  3. CThe 5′ cap
  4. DThe poly-A tail

3Solutions

1.Genetics

Answer: Xd × XD

Punnett square: one parent's gametes run along the top, the other's down the side. Each cell joins the gamete above it with the gamete beside it, and every cell is equally likely. A recessive trait only shows when both alleles are recessive; for an X-linked trait, sons get their only X from the mother.

Fill the square

XdXD, XdY, XDXD, XDY

Find the cell

Xd × XD = XdXD

Answer

Cell Xd × XD → XdXD
2.Genetics

Answer: N = 810

Hardy–Weinberg: in a large, randomly mating population with no selection, the allele frequencies p (dominant) and q (recessive), p + q = 1, give genotype frequencies p², 2pq and q².

Allele frequencies

q = √0.01 = 0.1
p = 0.9

Homozygous dominant

p² = 0.81
N = 1000·0.81 = 810

Answer

N = 810
3.Cell biology

Answer: A · Through nuclear pore complexes, guided by a nuclear localisation signal

Why this is the answer

Proteins with a nuclear localisation signal are recognised by importins and carried through nuclear pore complexes. Translation happens in the cytoplasm.

Answer

A · Through nuclear pore complexes, guided by a nuclear localisation signal
4.Cell biology

Answer: B · Introns

Why this is the answer

The spliceosome removes introns and joins exons; the 5′ cap and poly-A tail are added for stability and export.

Answer

B · Introns

ExamProblems · examproblems.com/courses/biology