A property is expected to earn net rent of €20 000 next year. The rent is expected to grow by 3% per year forever. The required return is 6% per year. Find the value PV of the property today.
C1 = €20 000g = 3%r = 6%
PV = €
2.Time value of moneyHard
A mortgage of €300 000 is repaid with equal monthly payments over 25 years at 4.2% per year, compounded monthly. How much is still owed just after the payment at the end of year 9? Find the outstanding balance B.
P = €300 0004.2% / 12N = 300k = 108
B = €
3.NPV & IRRMedium
A machine costs €40 000 today. It generates €14 000 at the end of each year for 3 years and can then be sold for €8 000. The cost of capital is 12%. Find the net present value NPV.
C0 = €40 000CF = €14 000S = €8 000n = 3r = 12%
NPV = €
4.NPV & IRRHard
A project costs €50 000 and returns €34 000, €28 500, €29 000 at the end of years 1 to 3. Find its internal rate of return IRR in percent.
CF0 = −50 000CF1 = 34 000CF2 = 28 500CF3 = 29 000
IRR = %
5.Bond pricing & yieldMedium
A bond with a face value of €1 000 pays a 7% annual coupon in two half-yearly payments and matures in 12 years. The yield to maturity is 3.5% per year. Find the price P of the bond.
F = €1 000coupon = 7%YTM = 3.5%n = 12
P = €
6.Bond pricing & yieldHard
A bond with a face value of €1 000 and an annual coupon of 5% matures in 10 years and sells for €1 080. Find its yield to maturity YTM in percent.
F = €1 000coupon = 5%n = 10P = €1 080
YTM = %
7.CAPM & WACCMedium
A company has equity worth €2 000 000 and debt worth €6 000 000. Its cost of equity is 13%, its pre-tax cost of debt is 6% and the tax rate is 20%. Find the WACC.
A company's business has an unlevered (asset) beta of 0.7. It plans a debt-to-equity ratio of 1. The tax rate is 21%, the risk-free rate is 2% and the market risk premium is 5%. Find the cost of equity re at the new capital structure.
βU = 0.7D/E = 1T = 21%rf = 2%rm − rf = 5%
re = %
9.Descriptive statisticsMedium
Find the sample standard deviation s of the data: 39, 42, 23, 13, 16, 37, 40.
n = 7
s =
10.Descriptive statisticsHard
Exam scores are normally distributed with mean 60 and standard deviation 5. Find the z-score z of a score of 50.
μ = 60σ = 5x = 50
z =
11.ProbabilityMedium
A fair die is rolled 7 times. What is the probability P of getting at least one six?
n = 7
P =
12.ProbabilityHard
A test has 12 multiple-choice questions. A student who guesses gets each one right with probability 0.1, independently. What is the probability P of exactly 2 correct answers?
n = 12p = 0.1k = 2
P =
13.Normal distributionMedium
Drag z so that the shaded area between −z and z under the standard normal curve is 0.9051. Find z to two decimals.
A = 0.9051
z =
14.Normal distributionHard
The mass X of a product from line 1 and Y from line 2 are independent and normal: X has mean 500 g and standard deviation 8 g, Y has mean 490 g and standard deviation 6 g. Find the probability P that X is greater than Y. Round z to two decimals.
μX = 500 g, σX = 8 gμY = 490 g, σY = 6 g
P =
15.Confidence intervalsMedium
A sample of 7 items has mean 64.5 and standard deviation s = 2.5. The population is roughly normal. Find the upper limit of the 95% confidence interval for the mean.
n = 7x̄ = 64.5s = 2.595%t(6) = 2.447
upper limit =
16.Confidence intervalsHard
Nothing is known in advance about the proportion of defective products. How many products n must be inspected so that a 95% confidence interval for the proportion has a margin of error of at most 0.01?
p = 0.5E = 0.0195%
n =
17.Hypothesis tests & confidence intervalsMedium
A sample of 81 students has a mean score of 498.6 and a sample standard deviation of 5. Find the test statistic t for H₀: μ = 500.
μ₀ = 500x̄ = 498.6s = 5n = 81
t =
18.Hypothesis tests & confidence intervalsHard
How large must a sample be so that the 90% confidence interval for a mean has a margin of error of at most 0.5? The standard deviation is 12. Find the smallest sample size n.
σ = 12E = 0.590%
n =
19.Linear regression & correlationMedium
The table gives 6 paired observations of x = load in kN and y = extension in mm. Find the coefficient of determination r² of the least-squares line.
n = 6
r² =
20.Linear regression & correlationHard
The table gives 5 paired observations of x = load in kN and y = extension in mm. Use the least-squares line ŷ = a + b·x. For which value x does the line predict ŷ = 14?
n = 5ŷ = 14
x =
3Solutions
1.Time value of money
Answer: PV = 666667 €
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
Whatever is still owed must be exactly paid off by the remaining payments.
N − k = 300 − 108 = 192
B = 1617·(1 − (1 + 0.0035)−192)/0.0035 = €225 761.84
Answer
B = €225 761.84
3.NPV & IRR
Answer: NPV = −680.1 €
Net present value: discount every cash flow back to today with the required rate of return r, then add them up: NPV = Σ CFₜ/(1 + r)ᵗ. A project with NPV > 0 earns more than r and adds value. The internal rate of return (IRR) is the rate at which NPV = 0.
Present value of the yearly cash flows
14 000·2.402 = 33 625.64
Present value of the salvage value
8 000/1.405 = 5 694.24
NPV
NPV = −40 000 + 33 625.64 + 5 694.24 = −€680.12
Answer
NPV = −€680.12
4.NPV & IRR
Answer: IRR = 39.02 %
Net present value: discount every cash flow back to today with the required rate of return r, then add them up: NPV = Σ CFₜ/(1 + r)ᵗ. A project with NPV > 0 earns more than r and adds value. The internal rate of return (IRR) is the rate at which NPV = 0.
Bracket the IRR
NPV falls as the rate rises, so the IRR lies between a rate with positive NPV and one with negative NPV.
NPV(35%) = 2 609.87
NPV(40%) = −604.96
Narrow down
Linear interpolation gives a first estimate; repeating it (or a calculator's IRR function) gives the exact rate.
Bond pricing: a bond’s price is the present value of its cash flows, discounted at the yield to maturity (YTM): the coupons form an annuity and the face value is paid back at maturity. P = C·(1 − (1 + y)⁻ⁿ)/y + F/(1 + y)ⁿ. When the yield is above the coupon rate the bond trades below face value, and the other way round.
Per period
C = €35.00, i = 0.0175, N = 24
Present value of the coupons
€35.00·(1 − 0.6594)/0.0175 = €681.12
Present value of the face value
€1 000·0.6594 = €659.44
Price
P = €1 340.56
Answer
P = €1 340.56
The yield is below the coupon rate, so the bond sells at a premium.
6.Bond pricing & yield
Answer: YTM = 4.013 %
Bond pricing: a bond’s price is the present value of its cash flows, discounted at the yield to maturity (YTM): the coupons form an annuity and the face value is paid back at maturity. P = C·(1 − (1 + y)⁻ⁿ)/y + F/(1 + y)ⁿ. When the yield is above the coupon rate the bond trades below face value, and the other way round.
Cost of capital: CAPM gives the return shareholders require: re = rf + β·(rm − rf). The weighted average cost of capital mixes equity and debt by their market values: WACC = E/V·re + D/V·rd·(1 − T), with V = E + D. Interest is tax-deductible, hence the (1 − T).
Weights
V = €8 000 000, E/V = 0.25, D/V = 0.75
WACC
WACC = 0.25·13% + 0.75·6%·(1 − 0.2) = 6.85%
Answer
WACC = 6.85%
8.CAPM & WACC
Answer: re = 8.265 %
Levered beta (Hamada): debt makes equity riskier. βL = βU·(1 + (1 − T)·D/E), where βU is the beta of the business without debt. To move a beta to another capital structure, unlever it first and then relever it at the new D/E.
Levered beta
βL = 0.7·(1 + 0.79·1) = 1.253
Cost of equity (CAPM)
re = 2% + 1.253·5% = 8.265%
Answer
re = 8.265%
9.Descriptive statistics
Answer: s = 12.3
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Standardise
z = (50 − 60)/5 = −2
Answer
z = −2
11.Probability
Answer: P = 0.7209
Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.
Complement
P(no six) = (5/6)7 = 0.2791
P = 1 − 0.2791 = 0.7209
Answer
P = 0.7209
12.Probability
Answer: P = 0.2301
Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.
From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.
Area to the left of z
Φ(z) = (1 + 0.9051)/2 = 0.9525
Read the z-table backwards
Find 0.9525 inside the table and read off z.
z = 1.67
Answer
z = 1.67
14.Normal distribution
Answer: P = 0.8413
Sums and differences of normal variables: if X and Y are independent and normal, X + Y and X − Y are normal too. Means add or subtract: E(X ± Y) = μX ± μY. Variances always add, also for a difference: Var(X ± Y) = σX² + σY², so σ = √(σX² + σY²). Standard deviations never add directly. The total of n independent items with the same distribution has mean n·μ and standard deviation σ·√n. Then standardise as usual: z = (x − mean)/σ and read Φ(z).
Distribution of the difference
μ = 500 − 490 = 10 g, σ = 10 g
Standardise
z = (0 − 10)/10 = −1
Probability
P = 1 − Φ(−1) = 0.8413
Answer
P = 0.8413
15.Confidence intervals
Answer: upper limit = 66.81
Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.
Critical value
df = n − 1 = 6, t = 2.447
Margin of error
E = 2.447·2.5/√7 = 2.312
Interval
64.5 ± 2.312 → [62.19, 66.81]
Answer
upper limit = 66.81
16.Confidence intervals
Answer: n = 9604
Confidence interval for a proportion: p̂ ± z·√(p̂(1 − p̂)/n), where p̂ = x/n. To reach a margin E you need n ≥ z²·p(1 − p)/E², rounded up; without a prior estimate use p = 0.5, which gives the largest n.
Solve for n
n = 1.96²·0.5·0.5/0.01² = 9604
Round up
n = 9604
Answer
n = 9604
17.Hypothesis tests & confidence intervals
Answer: t = −2.52
Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).
Standard error
SE = 5/√81 = 5/9 = 0.5556
Test statistic
t = (498.6 − 500)/0.5556 = −2.52
Answer
t = −2.52
t0.025; df = 80 = 1.99
|t| > 1.99, so H₀ is rejected at the 5% level (two-sided).
18.Hypothesis tests & confidence intervals
Answer: n = 1559
Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).
Solve for n
n = (1.645·12/0.5)² = 1559
Round up
n = 1559
Answer
n = 1559
19.Linear regression & correlation
Answer: r² = 0.9837
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.
Means
x̄ = 42/6 = 7
ȳ = 153/6 = 25.5
Sums of squares and products
Sxx = Σ(x − x̄)² = 70
Sxy = Σ(x − x̄)(y − ȳ) = 243
Syy = Σ(y − ȳ)² = 857.5
Coefficient of determination
r² = 243²/(70·857.5) = 0.9837
Answer
r² = 0.9837
About 98.37% of the variation in y is explained by the line.
20.Linear regression & correlation
Answer: x = 3.091
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.