You need €20 000 in 10 years. An account pays 3.6% per year, compounded quarterly. How much must you deposit today? Find the present value PV.
FV = €20 0003.6% / 4n = 10
PV = €
2.Time value of moneyHard
A loan of €150 000 is repaid with equal monthly payments over 25 years. The interest rate is 3% per year, compounded monthly. Find the monthly payment A.
P = €150 0003% / 12N = 300
A = €
3.NPV & IRRMedium
A project costs €30 000 today and returns €11 000 at the end of each year for 4 years. The cost of capital is 12%. Assume cash flows arrive evenly through each year. Find the discounted payback period DPB in years.
A project costs €40 000 and returns €16 000, €21 000, €17 500 at the end of years 1 to 3. Find its internal rate of return IRR in percent.
CF0 = −40 000CF1 = 16 000CF2 = 21 000CF3 = 17 500
IRR = %
5.Bond pricing & yieldMedium
A bond with a face value of €1 000 pays an annual coupon of 2% and matures in 11 years. Its yield to maturity changes from 5.5% to 6.5%. By how much ΔP does the bond price change?
F = €1 000coupon = 2%n = 11y1 = 5.5%y2 = 6.5%
ΔP = €
6.Bond pricing & yieldHard
A bond with a face value of €1 000 pays an annual coupon of 5% and matures in 6 years. The yield to maturity is 7%. Find the Macaulay duration D in years.
F = €1 000coupon = 5%n = 6YTM = 7%
D = years
7.CAPM & WACCMedium
A share with a beta of 1.6 has a required return of 13.1%. The risk-free rate is 3.5%. What expected market return rm does CAPM imply?
β = 1.6re = 13.1%rf = 3.5%
rm = %
8.CAPM & WACCHard
A company has 2 500 000 shares at €10.50 each and 10 000 bonds trading at €1 000 each. The pre-tax cost of debt is 5% and the tax rate is 20%. The share’s beta is 0.9, the risk-free rate 2.5% and the market return 7.5%. Find the WACC.
β = 0.9rf = 2.5%rm = 7.5%rd = 5%T = 20%
WACC = %
9.Descriptive statisticsMedium
Find the sample standard deviation s of the data: 43, 33, 57, 26, 37, 21, 52.
n = 7
s =
10.Descriptive statisticsHard
A quantity is normally distributed with mean 100 and standard deviation 8. What proportion P of values is below 84?
μ = 100σ = 8x = 84
P =
11.ProbabilityMedium
For the distribution shown, find the variance Var(X) of X.
x: 0, 1, 2, 3p(x): 0.15, 0.35, 0.2, 0.3
Var(X) =
12.ProbabilityHard
A game costs €2 to play. You win €6 with probability 0.1 and €20 with probability 0.05; otherwise you win nothing. The stake is not returned. Find the expected net gain E(G) per game.
stake = €2€6: p = 0.1€20: p = 0.05
E(G) = €
13.Normal distributionMedium
The exam scores are normally distributed with mean 65 points and standard deviation 10 points. What fraction lies between 57 and 80 points? Give P as a decimal.
μ = 65σ = 10x1 = 57x2 = 80
P =
14.Normal distributionHard
The IQ scores are normally distributed with mean 100 points and standard deviation 15 points. Find the value x below which 80% of them lie (the 80th percentile).
μ = 100σ = 15P = 80%
x = points
15.Confidence intervalsMedium
A sample of 10 items has mean 106 and standard deviation s = 1.5. The population is roughly normal. Find the margin of error E of a 99% confidence interval for the mean.
n = 10x̄ = 106s = 1.599%t(9) = 3.25
E =
16.Confidence intervalsHard
The population standard deviation is 5. How large a sample n do you need so that a 90% confidence interval for the mean has a margin of error of at most 1.5?
σ = 5E = 1.590%
n =
17.Hypothesis tests & confidence intervalsMedium
A sample of 81 students has a mean score of 117.1 and a sample standard deviation of 12. Find the test statistic t for H₀: μ = 120.
μ₀ = 120x̄ = 117.1s = 12n = 81
t =
18.Hypothesis tests & confidence intervalsHard
A one-sided z test of H₀: μ = 80 against H₁: μ > 80 is done at α = 0.05 with a sample of 25; the standard deviation is known to be 15. In reality the mean is 86.6. Find the power 1 − β of the test in percent.
μ₀ = 80μ = 86.6σ = 15n = 25α = 0.05
1 − β = %
19.Linear regression & correlationMedium
The table gives 5 paired observations of x = temperature in °C and y = ice creams sold. Their sums are given. Find Pearson's correlation coefficient r from these sums.
The table gives 6 paired observations of x = hours studied and y = exam score. Use the least-squares line ŷ = a + b·x. For which value x does the line predict ŷ = 75?
n = 6ŷ = 75
x =
3Solutions
1.Time value of money
Answer: PV = 13976 €
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
Rate and number of periods
i = 0.036000000000000004/4 = 0.009
N = 4·10 = 40
Present value
PV = FV/(1 + i)N = 20 000/1.431 = €13 976.01
Answer
PV = €13 976.01
2.Time value of money
Answer: A = 711.3 €
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
Monthly rate and number of payments
i = 0.03/12 = 0.0025
N = 12·25 = 300
Payment
The present value of N equal payments A is A·(1 − (1 + i)⁻ᴺ)/i. Set it equal to the loan and solve for A.
(1 + i)−N = 0.4728
A = 150 000·0.0025/(1 − 0.4728) = €711.32
Answer
A = €711.32
3.NPV & IRR
Answer: DPB = 3.512 years
Payback period: the time until the cumulative cash flows repay the initial investment. Cash is assumed to come in evenly during each year, so the last part is a fraction of a year. The simple payback ignores the time value of money; the discounted payback period uses the discounted cash flows instead.
Discounted and cumulative cash flows
year 1: 11 000/1.12 = 9 821.43 → Σ = 9 821.43
year 2: 11 000/1.254 = 8 769.13 → Σ = 18 590.56
year 3: 11 000/1.405 = 7 829.58 → Σ = 26 420.14
year 4: 11 000/1.574 = 6 990.70 → Σ = 33 410.84
Fraction of the last year
DPB = 3 + 3 579.86/6 990.70 = 3.512
Answer
DPB = 3.512 years
The discounted payback is always longer than the simple payback (2.727 years).
4.NPV & IRR
Answer: IRR = 16.91 %
Net present value: discount every cash flow back to today with the required rate of return r, then add them up: NPV = Σ CFₜ/(1 + r)ᵗ. A project with NPV > 0 earns more than r and adds value. The internal rate of return (IRR) is the rate at which NPV = 0.
Bracket the IRR
NPV falls as the rate rises, so the IRR lies between a rate with positive NPV and one with negative NPV.
NPV(15%) = 1 298.59
NPV(20%) = −1 956.02
Narrow down
Linear interpolation gives a first estimate; repeating it (or a calculator's IRR function) gives the exact rate.
Bond pricing: a bond’s price is the present value of its cash flows, discounted at the yield to maturity (YTM): the coupons form an annuity and the face value is paid back at maturity. P = C·(1 − (1 + y)⁻ⁿ)/y + F/(1 + y)ⁿ. When the yield is above the coupon rate the bond trades below face value, and the other way round.
Duration: the Macaulay duration is the weighted average time at which a bond pays its cash flows, with the present values of the cash flows as weights: D = Σ t·PVₜ/P. The modified duration D/(1 + y) estimates the percentage price change for a small change in yield: %ΔP ≈ −Dmod·Δy.
Present value of each cash flow
t = 1: 50/1.07 = 46.73, t·PV = 46.73
t = 2: 50/1.145 = 43.67, t·PV = 87.34
t = 3: 50/1.225 = 40.81, t·PV = 122.44
t = 4: 50/1.311 = 38.14, t·PV = 152.58
t = 5: 50/1.403 = 35.65, t·PV = 178.25
t = 6: 1050/1.501 = 699.66, t·PV = 4 197.96
Duration
P = 904.67
D = 4 785.30/904.67 = 5.29
Answer
D = 5.29 years
7.CAPM & WACC
Answer: rm = 9.5 %
Cost of capital: CAPM gives the return shareholders require: re = rf + β·(rm − rf). The weighted average cost of capital mixes equity and debt by their market values: WACC = E/V·re + D/V·rd·(1 − T), with V = E + D. Interest is tax-deductible, hence the (1 − T).
Market risk premium
rm − rf = (13.1% − 3.5%)/1.6 = 6%
Market return
rm = 3.5% + 6% = 9.5%
Answer
rm = 9.5%
8.CAPM & WACC
Answer: WACC = 6.172 %
Cost of capital: CAPM gives the return shareholders require: re = rf + β·(rm − rf). The weighted average cost of capital mixes equity and debt by their market values: WACC = E/V·re + D/V·rd·(1 − T), with V = E + D. Interest is tax-deductible, hence the (1 − T).
Market values
E = 2 500 000·€10.50 = €26 250 000
D = 10 000·€1 000 = €10 000 000
Cost of equity (CAPM)
re = 2.5% + 0.9·5% = 7%
Weights
V = €36 250 000, E/V = 0.7241, D/V = 0.2759
WACC
WACC = 0.7241·7% + 0.2759·5%·(1 − 0.2) = 6.172%
Answer
WACC = 6.172%
9.Descriptive statistics
Answer: s = 13.16
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Standardise
z = −2
Standard normal table
Φ(−2) = 0.02275
P = 0.02275
Answer
P = 0.02275
11.Probability
Answer: Var(X) = 1.127
Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.
Mean
μ = 0·0.15 + 1·0.35 + 2·0.2 + 3·0.3 = 1.65
Mean of the squares
E(X²) = 0·0.15 + 1·0.35 + 4·0.2 + 9·0.3 = 3.85
Variance
Var(X) = 3.85 − 1.65² = 1.127
Answer
Var(X) = 1.127
12.Probability
Answer: E(G) = −0.4 €
Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.
Net outcomes
G: 4 (p = 0.1), 18 (p = 0.05), −2 (p = 0.85)
Expected value
E(G) = 4·0.1 + 18·0.05 − 2·0.85 = −0.4 €
Answer
E(G) = −0.4 €
A negative value means you lose money on average.
13.Normal distribution
Answer: P = 0.7213
Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.
z-scores
z₁ = (57 − 65)/10 = −0.8
z₂ = (80 − 65)/10 = 1.5
Area between
P = Φ(1.5) − Φ(−0.8) = 0.9332 − 0.2119 = 0.7213
Answer
P = 0.7213
14.Normal distribution
Answer: x = 112.6 points
Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.
z for the percentile
Φ(z) = 0.8 → z = 0.8416
Back to x
x = 100 + 0.8416·15 = 112.62 points
Answer
x = 112.62 points
15.Confidence intervals
Answer: E = 1.542
Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.
Critical value
df = n − 1 = 9, t = 3.25
Margin of error
E = 3.25·1.5/√10 = 1.542
Answer
E = 1.542
16.Confidence intervals
Answer: n = 31
Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.
Solve for n
n = (1.645·5/1.5)² = 30.07
Round up
A sample size is a whole number, and rounding down would make the margin too large.
n = 31
Answer
n = 31
17.Hypothesis tests & confidence intervals
Answer: t = −2.175
Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).
Standard error
SE = 12/√81 = 12/9 = 1.333
Test statistic
t = (117.1 − 120)/1.333 = −2.175
Answer
t = −2.175
t0.025; df = 80 = 1.99
|t| > 1.99, so H₀ is rejected at the 5% level (two-sided).
18.Hypothesis tests & confidence intervals
Answer: 1 − β = 71.06 %
Power of a test: power = 1 − β is the probability of rejecting H₀ when it is false. Find the cutoff x̄c from μ₀ and z_α, then compute the probability of landing beyond x̄c using the true mean: z = (x̄c − μ)/(σ/√n).
Critical sample mean
SE = 15/√25 = 3
x̄c = 80 + 1.645·3 = 84.94
z under the true mean
z = (84.94 − 86.6)/3 = −0.555
Power
power = P(Z > −0.555) = 71.06%
1 − β = 71.06%
Answer
1 − β = 71.06%
19.Linear regression & correlation
Answer: r = 0.9881
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.
Centred sums
Sxy = 12721 − 105·593/5 = 268
Sxx = 2245 − 105²/5 = 40
Syy = 72169 − 593²/5 = 1839
Correlation coefficient
r = 268/√(40·1839) = 0.9881
Answer
r = 0.9881
20.Linear regression & correlation
Answer: x = 3.974
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.
Means
x̄ = 36/6 = 6
ȳ = 537/6 = 89.5
Sums of squares and products
Sxx = Σ(x − x̄)² = 70
Sxy = Σ(x − x̄)(y − ȳ) = 501
Regression line
b = 501/70 = 7.157
a = 89.5 − 7.157·6 = 46.56
ŷ = 46.56 + 7.157·x
Solve for x
x = (75 − 46.56)/7.157 = 3.974
Answer
x = 3.974
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