1.IntegralsMedium
Evaluate I = ∫₁2.5 x·ln x dx.
∫₁2.5 x ln x dx
I =
2.IntegralsHard
Find the area A of the region between the parabola y = 9 − x² and the x-axis.
y = 9 − x²
A =
3.Sequences & seriesMedium
Find the sum S = Σk=1∞ 4/(k(k + 4)).
ak = 4/(k(k + 4))
S =
4.Sequences & seriesHard
f(x) = sin x is approximated at x = 1 by its Maclaurin polynomial of degree n. With the Lagrange bound M·|x|ⁿ⁺¹/(n + 1)! and M = 1, find the smallest degree n that guarantees an error below 1 × 10⁻⁵.
f(x) = sin xx = 1M = 1ε = 1 × 10⁻⁵
n =
5.Multivariable calculusMedium
The tangent plane to z = ln(x² + 3y²) at the point where (x, y) = (0.5, 2) can be written as z = px + qy + c. Find c.
f(x, y) = ln(x² + 3y²)(a, b) = (0.5, 2)
c =
6.Multivariable calculusHard
The marked points are the critical points of f(x, y) = x³ − 3x + y² − 6y. Click the local minimum.
f(x, y) = x³ − 3x + y² − 6y
- 1A (1, 3)
- 2B (−1, 3)
7.Differential equationsMedium
A cup of coffee at 83 °C is left in a room at 21 °C. It follows Newton's law of cooling, dT/dt = −k·(T − Tₐ). With k = 0.04 min⁻¹, find its temperature T after 7 min.
T0 = 83 °CTa = 21 °Ck = 0.04 min⁻¹t = 7 min
T = °C
8.Differential equationsHard
Solve y″ + y′ + 25.25y = 0 with y(0) = 1 and y′(0) = 0 (released from rest). Find y(0.25); angles in radians.
y″ + y′ + 25.25y = 0y(0) = 1y′(0) = 0
y(0.25) =