Computer Networks: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

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1Formulas and methods

IPv4 subnetting

Hosts per subnet
2(32 − prefix) − 2 (/31: 2, /32: 1)
Block size
256 − (mask octet)
Network address
IP AND mask
Broadcast address
IP OR (NOT mask): all host bits set to 1
Subnets from n borrowed bits
2n

Number systems

Place values
binary 2k, octal 8k, hex 16k
To decimal
Σ dk·bk
From decimal
divide by the base, read the remainders bottom-up
Hex ↔ binary
one hex digit = 4 bits
Two’s complement
invert the bits and add 1

2Practice problems

1.IPv4 subnettingMedium
/24 → /2511111111111111111111111110000000network bitshost bits

The network 192.168.93.0/24 is divided into /25 subnets, numbered 1, 2, 3, … from the lowest address (subnet 1 starts at .0). What is the fourth octet x of the network address of subnet 2?

192.168.93.0/24/25subnet 2 (subnet 1 starts at .0)
x =
2.IPv4 subnettingHard
third octet 3 … 6012806403201608041211commonvaries

A router has routes to these networks: 10.57.3.0/24, 10.57.4.0/24, 10.57.5.0/24, 10.57.6.0/24. What is the longest prefix length p of a single summary route that covers all of them?

10.57.3.0/24 … 10.57.6.0/24
p =
3.Computer networksMedium

Which of these is a private IPv4 address range?

  1. A192.168.0.0/16
  2. B100.0.0.0/8
  3. C200.1.1.0/24
  4. D8.8.8.0/24
4.Computer networksHard

In the TCP/IP model, which layer adds port numbers?

  1. ATransport layer
  2. BApplication layer
  3. CInternet layer
  4. DLink layer
5.Number systemsMedium
8-bit two's complement?−128?64?32?16?8?4?2?1

Write −69 as an 8-bit two's complement pattern. Read the pattern as an unsigned binary number: what is its value U in decimal?

N = −698 bit
U =
6.Number systemsHard
click the bits to set them012806403201608040201

Set the bits to the 8-bit result of 0110 0100 AND 0110 0100. What is the result's value R in decimal?

0110 0100AND0110 0100
R =

3Solutions

1.IPv4 subnetting

Answer: x = 128

IPv4 subnetting: an address has 32 bits. The prefix /p says how many leading bits identify the network; the remaining 32 − p bits number the hosts. A subnet has 2³²⁻ᵖ addresses, but the first (network address) and last (broadcast address) cannot be given to hosts, so 2³²⁻ᵖ − 2 hosts fit. Exceptions: a /31 (point-to-point link, RFC 3021) uses both of its 2 addresses for hosts, and a /32 is one single address (a single host or a loopback).

Block size

27 = 128

Subnet number 2

network: (2 − 1)·128 = 128
broadcast: 128 + 128 − 1 = 255

Answer

x = 128
2.IPv4 subnetting

Answer: p = 21

Route summarisation: a summary route a.b.c.0/p covers all networks whose first p bits match. Write the differing octet of the first and last network in binary; the number of common leading bits, plus the bits of the octets before it, is the longest summary prefix.

Compare the bits

3 = 00000011
6 = 00000110
common leading bits: 5

Prefix length

p = 16 + 5 = 21

Answer

p = /21

Summary route: 10.57.0.0/21 (it also covers 4 network(s) that are not in the list).

3.Computer networks

Answer: A · 192.168.0.0/16

Why this is the answer

Private ranges are 10.0.0.0/8, 172.16.0.0/12 and 192.168.0.0/16; they are not routed on the public internet.

Answer

A · 192.168.0.0/16
4.Computer networks

Answer: A · Transport layer

Why this is the answer

TCP and UDP headers contain source and destination ports; the internet layer (IP) adds addresses.

Answer

A · Transport layer
5.Number systems

Answer: U = 187

Positional number systems: each digit is worth its value times a power of the base. In binary the places are worth 1, 2, 4, 8, 16, …; in hexadecimal 1, 16, 256, …, with A–F standing for 10–15. In 8-bit two's complement the leftmost bit is worth −128 instead of +128, which is how negative numbers are stored.

Invert and add one

69 = 0100 0101
inverted: 1011 1010
+1 → 1011 1011

Read it as unsigned

1011 1011₂ = 256 − 69 = 187

Answer

U = 187
6.Number systems

Answer: R = 100

Setting bits: each bit is worth a power of two (128, 64, …, 1). One hex digit is exactly four bits, and in 8-bit two's complement the leftmost bit is worth −128. Bitwise operations work on each bit position separately.

Bit by bit

AND gives 1 only where both bits are 1.

0110 0100
AND 0110 0100
= 0110 0100

Value of the result

0110 0100₂ = 100

Answer

R = 100

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