You need €10 000 in 7 years. An account pays 3% per year, compounded monthly. How much must you deposit today? Find the present value PV.
FV = €10 0003% / 12n = 7
PV = €
2.Time value of moneyHard
A mortgage of €200 000 is repaid with equal monthly payments over 20 years at 7.2% per year, compounded monthly. How much is still owed just after the payment at the end of year 12? Find the outstanding balance B.
P = €200 0007.2% / 12N = 240k = 144
B = €
3.NPV & IRRMedium
A project costs €50 000 today and returns €21 500, €15 500, €20 500, €20 000, €13 000, €11 500 at the end of years 1 to 6. The cost of capital is 6%. Assume cash flows arrive evenly through each year. Find the discounted payback period DPB in years.
A project costs €50 000 and returns €19 500, €27 000, €21 500 at the end of years 1 to 3. Find its internal rate of return IRR in percent.
CF0 = −50 000CF1 = 19 500CF2 = 27 000CF3 = 21 500
IRR = %
5.Bond pricing & yieldMedium
You buy a bond with 5 years to maturity (face value €1 000, annual coupon 3%) when its yield to maturity is 7%. One year later, just after receiving the first coupon, you sell it when the yield to maturity is 8%. Find your holding period return HPR in percent.
F = €1 000coupon = 3%n = 5y0 = 7%y1 = 8%
HPR = %
6.Bond pricing & yieldHard
A bond with 12 years to maturity (face value €1 000, annual coupon 7%) sells for €1 129. The issuer can call it in 4 years at a call price of €1 070. Find the yield to call YTC in percent.
F = €1 000coupon = 7%P = €1 129call price = €1 070call in 4 years
YTC = %
7.CAPM & WACCMedium
A company has equity worth €5 000 000 and debt worth €4 000 000. Its cost of equity is 9%, its pre-tax cost of debt is 4% and the tax rate is 25%. Find the WACC.
E = €5 000 000D = €4 000 000re = 9%rd = 4%T = 25%
WACC = %
8.CAPM & WACCHard
A company's business has an unlevered (asset) beta of 0.6. It plans a debt-to-equity ratio of 0.25. The tax rate is 20%, the risk-free rate is 2% and the market risk premium is 6.5%. Find the cost of equity re at the new capital structure.
βU = 0.6D/E = 0.25T = 20%rf = 2%rm − rf = 6.5%
re = %
9.Descriptive statisticsMedium
Find the sample standard deviation s of the data: 41, 17, 18, 49, 59.
n = 5
s =
10.Descriptive statisticsHard
Exam scores are normally distributed with mean 170 and standard deviation 10. Find the z-score z of a score of 180.
μ = 170σ = 10x = 180
z =
11.ProbabilityMedium
A bag holds 7 red and 6 blue balls. You draw two balls without putting the first one back. What is the probability P that both are red?
7 / 6
P =
12.ProbabilityHard
9 components are tested, and each one fails with probability 0.6, independently. What is the probability P that at most one fails?
n = 9p = 0.6
P =
13.Normal distributionMedium
The heights of adult men are normally distributed with mean 178 cm and standard deviation 7 cm. What fraction lies between 174.5 and 192.35 cm? Give P as a decimal.
μ = 178σ = 7x1 = 174.5x2 = 192.35
P =
14.Normal distributionHard
The delivery times are normally distributed with mean 32 min and standard deviation 6 min. Find the value x below which 99% of them lie (the 99th percentile).
μ = 32σ = 6P = 99%
x = min
15.Confidence intervalsMedium
A sample of 11 items has mean 40 and standard deviation s = 18. The population is roughly normal. Find the lower limit of the 99% confidence interval for the mean.
n = 11x̄ = 40s = 1899%t(10) = 3.169
lower limit =
16.Confidence intervalsHard
The population standard deviation is 20. How large a sample n do you need so that a 99% confidence interval for the mean has a margin of error of at most 4?
σ = 20E = 499%
n =
17.Hypothesis tests & confidence intervalsMedium
11 employees take a typing test before and after a training course. For each person the difference d = after − before (words per minute) is recorded. The mean difference is 8.23 and the standard deviation of the differences is 7. Find the paired test statistic t for H₀: μd = 0.
n = 11d̄ = 8.23sd = 7
t =
18.Hypothesis tests & confidence intervalsHard
In a trial, 40 of 100 patients on treatment A recover, and 58 of 120 patients on treatment B. Using the pooled proportion, find the test statistic z for H₀: p₁ = p₂.
x₁ = 40n₁ = 100x₂ = 58n₂ = 120
z =
19.Linear regression & correlationMedium
The table gives 5 paired observations of x = advertising spend in k€ and y = sales in k€. Find Pearson's correlation coefficient r.
n = 5
r =
20.Linear regression & correlationHard
The table gives 6 paired observations of x = load in kN and y = extension in mm. Use the least-squares line ŷ = a + b·x. Predict ŷ for x = 9.
n = 6x = 9
ŷ =
3Solutions
1.Time value of money
Answer: PV = 8108 €
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
Rate and number of periods
i = 0.03/12 = 0.0025
N = 12·7 = 84
Present value
PV = FV/(1 + i)N = 10 000/1.233 = €8 107.97
Answer
PV = €8 107.97
2.Time value of money
Answer: B = 114661 €
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
Whatever is still owed must be exactly paid off by the remaining payments.
N − k = 240 − 144 = 96
B = 1575·(1 − (1 + 0.006)−96)/0.006 = €114 661.47
Answer
B = €114 661.47
3.NPV & IRR
Answer: DPB = 2.925 years
Payback period: the time until the cumulative cash flows repay the initial investment. Cash is assumed to come in evenly during each year, so the last part is a fraction of a year. The simple payback ignores the time value of money; the discounted payback period uses the discounted cash flows instead.
Discounted and cumulative cash flows
year 1: 21 500/1.06 = 20 283.02 → Σ = 20 283.02
year 2: 15 500/1.124 = 13 794.94 → Σ = 34 077.96
year 3: 20 500/1.191 = 17 212.20 → Σ = 51 290.16
Fraction of the last year
DPB = 2 + 15 922.04/17 212.20 = 2.925
Answer
DPB = 2.925 years
The discounted payback is always longer than the simple payback (2.634 years).
4.NPV & IRR
Answer: IRR = 16.78 %
Net present value: discount every cash flow back to today with the required rate of return r, then add them up: NPV = Σ CFₜ/(1 + r)ᵗ. A project with NPV > 0 earns more than r and adds value. The internal rate of return (IRR) is the rate at which NPV = 0.
Bracket the IRR
NPV falls as the rate rises, so the IRR lies between a rate with positive NPV and one with negative NPV.
NPV(15%) = 1 509.00
NPV(20%) = −2 557.87
Narrow down
Linear interpolation gives a first estimate; repeating it (or a calculator's IRR function) gives the exact rate.
Bond pricing: a bond’s price is the present value of its cash flows, discounted at the yield to maturity (YTM): the coupons form an annuity and the face value is paid back at maturity. P = C·(1 − (1 + y)⁻ⁿ)/y + F/(1 + y)ⁿ. When the yield is above the coupon rate the bond trades below face value, and the other way round.
Bond pricing: a bond’s price is the present value of its cash flows, discounted at the yield to maturity (YTM): the coupons form an annuity and the face value is paid back at maturity. P = C·(1 − (1 + y)⁻ⁿ)/y + F/(1 + y)ⁿ. When the yield is above the coupon rate the bond trades below face value, and the other way round.
Equation for the yield
1129 = 70·(1 − (1 + y)−4)/y + 1070/(1 + y)4
Solve numerically
y = 4%: €1 168.73
y = 5%: €1 128.51
YTC = 4.987%
Answer
YTC = 4.987%
The yield to maturity is 5.503%. Investors in a premium bond expect it to be called, so the lower yield to call is the more realistic one.
7.CAPM & WACC
Answer: WACC = 6.333 %
Cost of capital: CAPM gives the return shareholders require: re = rf + β·(rm − rf). The weighted average cost of capital mixes equity and debt by their market values: WACC = E/V·re + D/V·rd·(1 − T), with V = E + D. Interest is tax-deductible, hence the (1 − T).
Weights
V = €9 000 000, E/V = 0.5556, D/V = 0.4444
WACC
WACC = 0.5556·9% + 0.4444·4%·(1 − 0.25) = 6.333%
Answer
WACC = 6.333%
8.CAPM & WACC
Answer: re = 6.68 %
Levered beta (Hamada): debt makes equity riskier. βL = βU·(1 + (1 − T)·D/E), where βU is the beta of the business without debt. To move a beta to another capital structure, unlever it first and then relever it at the new D/E.
Levered beta
βL = 0.6·(1 + 0.8·0.25) = 0.72
Cost of equity (CAPM)
re = 2% + 0.72·6.5% = 6.68%
Answer
re = 6.68%
9.Descriptive statistics
Answer: s = 18.74
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Standardise
z = (180 − 170)/10 = 1
Answer
z = 1
11.Probability
Answer: P = 0.2692
Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.
First and second draw
P = 7/13 · 6/12 = 42/156 = 0.2692
Answer
P = 0.2692
12.Probability
Answer: P = 0.003801
Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.
Zero and one failure
P(X = 0) = 0.49 = 0.0002621
P(X = 1) = 9·0.6·0.48 = 0.003539
Add them
P = 0.0002621 + 0.003539 = 0.003801
Answer
P = 0.003801
13.Normal distribution
Answer: P = 0.6713
Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.
z-scores
z₁ = (174.5 − 178)/7 = −0.5
z₂ = (192.35 − 178)/7 = 2.05
Area between
P = Φ(2.05) − Φ(−0.5) = 0.9798 − 0.3085 = 0.6713
Answer
P = 0.6713
14.Normal distribution
Answer: x = 45.96 min
Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.
z for the percentile
Φ(z) = 0.99 → z = 2.326
Back to x
x = 32 + 2.326·6 = 45.96 min
Answer
x = 45.96 min
15.Confidence intervals
Answer: lower limit = 22.8
Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.
Critical value
df = n − 1 = 10, t = 3.169
Margin of error
E = 3.169·18/√11 = 17.2
Interval
40 ± 17.2 → [22.8, 57.2]
Answer
lower limit = 22.8
16.Confidence intervals
Answer: n = 166
Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.
Solve for n
n = (2.576·20/4)² = 165.9
Round up
A sample size is a whole number, and rounding down would make the margin too large.
n = 166
Answer
n = 166
17.Hypothesis tests & confidence intervals
Answer: t = 3.899
Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).
Standard error of the mean difference
SE = 7/√11 = 2.111
Test statistic
t = 8.23/2.111 = 3.899
Answer
t = 3.899
With df = 10, the two-sided 5% critical value is 2.228; |t| is larger, so H₀ is rejected.
18.Hypothesis tests & confidence intervals
Answer: z = −1.238
Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.
Sample proportions
p̂₁ = 40/100 = 0.4
p̂₂ = 58/120 = 0.4833
p̂ = 98/220 = 0.4455
Standard error under H₀
SE = √(0.4455·0.5545·(1/100 + 1/120)) = 0.0673
Test statistic
z = (0.4 − 0.4833)/0.0673 = −1.238
Answer
z = −1.238
|z| < 1.96, so H₀ is not rejected at the 5% level (two-sided).
19.Linear regression & correlation
Answer: r = 0.9768
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.
Means
x̄ = 20/5 = 4
ȳ = 235/5 = 47
Sums of squares and products
Sxx = Σ(x − x̄)² = 10
Sxy = Σ(x − x̄)(y − ȳ) = 63
Syy = Σ(y − ȳ)² = 416
Correlation coefficient
r = 63/√(10·416) = 0.9768
Answer
r = 0.9768
20.Linear regression & correlation
Answer: ŷ = 35.68
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.
Means
x̄ = 42/6 = 7
ȳ = 169/6 = 28.17
Sums of squares and products
Sxx = Σ(x − x̄)² = 70
Sxy = Σ(x − x̄)(y − ȳ) = 263
Regression line
b = 263/70 = 3.757
a = 28.17 − 3.757·7 = 1.867
ŷ = 1.867 + 3.757·x
Prediction
ŷ = 1.867 + 3.757·9 = 35.68
Answer
ŷ = 35.68
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