Computer Networks: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

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1Formulas and methods

IPv4 subnetting

Hosts per subnet
2(32 − prefix) − 2 (/31: 2, /32: 1)
Block size
256 − (mask octet)
Network address
IP AND mask
Broadcast address
IP OR (NOT mask): all host bits set to 1
Subnets from n borrowed bits
2n

Number systems

Place values
binary 2k, octal 8k, hex 16k
To decimal
Σ dk·bk
From decimal
divide by the base, read the remainders bottom-up
Hex ↔ binary
one hex digit = 4 bits
Two’s complement
invert the bits and add 1

2Practice problems

1.IPv4 subnettingMedium
255.255.255.25211111111111111111111111111111100network bitshost bits

A subnet uses the mask 255.255.255.252. How many usable host addresses H does it have?

255.255.255.252
H =
2.IPv4 subnettingHard
third octet 53 … 54012806413211608140211commonvaries

A router has routes to these networks: 10.56.53.0/24, 10.56.54.0/24. What is the longest prefix length p of a single summary route that covers all of them?

10.56.53.0/24 … 10.56.54.0/24
p =
3.Computer networksMedium

A browser receives HTTP status code 404. What does it mean?

  1. AThe request succeeded
  2. BThe requested resource was not found
  3. CThe client must log in first
  4. DThe server had an internal error
4.Computer networksHard

By Shannon's theorem, what is the capacity of a 1 MHz channel with a signal-to-noise ratio of 255?

  1. A8 Mbit/s
  2. B1 Mbit/s
  3. C2 Mbit/s
  4. D255 Mbit/s
5.Number systemsMedium
place values in two's complement1−12816413201608141211

The 8-bit pattern 1110 0111 stores a signed integer in two's complement. What is its value N in decimal?

1110 01118 bit
N =
6.Number systemsHard
3261 codes, b = ? bits?2ᵇ⁻¹…?4?2?1

A system must give every one of 3261 items its own binary code of the same length. What is the smallest number of bits b needed?

3261
b = bit

3Solutions

1.IPv4 subnetting

Answer: H = 2

IPv4 subnetting: an address has 32 bits. The prefix /p says how many leading bits identify the network; the remaining 32 − p bits number the hosts. A subnet has 2³²⁻ᵖ addresses, but the first (network address) and last (broadcast address) cannot be given to hosts, so 2³²⁻ᵖ − 2 hosts fit. Exceptions: a /31 (point-to-point link, RFC 3021) uses both of its 2 addresses for hosts, and a /32 is one single address (a single host or a loopback).

Prefix length

255.255.255.252 = /30

Usable hosts

22 − 2 = 2

Answer

H = 2
2.IPv4 subnetting

Answer: p = 22

Route summarisation: a summary route a.b.c.0/p covers all networks whose first p bits match. Write the differing octet of the first and last network in binary; the number of common leading bits, plus the bits of the octets before it, is the longest summary prefix.

Compare the bits

53 = 00110101
54 = 00110110
common leading bits: 6

Prefix length

p = 16 + 6 = 22

Answer

p = /22

Summary route: 10.56.52.0/22 (it also covers 2 network(s) that are not in the list).

3.Computer networks

Answer: B · The requested resource was not found

Why this is the answer

404 Not Found means the server has no resource at that URL. 200 is OK, 401 is Unauthorized and 500 is Internal Server Error.

Answer

B · The requested resource was not found
4.Computer networks

Answer: A · 8 Mbit/s

Why this is the answer

C = 10⁶ × log₂(256) = 10⁶ × 8 = 8 Mbit/s. This is the upper limit for error-free data rate on a noisy channel.

Answer

A · 8 Mbit/s
5.Number systems

Answer: N = −25

Positional number systems: each digit is worth its value times a power of the base. In binary the places are worth 1, 2, 4, 8, 16, …; in hexadecimal 1, 16, 256, …, with A–F standing for 10–15. In 8-bit two's complement the leftmost bit is worth −128 instead of +128, which is how negative numbers are stored.

Add the place values

The other bits keep their normal positive values.

−128 + 64 + 32 + 4 + 2 + 1 = −25

Answer

N = −25
6.Number systems

Answer: b = 12 bit

Positional number systems: each digit is worth its value times a power of the base. In binary the places are worth 1, 2, 4, 8, 16, …; in hexadecimal 1, 16, 256, …, with A–F standing for 10–15. In 8-bit two's complement the leftmost bit is worth −128 instead of +128, which is how negative numbers are stored.

Powers of two

211 = 2048 < 3261
212 = 4096 ≥ 3261

Answer

b = 12

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