You invest €1 000 at a nominal rate of 4% per year, compounded quarterly. Find the value FV of the investment after 9 years.
PV = €1 0004% / 4n = 9
FV = €
2.Time value of moneyHard
You deposit €6 000 at the start of every year for 18 years, the first deposit today. The account pays 7% per year. How much is in the account at the end of year 18? Find FV.
A = €6 000i = 7%n = 18
FV = €
3.NPV & IRRMedium
An investment of €75 000 gives these cash flows at the end of years 1 to 3: €23 000, €37 000, €33 000. The cost of capital is 10%. Find the net present value NPV.
A project costs €50 000 today. Its cash flow is €5 500 at the end of year 1 and grows by 2% per year until the last cash flow at the end of year 10. The cost of capital is 12%. Find the net present value NPV.
C0 = €50 000CF1 = €5 500g = 2%n = 10r = 12%
NPV = €
5.Bond pricing & yieldMedium
A bond with a face value of €1 000 pays a 3% annual coupon in two half-yearly payments and matures in 8 years. The yield to maturity is 6% per year. Find the price P of the bond.
F = €1 000coupon = 3%YTM = 6%n = 8
P = €
6.Bond pricing & yieldHard
A bond with a face value of €1 000 pays an annual coupon of 5% and matures in 5 years. The yield to maturity is 7%. Find the Macaulay duration D in years.
F = €1 000coupon = 5%n = 5YTM = 7%
D = years
7.CAPM & WACCMedium
A company has equity worth €4 000 000 and debt worth €1 000 000. Its cost of equity is 10%, its pre-tax cost of debt is 3% and the tax rate is 25.8%. Find the WACC.
A company has 1 000 000 shares at €53.50 each and 40 000 bonds trading at €960 each. The pre-tax cost of debt is 3% and the tax rate is 25%. The share’s beta is 1.3, the risk-free rate 4% and the market return 9.5%. Find the WACC.
β = 1.3rf = 4%rm = 9.5%rd = 3%T = 25%
WACC = %
9.Descriptive statisticsMedium
Find the sample standard deviation s of the data: 50, 17, 58, 18, 12, 26.
n = 6
s =
10.Descriptive statisticsHard
A quantity is normally distributed with mean 170 and standard deviation 10. What proportion P of values is above 190?
μ = 170σ = 10x = 190
P =
11.ProbabilityMedium
For the distribution shown, find the standard deviation σ of X.
x: 0, 1, 2p(x): 0.3, 0.35, 0.35
σ =
12.ProbabilityHard
A test has 5 multiple-choice questions. A student who guesses gets each one right with probability 0.1, independently. What is the probability P of exactly 1 correct answers?
n = 5p = 0.1k = 1
P =
13.Normal distributionMedium
Drag z so that the shaded area between −z and z under the standard normal curve is 0.9127. Find z to two decimals.
A = 0.9127
z =
14.Normal distributionHard
The IQ scores are normally distributed with mean 100 points and standard deviation 15 points. Drag the cut-off so the shaded top 10% is to the right of it. Find the cut-off x.
μ = 100 pointsσ = 15 points10%
x = points
15.Confidence intervalsMedium
A sample of 10 items has mean 107.5 and standard deviation s = 17. The population is roughly normal. Find the margin of error E of a 90% confidence interval for the mean.
n = 10x̄ = 107.5s = 1790%t(9) = 1.833
E =
16.Confidence intervalsHard
Nothing is known in advance about the proportion of defective products. How many products n must be inspected so that a 95% confidence interval for the proportion has a margin of error of at most 0.01?
p = 0.5E = 0.0195%
n =
17.Hypothesis tests & confidence intervalsMedium
11 employees take a typing test before and after a training course. For each person the difference d = after − before (words per minute) is recorded. The mean difference is 1.77 and the standard deviation of the differences is 4.2. Find the paired test statistic t for H₀: μd = 0.
n = 11d̄ = 1.77sd = 4.2
t =
18.Hypothesis tests & confidence intervalsHard
In a trial, 75 of 150 patients on treatment A recover, and 50 of 80 patients on treatment B. Using the pooled proportion, find the test statistic z for H₀: p₁ = p₂.
x₁ = 75n₁ = 150x₂ = 50n₂ = 80
z =
19.Linear regression & correlationMedium
The table gives 5 paired observations of x = load in kN and y = extension in mm. Their sums are given. Find Pearson's correlation coefficient r from these sums.
n = 5Σx = 30Σy = 107Σx² = 220Σy² = 2819Σxy = 786
r =
20.Linear regression & correlationHard
The table gives 6 paired observations of x = temperature in °C and y = ice creams sold. Use the least-squares line ŷ = a + b·x. Predict ŷ for x = 25.
n = 6x = 25
ŷ =
3Solutions
1.Time value of money
Answer: FV = 1431 €
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
Rate and number of periods
i = r/m = 0.04/4 = 0.01
N = m·n = 4·9 = 36
Future value
FV = 1 000·(1 + 0.01)36 = 1 000·1.431 = €1 430.77
Answer
FV = €1 430.77
2.Time value of money
Answer: FV = 218274 €
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
Ordinary annuity factor
((1 + 0.07)18 − 1)/0.07 = 34
Annuity due
Each deposit is invested one year longer.
FV = 6 000·34·1.07 = €218 273.79
Answer
FV = €218 273.79
3.NPV & IRR
Answer: NPV = 1281 €
Net present value: discount every cash flow back to today with the required rate of return r, then add them up: NPV = Σ CFₜ/(1 + r)ᵗ. A project with NPV > 0 earns more than r and adds value. The internal rate of return (IRR) is the rate at which NPV = 0.
Present value of each cash flow
CF0 = −75 000
CF1/(1 + 0.1)1 = 23 000/1.1 = 20 909.09
CF2/(1 + 0.1)2 = 37 000/1.21 = 30 578.51
CF3/(1 + 0.1)3 = 33 000/1.331 = 24 793.39
Add them up
NPV = €1 280.99
Answer
NPV = €1 280.99
NPV is positive, so the project earns more than the required return.
4.NPV & IRR
Answer: NPV = −16587 €
Net present value: discount every cash flow back to today with the required rate of return r, then add them up: NPV = Σ CFₜ/(1 + r)ᵗ. A project with NPV > 0 earns more than r and adds value. The internal rate of return (IRR) is the rate at which NPV = 0.
Present value of the growing annuity
((1.02)/(1.12))10 = 0.3925
PV = 5 500/(0.12 − 0.02)·(1 − 0.3925) = 33 413.40
NPV
NPV = 33 413.40 − 50 000 = −€16 586.60
Answer
NPV = −€16 586.60
NPV is negative, so the project earns less than the required return.
5.Bond pricing & yield
Answer: P = 811.6 €
Bond pricing: a bond’s price is the present value of its cash flows, discounted at the yield to maturity (YTM): the coupons form an annuity and the face value is paid back at maturity. P = C·(1 − (1 + y)⁻ⁿ)/y + F/(1 + y)ⁿ. When the yield is above the coupon rate the bond trades below face value, and the other way round.
Per period
C = €15.00, i = 0.03, N = 16
Present value of the coupons
€15.00·(1 − 0.6232)/0.03 = €188.42
Present value of the face value
€1 000·0.6232 = €623.17
Price
P = €811.58
Answer
P = €811.58
The yield is above the coupon rate, so the bond sells at a discount.
6.Bond pricing & yield
Answer: D = 4.523 years
Duration: the Macaulay duration is the weighted average time at which a bond pays its cash flows, with the present values of the cash flows as weights: D = Σ t·PVₜ/P. The modified duration D/(1 + y) estimates the percentage price change for a small change in yield: %ΔP ≈ −Dmod·Δy.
Present value of each cash flow
t = 1: 50/1.07 = 46.73, t·PV = 46.73
t = 2: 50/1.145 = 43.67, t·PV = 87.34
t = 3: 50/1.225 = 40.81, t·PV = 122.44
t = 4: 50/1.311 = 38.14, t·PV = 152.58
t = 5: 1050/1.403 = 748.64, t·PV = 3 743.18
Duration
P = 918.00
D = 4 152.27/918.00 = 4.523
Answer
D = 4.523 years
7.CAPM & WACC
Answer: WACC = 8.445 %
Cost of capital: CAPM gives the return shareholders require: re = rf + β·(rm − rf). The weighted average cost of capital mixes equity and debt by their market values: WACC = E/V·re + D/V·rd·(1 − T), with V = E + D. Interest is tax-deductible, hence the (1 − T).
Weights
V = €5 000 000, E/V = 0.8, D/V = 0.2
WACC
WACC = 0.8·10% + 0.2·3%·(1 − 0.258) = 8.445%
Answer
WACC = 8.445%
8.CAPM & WACC
Answer: WACC = 7.431 %
Cost of capital: CAPM gives the return shareholders require: re = rf + β·(rm − rf). The weighted average cost of capital mixes equity and debt by their market values: WACC = E/V·re + D/V·rd·(1 − T), with V = E + D. Interest is tax-deductible, hence the (1 − T).
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Standardise
z = 2
Standard normal table
Φ(2) = 0.9772
P = 1 − 0.9772 = 0.02275
Answer
P = 0.02275
11.Probability
Answer: σ = 0.8047
Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.
Mean
μ = 0·0.3 + 1·0.35 + 2·0.35 = 1.05
Mean of the squares
E(X²) = 0·0.3 + 1·0.35 + 4·0.35 = 1.75
Variance
Var(X) = 1.75 − 1.05² = 0.6475
σ = √0.6475 = 0.8047
Answer
σ = 0.8047
12.Probability
Answer: P = 0.3281
Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.
Binomial formula
P(X = 1) = 5·0.11·0.94 = 5·0.1·0.6561 = 0.3281
Answer
P = 0.3281
13.Normal distribution
Answer: z = 1.71
From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.
Area to the left of z
Φ(z) = (1 + 0.9127)/2 = 0.9564
Read the z-table backwards
Find 0.9564 inside the table and read off z.
z = 1.71
Answer
z = 1.71
14.Normal distribution
Answer: x = 119.2 points
From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.
Area to the left
Φ(z) = 0.9
z from the table
z ≈ 1.28
Back to the original units
x = 100 + 1.28·15 = 119.2 points
Answer
x = 119.2 points
15.Confidence intervals
Answer: E = 9.854
Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.
Critical value
df = n − 1 = 9, t = 1.833
Margin of error
E = 1.833·17/√10 = 9.854
Answer
E = 9.854
16.Confidence intervals
Answer: n = 9604
Confidence interval for a proportion: p̂ ± z·√(p̂(1 − p̂)/n), where p̂ = x/n. To reach a margin E you need n ≥ z²·p(1 − p)/E², rounded up; without a prior estimate use p = 0.5, which gives the largest n.
Solve for n
n = 1.96²·0.5·0.5/0.01² = 9604
Round up
n = 9604
Answer
n = 9604
17.Hypothesis tests & confidence intervals
Answer: t = 1.398
Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).
Standard error of the mean difference
SE = 4.2/√11 = 1.266
Test statistic
t = 1.77/1.266 = 1.398
Answer
t = 1.398
With df = 10, the two-sided 5% critical value is 2.228; |t| is smaller, so H₀ is not rejected.
18.Hypothesis tests & confidence intervals
Answer: z = −1.813
Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.
Sample proportions
p̂₁ = 75/150 = 0.5
p̂₂ = 50/80 = 0.625
p̂ = 125/230 = 0.5435
Standard error under H₀
SE = √(0.5435·0.4565·(1/150 + 1/80)) = 0.06896
Test statistic
z = (0.5 − 0.625)/0.06896 = −1.813
Answer
z = −1.813
|z| < 1.96, so H₀ is not rejected at the 5% level (two-sided).
19.Linear regression & correlation
Answer: r = 0.9897
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.
Centred sums
Sxy = 786 − 30·107/5 = 144
Sxx = 220 − 30²/5 = 40
Syy = 2819 − 107²/5 = 529.2
Correlation coefficient
r = 144/√(40·529.2) = 0.9897
Answer
r = 0.9897
20.Linear regression & correlation
Answer: ŷ = 97.72
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.
Means
x̄ = 126/6 = 21
ȳ = 479/6 = 79.83
Sums of squares and products
Sxx = Σ(x − x̄)² = 70
Sxy = Σ(x − x̄)(y − ȳ) = 313
Regression line
b = 313/70 = 4.471
a = 79.83 − 4.471·21 = −14.07
ŷ = −14.07 + 4.471·x
Prediction
ŷ = −14.07 + 4.471·25 = 97.72
Answer
ŷ = 97.72
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