Clinical Nutrition: cram pack

Formula sheets, the key method steps for every topic and 4 practice problems, with full solutions at the back.

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1Formulas and methods

Enteral & parenteral nutrition calculations

Daily volume
mL = kcal / (kcal/mL)
Continuous feed
mL/h = daily volume / hours of feeding
Bolus feed
mL per feed = daily volume / number of feeds
Energy and protein delivered
kcal = mL × kcal/mL; g = L × g/L
Free water
mL = formula volume × water fraction
Ideal body weight (Devine)
men 50 + 2.3 × (in − 60); women 45.5 + 2.3 × (in − 60); 1 in = 2.54 cm
Body mass index
BMI = kg/m²
Parenteral nutrition
dextrose 3.4 kcal/g, amino acids 4 kcal/g, lipid 20% 2.0 kcal/mL, 10% 1.1 kcal/mL
Nitrogen
g N = g protein / 6.25
Glucose infusion rate
GIR = mg/(kg·min) = % × mL/h / (6 × kg)

Method

  1. Write down what is asked: a pump rate, a volume, kilocalories, grams of protein or water.
  2. Turn energy into volume with mL = kcal/(kcal/mL), and volume into protein with litres × g/L.
  3. Divide by the hours the feed actually runs for a rate, or by the number of feeds for a bolus.
  4. For needs, multiply kcal/kg or g/kg by the weight the rule names; find the ideal body weight with Devine: 50 or 45.5 + 2.3 × (inches − 60).
  5. For PN, find grams as % × mL/100, then use 3.4 kcal/g for dextrose, 4 kcal/g for amino acids and the stated kcal/mL for lipid.

IV fluids & fluid balance

Holliday–Segar per hour
4 mL/kg (first 10 kg) + 2 mL/kg (next 10 kg) + 1 mL/kg (each kg above 20)
Holliday–Segar per day
100 / 50 / 20 mL/kg for the same bands
Fluid balance
intake − output
Ice chips
count as half their volume
Urine output
mL/kg/h = mL / (kg × h)
Infusion time
time (h) = volume left (mL) / rate (mL/h)
Volume infused
mL = rate × time

2Practice problems

1.Enteral & parenteral nutrition calculationsMedium
55 g/L1.5 g/kg/day85 mL/h81 kg18 h/dayΔP = ? g

Practice exercise (made-up values, not clinical guidance). An 81 kg patient needs 1.5 g of protein per kg a day. The tube feed contains 55 g of protein per litre and runs at 85 mL/h for 18 hours a day. How many grams of extra protein ΔP a day are still needed? Round to one decimal place.

81 kg1.5 g/kg/day55 g/L85 mL/h · 18 h
ΔP = g/day
2.Enteral & parenteral nutrition calculationsHard
12 hdextrose 20%1200 mLamino acids 6%1200 mL73 kg12 hGIR = ? mg/kg/min

Practice exercise (made-up values, not clinical guidance). A 73 kg adult receives 1200 mL of parenteral nutrition containing 20% dextrose, infused over 12 hours. Find the glucose infusion rate GIR in mg/kg/min. Round to two decimal places.

73 kg1200 mLdextrose 20%12 h
GIR = mg/kg/min
3.IV fluids & fluid balanceMedium
IntakeOutput8-hour shiftmilk100 mLjelly100 mLjuice200 mLIV infusion100 mL/h × 8 hIV antibiotic1 × 50 mLurine400 mLurine150 mLwound drain100 mLvomit250 mL

Practice exercise (made-up values, not clinical guidance). The record shows a patient's intake and output for one 8-hour shift. The patient weighs 45 kg. Find the average urine output U in mL/kg/h. Round to two decimal places.

45 kg8 hurine: 400 mLurine: 150 mLwound drain: 100 mLvomit: 250 mL
U = mL/kg/h
4.IV fluids & fluid balanceHard
1000 mL→ 150 mL/hstart 18:00ttotal​ = ? h80 mL/h × 2 h

Practice exercise (made-up values, not clinical guidance). A 1000 mL infusion starts at 18:00 at 80 mL/h. After 2 hours the rate is changed to 150 mL/h and is not changed again. How many hours t after the start will the bag be empty? Round to one decimal place.

1000 mL80 mL/h · 2 h150 mL/h
t = h

3Solutions

1.Enteral & parenteral nutrition calculations

Answer: ΔP = 37.4 g/day

Needs and free water: energy needs are often estimated as kcal/kg/day × weight and protein needs as g/kg/day × weight. A formula is only partly water, so its free water = volume × water fraction; water flushes make up the rest of the daily fluid goal. Ideal body weight (Devine): IBW = 50 kg + 2.3 kg for every inch over 5 feet (60 in) for men, and 45.5 kg + 2.3 kg per inch over 60 in for women; 1 in = 2.54 cm. The formula is meant for adults at least 152.4 cm (5 ft) tall. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Protein needed

1.5·81 = 121.5 g/day

Protein from the feed

85·18 = 1530 mL = 1.53 L
1.53·55 = 84.15 g/day

Shortfall

ΔP = 121.5 − 84.15 = 37.35 ≈ 37.4 g/day

Answer

ΔP = 37.4 g/day
2.Enteral & parenteral nutrition calculations

Answer: GIR = 4.57 mg/kg/min

Parenteral nutrition: dextrose provides 3.4 kcal/g, amino acids 4 kcal/g and lipid emulsion the kcal/mL stated (2 kcal/mL for 20%, 1.1 kcal/mL for 10%). Grams = % × mL/100. Non-protein kcal (NPC) = dextrose + lipid kcal; nitrogen = protein/6.25. The glucose infusion rate (GIR) in mg/kg/min = dextrose mg/(kg × minutes). The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Dextrose in the bag

20·1200/100 = 240 g = 240 000 mg

Minutes of infusion

12·60 = 720 min

Glucose infusion rate

GIR = 240 000/(73·720) = 4.566 ≈ 4.57 mg/kg/min

Answer

GIR = 4.57 mg/kg/min
3.IV fluids & fluid balance

Answer: U = 1.53 mL/kg/h

Intake and output: intake counts everything that goes in (oral fluids, IV infusions, IV medications and flushes, tube feeds); ice chips count as half their volume. Output counts urine, drains, vomit and other losses. Balance = total intake − total output; a negative balance is a net loss. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Total urine

400 + 150 = 550 mL

Per kilogram per hour

U = 550/(45·8) = 1.528 ≈ 1.53 mL/kg/h

Answer

U = 1.53 mL/kg/h
4.IV fluids & fluid balance

Answer: t = 7.6 h

Infusion time: time (h) = volume to infuse (mL)/rate (mL/h); use the volume still left in the bag, not the bag size. Volume infused = rate × time. Convert decimal hours to hours and minutes with the fraction × 60 (0.5 h = 30 min, not 50 min). The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

First part

80·2 = 160 mL
1000 − 160 = 840 mL left

Second part

840/150 = 5.6 h

Total time

t = 2 + 5.6 = 7.6 h

Answer

t = 7.6 h

That is about 7 h 36 min, so the bag runs out at about 01:36.

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