Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the gentamicin level is 10 mg/L. The half-life is 3 h, and the drug is eliminated by first-order kinetics. What is the level C 9 h later?
Find C (mg/L)
Show hints
- Number of half-lives: n = t/t½.
- C = C₀·(1/2)ⁿ, or C = C₀·e^(−kt) with k = 0.693/t½.
- n = 9/3 = 3.
Show the answer and the step-by-step solution
First-order elimination: a constant fraction of the drug is removed per hour, so C = C₀·e−kt with k = ln 2/t½ = 0.693/t½. After n half-lives C = C₀·(1/2)ⁿ. With regular doses or an infusion, the level reaches 1 − (1/2)ⁿ of steady state after n half-lives: about 97% after 5. A loading dose fills the volume of distribution: LD = Vd × C. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.