You invest €5 000 at 3% per year with continuous compounding. Find the value FV after 19 years.
PV = €5 000r = 3%t = 19
FV = €
2.Time value of moneyHard
A loan of €250 000 is repaid with equal monthly payments over 25 years. The interest rate is 5.4% per year, compounded monthly. Find the monthly payment A.
P = €250 0005.4% / 12N = 300
A = €
3.NPV & IRRMedium
A project costs €500 000 today. It generates €36 000 at the end of the first year, and the cash flow then grows by 3% per year forever. The cost of capital is 9%. Find the net present value NPV.
C0 = €500 000CF1 = €36 000g = 3%r = 9%
NPV = €
4.NPV & IRRHard
An investment of €50 000 returns €15 500 at the end of each year for 4 years. Find its internal rate of return IRR in percent.
C0 = €50 000CF = €15 500n = 4
IRR = %
5.Bond pricing & yieldMedium
A bond with a face value of €1 000 pays a 5% annual coupon in two half-yearly payments and matures in 6 years. The yield to maturity is 5.5% per year. Find the price P of the bond.
F = €1 000coupon = 5%YTM = 5.5%n = 6
P = €
6.Bond pricing & yieldHard
A bond with a face value of €1 000 pays an annual coupon of 7% and matures in 4 years. The yield to maturity is 9%. Find the Macaulay duration D in years.
F = €1 000coupon = 7%n = 4YTM = 9%
D = years
7.CAPM & WACCMedium
A company has equity worth €5 000 000 and debt worth €3 000 000. Its cost of equity is 12%, its pre-tax cost of debt is 4.5% and the tax rate is 25%. Find the WACC.
A company has 5 000 000 shares at €28.00 each and 5 000 bonds trading at €980 each. The pre-tax cost of debt is 6% and the tax rate is 25.8%. The share’s beta is 0.9, the risk-free rate 1% and the market return 5.5%. Find the WACC.
β = 0.9rf = 1%rm = 5.5%rd = 6%T = 25.8%
WACC = %
9.Descriptive statisticsMedium
Find the sample standard deviation s of the data: 11, 43, 44, 19, 44, 51.
n = 6
s =
10.Descriptive statisticsHard
Exam scores are normally distributed with mean 170 and standard deviation 10. Find the z-score z of a score of 155.
μ = 170σ = 10x = 155
z =
11.ProbabilityMedium
In how many ways N can a committee of 4 people be chosen from a group of 14? The order does not matter.
n = 14k = 4
N =
12.ProbabilityHard
A test has 9 multiple-choice questions. A student who guesses gets each one right with probability 0.6, independently. What is the probability P of exactly 1 correct answers?
n = 9p = 0.6k = 1
P =
13.Normal distributionMedium
The bag weights are normally distributed with mean 250 g and standard deviation 5 g. What fraction lies between 246.25 and 252.75 g? Give P as a decimal.
μ = 250σ = 5x1 = 246.25x2 = 252.75
P =
14.Normal distributionHard
Runner A's lap time X and runner B's lap time Y are independent and normal: X has mean 52 s and standard deviation 4 s, Y has mean 48 s and standard deviation 3 s. Find the probability P that X is greater than Y. Round z to two decimals.
μX = 52 s, σX = 4 sμY = 48 s, σY = 3 s
P =
15.Confidence intervalsMedium
The battery life of two phone models is compared. Model 1: 30 phones, mean 72 h, known standard deviation 13 h. Model 2: 100 phones, mean 61.5 h, known standard deviation 9 h. Find the margin of error E of the 99% confidence interval for μ₁ − μ₂.
Two fertilisers are tested. Plot group 1: 10 plots, mean yield 41.5 kg, standard deviation 1.5 kg. Plot group 2: 12 plots, mean 29.5 kg, standard deviation 2.5 kg. Assume equal variances (pooled t, df = n₁ + n₂ − 2). Find the margin of error E of the 90% confidence interval for μ₁ − μ₂.
Two production lines make the same part. Line 1: a sample of 40 parts has mean length 80 mm, and the line's known standard deviation is 16 mm. Line 2: a sample of 100 parts has mean 73.3 mm, known standard deviation 17 mm. Find the test statistic z for H₀: μ₁ = μ₂, taking the difference as x̄₁ − x̄₂ (line 1 minus line 2).
How large must a sample be so that the 99% confidence interval for a mean has a margin of error of at most 3? The standard deviation is 5. Find the smallest sample size n.
σ = 5E = 399%
n =
19.Linear regression & correlationMedium
The table gives 5 paired observations of x = advertising spend in k€ and y = sales in k€. Find the coefficient of determination r² of the least-squares line.
n = 5
r² =
20.Linear regression & correlationHard
The table gives 5 paired observations of x = hours studied and y = exam score. Use the least-squares line ŷ = a + b·x. For which value x does the line predict ŷ = 59?
n = 5ŷ = 59
x =
3Solutions
1.Time value of money
Answer: FV = 8841 €
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
Exponent
r·t = 0.03·19 = 0.57
e0.57 = 1.768
Future value
FV = 5 000·1.768 = €8 841.34
Answer
FV = €8 841.34
2.Time value of money
Answer: A = 1520 €
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
Monthly rate and number of payments
i = 0.054000000000000006/12 = 0.0045
N = 12·25 = 300
Payment
The present value of N equal payments A is A·(1 − (1 + i)⁻ᴺ)/i. Set it equal to the loan and solve for A.
(1 + i)−N = 0.26
A = 250 000·0.0045/(1 − 0.26) = €1 520.32
Answer
A = €1 520.32
3.NPV & IRR
Answer: NPV = 100000 €
Net present value: discount every cash flow back to today with the required rate of return r, then add them up: NPV = Σ CFₜ/(1 + r)ᵗ. A project with NPV > 0 earns more than r and adds value. The internal rate of return (IRR) is the rate at which NPV = 0.
Value of the cash flows
PV = 36 000/(0.09 − 0.03) = 600 000.00
NPV
NPV = 600 000.00 − 500 000 = €100 000.00
Answer
NPV = €100 000.00
NPV is positive, so the project earns more than the required return.
4.NPV & IRR
Answer: IRR = 9.196 %
Net present value: discount every cash flow back to today with the required rate of return r, then add them up: NPV = Σ CFₜ/(1 + r)ᵗ. A project with NPV > 0 earns more than r and adds value. The internal rate of return (IRR) is the rate at which NPV = 0.
Required annuity factor
(1 − (1 + i)−4)/i = 50 000/15 500 = 3.226
Solve for the rate
The annuity factor falls as the rate rises; bracket the rate and narrow down.
i = 9%: 3.24
i = 10%: 3.17
IRR = 9.196%
Answer
IRR = 9.196%
5.Bond pricing & yield
Answer: P = 974.7 €
Bond pricing: a bond’s price is the present value of its cash flows, discounted at the yield to maturity (YTM): the coupons form an annuity and the face value is paid back at maturity. P = C·(1 − (1 + y)⁻ⁿ)/y + F/(1 + y)ⁿ. When the yield is above the coupon rate the bond trades below face value, and the other way round.
Per period
C = €25.00, i = 0.0275, N = 12
Present value of the coupons
€25.00·(1 − 0.7221)/0.0275 = €252.61
Present value of the face value
€1 000·0.7221 = €722.13
Price
P = €974.74
Answer
P = €974.74
The yield is above the coupon rate, so the bond sells at a discount.
6.Bond pricing & yield
Answer: D = 3.61 years
Duration: the Macaulay duration is the weighted average time at which a bond pays its cash flows, with the present values of the cash flows as weights: D = Σ t·PVₜ/P. The modified duration D/(1 + y) estimates the percentage price change for a small change in yield: %ΔP ≈ −Dmod·Δy.
Present value of each cash flow
t = 1: 70/1.09 = 64.22, t·PV = 64.22
t = 2: 70/1.188 = 58.92, t·PV = 117.84
t = 3: 70/1.295 = 54.05, t·PV = 162.16
t = 4: 1070/1.412 = 758.01, t·PV = 3 032.06
Duration
P = 935.21
D = 3 376.27/935.21 = 3.61
Answer
D = 3.61 years
7.CAPM & WACC
Answer: WACC = 8.766 %
Cost of capital: CAPM gives the return shareholders require: re = rf + β·(rm − rf). The weighted average cost of capital mixes equity and debt by their market values: WACC = E/V·re + D/V·rd·(1 − T), with V = E + D. Interest is tax-deductible, hence the (1 − T).
Weights
V = €8 000 000, E/V = 0.625, D/V = 0.375
WACC
WACC = 0.625·12% + 0.375·4.5%·(1 − 0.25) = 8.766%
Answer
WACC = 8.766%
8.CAPM & WACC
Answer: WACC = 5.03 %
Cost of capital: CAPM gives the return shareholders require: re = rf + β·(rm − rf). The weighted average cost of capital mixes equity and debt by their market values: WACC = E/V·re + D/V·rd·(1 − T), with V = E + D. Interest is tax-deductible, hence the (1 − T).
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Standardise
z = (155 − 170)/10 = −1.5
Answer
z = −1.5
11.Probability
Answer: N = 1001
Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.
Combinations
C(14, 4) = (14·13·12·11)/(4·3·2·1) = 1001
Answer
N = 1001
12.Probability
Answer: P = 0.003539
Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.
Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.
z-scores
z₁ = (246.25 − 250)/5 = −0.75
z₂ = (252.75 − 250)/5 = 0.55
Area between
P = Φ(0.55) − Φ(−0.75) = 0.7088 − 0.2266 = 0.4822
Answer
P = 0.4822
14.Normal distribution
Answer: P = 0.7881
Sums and differences of normal variables: if X and Y are independent and normal, X + Y and X − Y are normal too. Means add or subtract: E(X ± Y) = μX ± μY. Variances always add, also for a difference: Var(X ± Y) = σX² + σY², so σ = √(σX² + σY²). Standard deviations never add directly. The total of n independent items with the same distribution has mean n·μ and standard deviation σ·√n. Then standardise as usual: z = (x − mean)/σ and read Φ(z).
Distribution of the difference
μ = 52 − 48 = 4 s, σ = 5 s
Standardise
z = (0 − 4)/5 = −0.8
Probability
P = 1 − Φ(−0.8) = 0.7881
Answer
P = 0.7881
15.Confidence intervals
Answer: E = 6.539 h
Interval for a difference: estimate ± critical value × standard error. For two independent means with known σ: SE = √(σ₁²/n₁ + σ₂²/n₂) and z. With equal unknown variances: pooled s_p and t with n₁ + n₂ − 2 degrees of freedom. For paired data, work with the differences: d̄ ± t·s_d/√n.
Point estimate
x̄₁ − x̄₂ = 72 − 61.5 = 10.5
Standard error
SE = √(13²/30 + 9²/100) = 2.538
Margin of error
E = 2.576·2.538 = 6.539
Answer
E = 6.539 h
The interval does not contain 0, so the means differ significantly.
16.Confidence intervals
Answer: E = 1.558 kg
Interval for a difference: estimate ± critical value × standard error. For two independent means with known σ: SE = √(σ₁²/n₁ + σ₂²/n₂) and z. With equal unknown variances: pooled s_p and t with n₁ + n₂ − 2 degrees of freedom. For paired data, work with the differences: d̄ ± t·s_d/√n.
Pooled standard deviation
sp² = (9·1.5² + 11·2.5²)/20 = 4.45
sp = 2.11
Margin of error
E = 1.725·2.11·√(1/10 + 1/12) = 1.558
Answer
E = 1.558 kg
17.Hypothesis tests & confidence intervals
Answer: z = 2.198
Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.
Standard error of the difference
SE = √(16²/40 + 17²/100) = √9.29 = 3.048
Test statistic
z = (80 − 73.3)/3.048 = 2.198
Answer
z = 2.198
|z| > 1.96, so H₀ is rejected at the 5% level (two-sided).
18.Hypothesis tests & confidence intervals
Answer: n = 19
Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).
Solve for n
n = (2.576·5/3)² = 18.43
Round up
n = 19
Answer
n = 19
19.Linear regression & correlation
Answer: r² = 0.8848
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.
Means
x̄ = 35/5 = 7
ȳ = 231/5 = 46.2
Sums of squares and products
Sxx = Σ(x − x̄)² = 40
Sxy = Σ(x − x̄)(y − ȳ) = 88
Syy = Σ(y − ȳ)² = 218.8
Coefficient of determination
r² = 88²/(40·218.8) = 0.8848
Answer
r² = 0.8848
About 88.48% of the variation in y is explained by the line.
20.Linear regression & correlation
Answer: x = 8
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.
Means
x̄ = 25/5 = 5
ȳ = 268/5 = 53.6
Sums of squares and products
Sxx = Σ(x − x̄)² = 40
Sxy = Σ(x − x̄)(y − ȳ) = 72
Regression line
b = 72/40 = 1.8
a = 53.6 − 1.8·5 = 44.6
ŷ = 44.6 + 1.8·x
Solve for x
x = (59 − 44.6)/1.8 = 8
Answer
x = 8
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