Biology: Genetics and Cell Biology: cram pack

Formula sheets, the key method steps for every topic and 4 practice problems, with full solutions at the back.

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1Formulas and methods

Genetics

Monohybrid cross (Aa × Aa)
genotypes 1 : 2 : 1, phenotypes 3 : 1
Dihybrid cross
phenotypes 9 : 3 : 3 : 1
Hardy–Weinberg
p + q = 1, p² + 2pq + q² = 1
Independent genes
multiply the probabilities

2Practice problems

1.GeneticsMedium
AaBb ♀aabb ♂ABAbaBababababab????????????????

Tall (A) is dominant over short (a), and round seeds (B) over wrinkled (b). The genes are on different chromosomes. For the cross AaBb × aabb, what is the probability P that an offspring is tall, wrinkled seeds?

AaBb × aabb
P =
2.GeneticsHard
♂ AaBb♀ AaBbabAbaBABabaBABAb

Two AaBb parents are crossed. Gene A gives black fur (dominant) or white fur; gene B gives tall plants (dominant) or short plants. Click the one cell for an offspring that is homozygous for black fur and shows short plants.

AaBb × AaBb
  1. 1ab × ab
  2. 2ab × Ab
  3. 3ab × aB
  4. 4ab × AB
  5. 5aB × ab
  6. 6aB × Ab
  7. 7aB × aB
  8. 8aB × AB
  9. 9AB × ab
  10. 10AB × Ab
  11. 11AB × aB
  12. 12AB × AB
  13. 13Ab × ab
  14. 14Ab × Ab
  15. 15Ab × aB
  16. 16Ab × AB
3.Cell biologyMedium

Which tag added in the Golgi sends enzymes to the lysosomes?

  1. AUbiquitin
  2. BMannose-6-phosphate
  3. CA nuclear localisation signal
  4. DA KDEL sequence
4.Cell biologyHard

Which checkpoint ensures all chromosomes are attached to the spindle before anaphase begins?

  1. AThe G2/M checkpoint
  2. BThe G1/S checkpoint
  3. CThe spindle assembly (metaphase) checkpoint
  4. DThe S-phase checkpoint

3Solutions

1.Genetics

Answer: P = 0.25

Mendelian genetics: each parent passes on one allele of each gene, chosen at random. A Punnett square lists every combination of gametes, each equally likely. A dominant allele (capital letter) shows whenever it is present; a recessive one only in the homozygous form. Genes on different chromosomes are inherited independently, so their probabilities multiply.

Each gene on its own

P(tall) = 0.5
P(wrinkled seeds) = 0.5

Multiply

P = 0.5·0.5 = 0.25

Answer

P = 0.25
2.Genetics

Answer: Ab × Ab

Punnett square: one parent's gametes run along the top, the other's down the side. Each cell joins the gamete above it with the gamete beside it, and every cell is equally likely. A recessive trait only shows when both alleles are recessive; for an X-linked trait, sons get their only X from the mother.

Genotype asked for

AAbb

Gametes

A homozygous genotype needs the same gamete from both parents, so only one cell in the 16 fits.

Ab × Ab = AAbb

Answer

Cell Ab × Ab → AAbb
3.Cell biology

Answer: B · Mannose-6-phosphate

Why this is the answer

In the Golgi, lysosomal enzymes receive mannose-6-phosphate. Receptors that bind this tag package them into vesicles bound for lysosomes.

Answer

B · Mannose-6-phosphate
4.Cell biology

Answer: C · The spindle assembly (metaphase) checkpoint

Why this is the answer

The spindle checkpoint delays anaphase until every kinetochore is attached, preventing unequal chromosome distribution.

Answer

C · The spindle assembly (metaphase) checkpoint

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