1.IntegralsMedium
Evaluate I = ∫01 2x·(x² + 1)3 dx.
f(x) = 2x·(x² + 1)3[0, 1]
I =
2.IntegralsHard
Evaluate I = ∫₀1.5 x²·eˣ dx.
∫₀1.5 x²eˣ dx
I =
3.Sequences & seriesMedium
Apply the root test to Σk=1∞ ((4k + 1)/(3k + 4))ᵏ. Find L = lim |ak|1/k.
ak = ((4k + 1)/(3k + 4))ᵏ
L =
4.Sequences & seriesHard
f(x) = cos x is approximated by its Maclaurin polynomial of degree 2 at x = −0.5. Use the Lagrange error bound M·|x|ⁿ⁺¹/(n + 1)! with M = 1 to find the largest possible error |R₂|.
f(x) = cos xn = 2x = −0.5M = 1
|R₂| =
5.Multivariable calculusMedium
For f(x, y) = −2x³y − 5x³ + 5y² − 4xy, find the maximum rate of change of f at the point (2, 2), that is |∇f|.
f(x, y) = −2x³y − 5x³ + 5y² − 4xyP = (2, 2)
|∇f| =
6.Multivariable calculusHard
Use polar coordinates to evaluate I = ∬R (x² + y²) dA, where R is the ring 0.25 ≤ x² + y² ≤ 2.25.
f = x² + y²0.5 ≤ r ≤ 1.50 ≤ θ ≤ 2π
I =
7.Differential equationsMedium
Solve y″ + 8y′ + 16y = 0 with y(0) = 2 and y′(0) = 2. Find y(1.5).
y″ + 8y′ + 16y = 0y(0) = 2y′(0) = 2
y(1.5) =
8.Differential equationsHard
A tank holds 400 L of pure water. Brine with 0.2 kg of salt per litre flows in at 5 L/min, and the well-mixed solution flows out at the same rate. After how many minutes t does the tank contain 48 kg of salt?
V = 400 Lm0 = 0 kgc = 0.2 kg/Lr = 5 L/min
t = min