Biology: Genetics and Cell Biology: cram pack

Formula sheets, the key method steps for every topic and 4 practice problems, with full solutions at the back.

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1Formulas and methods

Genetics

Monohybrid cross (Aa × Aa)
genotypes 1 : 2 : 1, phenotypes 3 : 1
Dihybrid cross
phenotypes 9 : 3 : 3 : 1
Hardy–Weinberg
p + q = 1, p² + 2pq + q² = 1
Independent genes
multiply the probabilities

2Practice problems

1.GeneticsMedium
AaBb ♀Aabb ♂ABAbaBabAbAbabab????????????????

Tall (A) is dominant over short (a), and round seeds (B) over wrinkled (b). The genes are on different chromosomes. For the cross AaBb × Aabb, what is the probability P that an offspring is tall, round seeds?

AaBb × Aabb
P =
2.GeneticsHard
♂ AaBb♀ AaBbAbabABaBabABAbaB

Two AaBb parents are crossed. Gene A gives purple flowers (dominant) or white flowers; gene B gives tall plants (dominant) or short plants. Click the one cell for an offspring that is shows white flowers and is homozygous for tall plants.

AaBb × AaBb
  1. 1ab × Ab
  2. 2ab × ab
  3. 3ab × AB
  4. 4ab × aB
  5. 5AB × Ab
  6. 6AB × ab
  7. 7AB × AB
  8. 8AB × aB
  9. 9Ab × Ab
  10. 10Ab × ab
  11. 11Ab × AB
  12. 12Ab × aB
  13. 13aB × Ab
  14. 14aB × ab
  15. 15aB × AB
  16. 16aB × aB
3.Cell biologyMedium

A competitive inhibitor binds the active site of an enzyme. What can overcome its effect?

  1. ARaising the inhibitor concentration
  2. BRaising the substrate concentration
  3. CLowering the temperature to 0 °C
  4. DRemoving the enzyme's cofactor
4.Cell biologyHard

Where in the cell does the electron transport chain of aerobic respiration take place?

  1. AOuter mitochondrial membrane
  2. BMitochondrial matrix
  3. CInner mitochondrial membrane
  4. DCytoplasm

3Solutions

1.Genetics

Answer: P = 0.375

Mendelian genetics: each parent passes on one allele of each gene, chosen at random. A Punnett square lists every combination of gametes, each equally likely. A dominant allele (capital letter) shows whenever it is present; a recessive one only in the homozygous form. Genes on different chromosomes are inherited independently, so their probabilities multiply.

Each gene on its own

P(tall) = 0.75
P(round seeds) = 0.5

Multiply

P = 0.75·0.5 = 0.375

Answer

P = 0.375
2.Genetics

Answer: aB × aB

Punnett square: one parent's gametes run along the top, the other's down the side. Each cell joins the gamete above it with the gamete beside it, and every cell is equally likely. A recessive trait only shows when both alleles are recessive; for an X-linked trait, sons get their only X from the mother.

Genotype asked for

aaBB

Gametes

A homozygous genotype needs the same gamete from both parents, so only one cell in the 16 fits.

aB × aB = aaBB

Answer

Cell aB × aB → aaBB
3.Cell biology

Answer: B · Raising the substrate concentration

Why this is the answer

Because substrate and inhibitor compete for the active site, enough substrate can outcompete the inhibitor. Vmax is unchanged but the apparent Km rises.

Answer

B · Raising the substrate concentration
4.Cell biology

Answer: C · Inner mitochondrial membrane

Why this is the answer

Complexes of the ETC sit in the inner membrane, pumping protons into the intermembrane space; ATP synthase uses the gradient.

Answer

C · Inner mitochondrial membrane

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