1.IntegralsMedium
Evaluate I = ∫₀π/2 x·sin x dx (x in radians).
∫₀π/2 x·sin x dx
I =
2.IntegralsHard
Find the area A of the region enclosed by y = 2x2 and y = 4x.
y = 2x2y = 4x
A =
3.Sequences & seriesMedium
Find the radius of convergence R of the power series Σk=1∞ k!·xᵏ/kᵏ.
Σ k!·xᵏ/kᵏx₀ = 0
R =
4.Sequences & seriesHard
f(x) = cos x is approximated at x = 1.5 by its Maclaurin polynomial of degree n. With the Lagrange bound M·|x|ⁿ⁺¹/(n + 1)! and M = 1, find the smallest degree n that guarantees an error below 1 × 10⁻⁶.
f(x) = cos xx = 1.5M = 1ε = 1 × 10⁻⁶
n =
5.Multivariable calculusMedium
z = −2xy + 5x² with x = −2t − 1 and y = t² + 1. Use the chain rule to find dz/dt at t = 0.
z = −2xy + 5x²x = −2t − 1y = t² + 1t = 0
dz/dt =
6.Multivariable calculusHard
Find the critical points of f(x, y) = 3x² + xy + 2y² + 13x + 6y − 5, classify them, and give the value fmin of f at its local minimum.
f(x, y) = 3x² + xy + 2y² + 13x + 6y − 5
fmin =
7.Differential equationsMedium
A forged steel part at 340 °C is left to cool in a workshop at 22 °C. After 32 min its temperature is 86 °C. It follows Newton's law of cooling, dT/dt = −k·(T − Tₐ). Find the constant k in min⁻¹.
T0 = 340 °CTa = 22 °CT(32) = 86 °C
k = min⁻¹
8.Differential equationsHard
Solve y″ + y′ + 9.25y = 0 with y(0) = 10 and y′(0) = 0 (released from rest). Find y(0.5); angles in radians.
y″ + y′ + 9.25y = 0y(0) = 10y′(0) = 0
y(0.5) =