Biology: Genetics and Cell Biology: cram pack

Formula sheets, the key method steps for every topic and 4 practice problems, with full solutions at the back.

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1Formulas and methods

Genetics

Monohybrid cross (Aa × Aa)
genotypes 1 : 2 : 1, phenotypes 3 : 1
Dihybrid cross
phenotypes 9 : 3 : 3 : 1
Hardy–Weinberg
p + q = 1, p² + 2pq + q² = 1
Independent genes
multiply the probabilities

2Practice problems

1.GeneticsMedium
♂♀XH​YXh​XH​

haemophilia is X-linked recessive (allele h). A carrier mother, XHXh, has children with an unaffected father, XHY. The mother's gametes run down the side. Click the cell for an affected son.

♀ XHXh♂ XHY
  1. 1Xh × XH
  2. 2Xh × Y
  3. 3XH × XH
  4. 4XH × Y
2.GeneticsHard
AAAa?Aa?aap (A)q (a)p (A)q (a)q² = 0.04f = ?

A recessive condition affects 4% of a population in Hardy–Weinberg equilibrium. What fraction f of the population are carriers (heterozygous)?

q² = 0.04
f =
3.Cell biologyMedium

A codon consists of:

  1. AOne nucleotide
  2. BA whole gene
  3. CThree nucleotides on mRNA that code for an amino acid or a stop signal
  4. DThree amino acids
4.Cell biologyHard

In E. coli, under which conditions is the lac operon most strongly transcribed?

  1. ALactose present and glucose absent
  2. BLactose absent and glucose present
  3. CBoth lactose and glucose present
  4. DBoth lactose and glucose absent

3Solutions

1.Genetics

Answer: Xh × Y

Punnett square: one parent's gametes run along the top, the other's down the side. Each cell joins the gamete above it with the gamete beside it, and every cell is equally likely. A recessive trait only shows when both alleles are recessive; for an X-linked trait, sons get their only X from the mother.

Fill the square

XhXH, XhY, XHXH, XHY

Find the cell

Xh × Y = XhY

Answer

Cell Xh × Y → XhY
2.Genetics

Answer: f = 0.32

Hardy–Weinberg: in a large, randomly mating population with no selection, the allele frequencies p (dominant) and q (recessive), p + q = 1, give genotype frequencies p², 2pq and q².

Allele frequencies

q = √0.04 = 0.2
p = 1 − 0.2 = 0.8

Carriers

2pq = 2·0.8·0.2 = 0.32

Answer

f = 0.32
3.Cell biology

Answer: C · Three nucleotides on mRNA that code for an amino acid or a stop signal

Why this is the answer

Each triplet of bases specifies an amino acid or stop; the genetic code is redundant (several codons per amino acid).

Answer

C · Three nucleotides on mRNA that code for an amino acid or a stop signal
4.Cell biology

Answer: A · Lactose present and glucose absent

Why this is the answer

Lactose (as allolactose) removes the repressor. Low glucose raises cAMP, which activates CAP to boost transcription. Both are needed for maximal expression.

Answer

A · Lactose present and glucose absent

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