Biology: Genetics and Cell Biology: cram pack

Formula sheets, the key method steps for every topic and 4 practice problems, with full solutions at the back.

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1Formulas and methods

Genetics

Monohybrid cross (Aa × Aa)
genotypes 1 : 2 : 1, phenotypes 3 : 1
Dihybrid cross
phenotypes 9 : 3 : 3 : 1
Hardy–Weinberg
p + q = 1, p² + 2pq + q² = 1
Independent genes
multiply the probabilities

2Practice problems

1.GeneticsMedium
♂♀YXH​Xh​XH​

haemophilia is X-linked recessive (allele h). A carrier mother, XHXh, has children with an unaffected father, XHY. The mother's gametes run down the side. Click the cell for a carrier daughter.

♀ XHXh♂ XHY
  1. 1Xh × Y
  2. 2Xh × XH
  3. 3XH × Y
  4. 4XH × XH
2.GeneticsHard
AA?AaAaaap (A)q (a)p (A)q (a)q² = 0.01N = 500

In a population of 500 in Hardy–Weinberg equilibrium, 1% show a recessive trait. How many individuals N are expected to be homozygous dominant?

N = 500q² = 0.01
N =
3.Cell biologyMedium

Which cell junction anchors intermediate filaments and gives tissues such as skin mechanical strength?

  1. APlasmodesma
  2. BTight junction
  3. CDesmosome
  4. DGap junction
4.Cell biologyHard

A disease is passed from an affected mother to all her children but never from an affected father. Where is the mutation most likely located?

  1. AOn the Y chromosome
  2. BIn mitochondrial DNA
  3. COn the X chromosome, as a dominant trait
  4. DOn an autosome, as a recessive trait

3Solutions

1.Genetics

Answer: Xh × XH

Punnett square: one parent's gametes run along the top, the other's down the side. Each cell joins the gamete above it with the gamete beside it, and every cell is equally likely. A recessive trait only shows when both alleles are recessive; for an X-linked trait, sons get their only X from the mother.

Fill the square

XhY, XhXH, XHY, XHXH

Find the cell

Xh × XH = XhXH

Answer

Cell Xh × XH → XhXH
2.Genetics

Answer: N = 405

Hardy–Weinberg: in a large, randomly mating population with no selection, the allele frequencies p (dominant) and q (recessive), p + q = 1, give genotype frequencies p², 2pq and q².

Allele frequencies

q = √0.01 = 0.1
p = 0.9

Homozygous dominant

p² = 0.81
N = 500·0.81 = 405

Answer

N = 405
3.Cell biology

Answer: C · Desmosome

Why this is the answer

Desmosomes link the keratin intermediate filaments of neighbouring cells via cadherins, so tissues under stress do not tear apart.

Answer

C · Desmosome
4.Cell biology

Answer: B · In mitochondrial DNA

Why this is the answer

Mitochondria, and their DNA, are inherited almost only from the egg. Mitochondrial disorders therefore follow maternal inheritance.

Answer

B · In mitochondrial DNA

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