You invest €5 000 at 3% per year with continuous compounding. Find the value FV after 3 years.
PV = €5 000r = 3%t = 3
FV = €
2.Time value of moneyHard
You borrow €25 000 at 3.6% per year, compounded monthly, and repay €475 at the end of every month. How many months does it take until the loan is repaid (the last payment may be smaller)? Give the number of payments N.
P = €25 000A = €4753.6% / 12
N = payments
3.NPV & IRRMedium
A machine costs €40 000 today, lasts 6 years and costs €2 000 per year to run (paid at the end of each year). The cost of capital is 10%. Find its equivalent annual cost EAC.
C0 = €40 000M = €2 000n = 6r = 10%
EAC = €
4.NPV & IRRHard
An investment of €80 000 returns €28 500 at the end of each year for 3 years. Find its internal rate of return IRR in percent.
C0 = €80 000CF = €28 500n = 3
IRR = %
5.Bond pricing & yieldMedium
A bond with a face value of €1 000 pays a 6% annual coupon in two half-yearly payments and matures in 7 years. The yield to maturity is 3.5% per year. Find the price P of the bond.
F = €1 000coupon = 6%YTM = 3.5%n = 7
P = €
6.Bond pricing & yieldHard
A bond with a face value of €1 000 and an annual coupon of 5% matures in 4 years and sells for €965. Find its yield to maturity YTM in percent.
F = €1 000coupon = 5%n = 4P = €965
YTM = %
7.CAPM & WACCMedium
A company has equity worth €3 000 000 and debt worth €1 000 000. Its cost of equity is 14%, its pre-tax cost of debt is 7% and the tax rate is 30%. Find the WACC.
A company has 1 000 000 shares at €58.50 each and 20 000 bonds trading at €960 each. The pre-tax cost of debt is 5% and the tax rate is 28%. The share’s beta is 1.2, the risk-free rate 4% and the market return 8.5%. Find the WACC.
β = 1.2rf = 4%rm = 8.5%rd = 5%T = 28%
WACC = %
9.Descriptive statisticsMedium
Find the sample standard deviation s of the data: 50, 14, 29, 58, 41, 15.
n = 6
s =
10.Descriptive statisticsHard
Exam scores are normally distributed with mean 70 and standard deviation 15. Find the z-score z of a score of 100.
μ = 70σ = 15x = 100
z =
11.ProbabilityMedium
A fair die is rolled 7 times. What is the probability P of getting at least one six?
n = 7
P =
12.ProbabilityHard
A test has 7 multiple-choice questions. A student who guesses gets each one right with probability 0.7, independently. What is the probability P of exactly 1 correct answers?
n = 7p = 0.7k = 1
P =
13.Normal distributionMedium
Drag z so that the shaded area under the standard normal curve, to the right of z, is 0.0143. Find z to two decimals.
A = 0.0143
z =
14.Normal distributionHard
The exam scores are normally distributed with mean 65 points and standard deviation 10 points. Find the value x below which 80% of them lie (the 80th percentile).
μ = 65σ = 10P = 80%
x = points
15.Confidence intervalsMedium
A sample of 16 items has mean 33 and standard deviation s = 10. The population is roughly normal. Find the upper limit of the 95% confidence interval for the mean.
n = 16x̄ = 33s = 1095%t(15) = 2.131
upper limit =
16.Confidence intervalsHard
A pilot study suggests that about 0.8 of products are defective. How many products n must be inspected so that a 95% confidence interval for the proportion has a margin of error of at most 0.03?
p ≈ 0.8E = 0.0395%
n =
17.Hypothesis tests & confidence intervalsMedium
A sample of 64 students has a mean score of 202.4 and a sample standard deviation of 8. Find the test statistic t for H₀: μ = 200.
μ₀ = 200x̄ = 202.4s = 8n = 64
t =
18.Hypothesis tests & confidence intervalsHard
A one-sided z test at α = 0.05 must detect a shift of the mean of 2.5 units with a power of 80%. The standard deviation is 7. Find the minimum sample size n.
The table gives 5 paired observations of x = car age in years and y = price in k€. Find the coefficient of determination r² of the least-squares line.
n = 5
r² =
20.Linear regression & correlationHard
The table gives 6 paired observations of x = temperature in °C and y = ice creams sold. Use the least-squares line ŷ = a + b·x. For which value x does the line predict ŷ = 50?
n = 6ŷ = 50
x =
3Solutions
1.Time value of money
Answer: FV = 5471 €
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
Exponent
r·t = 0.03·3 = 0.09
e0.09 = 1.094
Future value
FV = 5 000·1.094 = €5 470.87
Answer
FV = €5 470.87
2.Time value of money
Answer: N = 58 payments
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
Rearrange the annuity formula
i = 0.003
(1 + i)−N = 1 − 25 000·0.003/475 = 0.8421
Solve with logarithms
N = −ln(0.8421)/ln(1.003) = 57.37
Round up to whole payments
57 full payments leave a small balance, which the last, smaller payment clears.
N = 58
Answer
N = 58 payments
3.NPV & IRR
Answer: EAC = 11184 €
Equivalent annual cost: spread the present value of all costs over the life as an equal yearly amount (an annuity): EAC = PV·r/(1 − (1 + r)⁻ⁿ). It lets you compare machines with different lives.
Annuity factor
(1 − 1.1−6)/0.1 = 4.355
Annualised purchase price
40 000/4.355 = 9 184.30
EAC
EAC = 9 184.30 + 2 000 = €11 184.30
Answer
EAC = €11 184.30
4.NPV & IRR
Answer: IRR = 3.4 %
Net present value: discount every cash flow back to today with the required rate of return r, then add them up: NPV = Σ CFₜ/(1 + r)ᵗ. A project with NPV > 0 earns more than r and adds value. The internal rate of return (IRR) is the rate at which NPV = 0.
Required annuity factor
(1 − (1 + i)−3)/i = 80 000/28 500 = 2.807
Solve for the rate
The annuity factor falls as the rate rises; bracket the rate and narrow down.
i = 3%: 2.829
i = 4%: 2.775
IRR = 3.4%
Answer
IRR = 3.4%
5.Bond pricing & yield
Answer: P = 1154 €
Bond pricing: a bond’s price is the present value of its cash flows, discounted at the yield to maturity (YTM): the coupons form an annuity and the face value is paid back at maturity. P = C·(1 − (1 + y)⁻ⁿ)/y + F/(1 + y)ⁿ. When the yield is above the coupon rate the bond trades below face value, and the other way round.
Per period
C = €30.00, i = 0.0175, N = 14
Present value of the coupons
€30.00·(1 − 0.7844)/0.0175 = €369.66
Present value of the face value
€1 000·0.7844 = €784.36
Price
P = €1 154.03
Answer
P = €1 154.03
The yield is below the coupon rate, so the bond sells at a premium.
6.Bond pricing & yield
Answer: YTM = 6.01 %
Bond pricing: a bond’s price is the present value of its cash flows, discounted at the yield to maturity (YTM): the coupons form an annuity and the face value is paid back at maturity. P = C·(1 − (1 + y)⁻ⁿ)/y + F/(1 + y)ⁿ. When the yield is above the coupon rate the bond trades below face value, and the other way round.
Equation for the yield
€965 = €50·(1 − (1 + y)⁻⁴)/y + €1 000/(1 + y)⁴
Solve numerically
P(6%) = €965.35, P(7%) = €932.26
YTM = 6.01%
Answer
YTM = 6.01%
7.CAPM & WACC
Answer: WACC = 11.72 %
Cost of capital: CAPM gives the return shareholders require: re = rf + β·(rm − rf). The weighted average cost of capital mixes equity and debt by their market values: WACC = E/V·re + D/V·rd·(1 − T), with V = E + D. Interest is tax-deductible, hence the (1 − T).
Weights
V = €4 000 000, E/V = 0.75, D/V = 0.25
WACC
WACC = 0.75·14% + 0.25·7%·(1 − 0.3) = 11.72%
Answer
WACC = 11.72%
8.CAPM & WACC
Answer: WACC = 7.967 %
Cost of capital: CAPM gives the return shareholders require: re = rf + β·(rm − rf). The weighted average cost of capital mixes equity and debt by their market values: WACC = E/V·re + D/V·rd·(1 − T), with V = E + D. Interest is tax-deductible, hence the (1 − T).
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Standardise
z = (100 − 70)/15 = 2
Answer
z = 2
11.Probability
Answer: P = 0.7209
Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.
Complement
P(no six) = (5/6)7 = 0.2791
P = 1 − 0.2791 = 0.7209
Answer
P = 0.7209
12.Probability
Answer: P = 0.003572
Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.
From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.
Area to the left of z
Φ(z) = 1 − 0.0143 = 0.9857
Read the z-table backwards
Find 0.9857 inside the table and read off z.
z = 2.19
Answer
z = 2.19
14.Normal distribution
Answer: x = 73.42 points
Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.
z for the percentile
Φ(z) = 0.8 → z = 0.8416
Back to x
x = 65 + 0.8416·10 = 73.42 points
Answer
x = 73.42 points
15.Confidence intervals
Answer: upper limit = 38.33
Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.
Critical value
df = n − 1 = 15, t = 2.131
Margin of error
E = 2.131·10/√16 = 5.327
Interval
33 ± 5.327 → [27.67, 38.33]
Answer
upper limit = 38.33
16.Confidence intervals
Answer: n = 683
Confidence interval for a proportion: p̂ ± z·√(p̂(1 − p̂)/n), where p̂ = x/n. To reach a margin E you need n ≥ z²·p(1 − p)/E², rounded up; without a prior estimate use p = 0.5, which gives the largest n.
Solve for n
n = 1.96²·0.8·0.2/0.03² = 683
Round up
n = 683
Answer
n = 683
17.Hypothesis tests & confidence intervals
Answer: t = 2.4
Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).
Standard error
SE = 8/√64 = 8/8 = 1
Test statistic
t = (202.4 − 200)/1 = 2.4
Answer
t = 2.4
t0.025; df = 63 = 1.998
|t| > 1.998, so H₀ is rejected at the 5% level (two-sided).
18.Hypothesis tests & confidence intervals
Answer: n = 49
Sample size for a test: to detect a true shift δ with power 1 − β in a one-sided z test at level α, the standard error must satisfy δ = (z_α + z_β)·σ/√n, so n = ((z_α + z_β)·σ/δ)², rounded up.
Solve for n
n = ((1.645 + 0.842)·7/2.5)² = 48.49
Round up
n = 49
Answer
n = 49
19.Linear regression & correlation
Answer: r² = 0.8372
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.
Means
x̄ = 15/5 = 3
ȳ = 98/5 = 19.6
Sums of squares and products
Sxx = Σ(x − x̄)² = 10
Sxy = Σ(x − x̄)(y − ȳ) = −12
Syy = Σ(y − ȳ)² = 17.2
Coefficient of determination
r² = −12²/(10·17.2) = 0.8372
Answer
r² = 0.8372
About 83.72% of the variation in y is explained by the line.
20.Linear regression & correlation
Answer: x = 21.93
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.
Means
x̄ = 129/6 = 21.5
ȳ = 291/6 = 48.5
Sums of squares and products
Sxx = Σ(x − x̄)² = 157.5
Sxy = Σ(x − x̄)(y − ȳ) = 544.5
Regression line
b = 544.5/157.5 = 3.457
a = 48.5 − 3.457·21.5 = −25.83
ŷ = −25.83 + 3.457·x
Solve for x
x = (50 − (−25.83))/3.457 = 21.93
Answer
x = 21.93
This is independent practice material. ExamProblems is not affiliated with or endorsed by the organisation that runs this exam, and the exam name is used only to describe the content. CFA® and Chartered Financial Analyst® are trademarks of CFA Institute, which is not affiliated with ExamProblems and does not endorse it or vouch for its accuracy.