Biology: Genetics and Cell Biology: cram pack

Formula sheets, the key method steps for every topic and 4 practice problems, with full solutions at the back.

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1Formulas and methods

Genetics

Monohybrid cross (Aa × Aa)
genotypes 1 : 2 : 1, phenotypes 3 : 1
Dihybrid cross
phenotypes 9 : 3 : 3 : 1
Hardy–Weinberg
p + q = 1, p² + 2pq + q² = 1
Independent genes
multiply the probabilities

2Practice problems

1.GeneticsMedium
AaBb ♀Aabb ♂ABAbaBabAbAbabab????????????????

Tall (A) is dominant over short (a), and round seeds (B) over wrinkled (b). The genes are on different chromosomes. For the cross AaBb × Aabb, what is the probability P that an offspring is tall, wrinkled seeds?

AaBb × Aabb
P =
2.GeneticsHard
AAAa?Aa?aap (A)q (a)p (A)q (a)q² = 0.16f = ?

A recessive condition affects 16% of a population in Hardy–Weinberg equilibrium. What fraction f of the population are carriers (heterozygous)?

q² = 0.16
f =
3.Cell biologyMedium

Transcription produces:

  1. ADNA from DNA
  2. BmRNA from a DNA template
  3. CProtein from mRNA
  4. DDNA from RNA
4.Cell biologyHard

A double-stranded DNA sample contains 30% adenine. What percentage is guanine?

  1. A40%
  2. B20%
  3. C30%
  4. D70%

3Solutions

1.Genetics

Answer: P = 0.375

Mendelian genetics: each parent passes on one allele of each gene, chosen at random. A Punnett square lists every combination of gametes, each equally likely. A dominant allele (capital letter) shows whenever it is present; a recessive one only in the homozygous form. Genes on different chromosomes are inherited independently, so their probabilities multiply.

Each gene on its own

P(tall) = 0.75
P(wrinkled seeds) = 0.5

Multiply

P = 0.75·0.5 = 0.375

Answer

P = 0.375
2.Genetics

Answer: f = 0.48

Hardy–Weinberg: in a large, randomly mating population with no selection, the allele frequencies p (dominant) and q (recessive), p + q = 1, give genotype frequencies p², 2pq and q².

Allele frequencies

q = √0.16 = 0.4
p = 1 − 0.4 = 0.6

Carriers

2pq = 2·0.6·0.4 = 0.48

Answer

f = 0.48
3.Cell biology

Answer: B · mRNA from a DNA template

Why this is the answer

RNA polymerase transcribes a DNA template strand into RNA; translation then makes protein at ribosomes.

Answer

B · mRNA from a DNA template
4.Cell biology

Answer: B · 20%

Why this is the answer

A = T = 30%, so A + T = 60%. The remaining 40% is split equally between G and C, so G = 20%.

Answer

B · 20%

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