Computer Networks: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

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1Formulas and methods

IPv4 subnetting

Hosts per subnet
2(32 − prefix) − 2 (/31: 2, /32: 1)
Block size
256 − (mask octet)
Network address
IP AND mask
Broadcast address
IP OR (NOT mask): all host bits set to 1
Subnets from n borrowed bits
2n

Number systems

Place values
binary 2k, octal 8k, hex 16k
To decimal
Σ dk·bk
From decimal
divide by the base, read the remainders bottom-up
Hex ↔ binary
one hex digit = 4 bits
Two’s complement
invert the bits and add 1

2Practice problems

1.IPv4 subnettingMedium
255.255.240.011111111111111111111000000000000network bitshost bits

A subnet uses the mask 255.255.240.0. How many usable host addresses H does it have?

255.255.240.0
H =
2.IPv4 subnettingHard
third octet = 248112816413211618040201networkhost

A host has the address 172.20.248.132/20. What is the third octet x of its network address?

172.20.248.132/20
x =
3.Computer networksMedium

Which metric does RIP use to choose routes?

  1. AHop count
  2. BMeasured delay
  3. CLink bandwidth
  4. DBusiness policy
4.Computer networksHard

An 8-port switch (no VLANs) has one host on each port. How many collision domains and broadcast domains are there?

  1. A1 collision domain, 1 broadcast domain
  2. B8 collision domains, 8 broadcast domains
  3. C8 collision domains, 1 broadcast domain
  4. D1 collision domain, 8 broadcast domains
5.Number systemsMedium
8-bit two's complement0−12806403201608040201

Set the bits so they store −77 in 8-bit two's complement. Read as an unsigned number, what is the pattern's value U?

N = −778 bit
U =
6.Number systemsHard
click the bits to set them012806403201608040201

Set the bits to the 8-bit result of 1110 0011 >> 3. What is the result's value R in decimal?

1110 0011>> 3
R =

3Solutions

1.IPv4 subnetting

Answer: H = 4094

IPv4 subnetting: an address has 32 bits. The prefix /p says how many leading bits identify the network; the remaining 32 − p bits number the hosts. A subnet has 2³²⁻ᵖ addresses, but the first (network address) and last (broadcast address) cannot be given to hosts, so 2³²⁻ᵖ − 2 hosts fit. Exceptions: a /31 (point-to-point link, RFC 3021) uses both of its 2 addresses for hosts, and a /32 is one single address (a single host or a loopback).

Prefix length

255.255.240.0 = /20

Usable hosts

212 − 2 = 4094

Answer

H = 4094
2.IPv4 subnetting

Answer: x = 240

IPv4 subnetting: an address has 32 bits. The prefix /p says how many leading bits identify the network; the remaining 32 − p bits number the hosts. A subnet has 2³²⁻ᵖ addresses, but the first (network address) and last (broadcast address) cannot be given to hosts, so 2³²⁻ᵖ − 2 hosts fit. Exceptions: a /31 (point-to-point link, RFC 3021) uses both of its 2 addresses for hosts, and a /32 is one single address (a single host or a loopback).

Block size in the third octet

24 = 16

Subnet of this host

network: 172.20.240.0
broadcast: 172.20.255.255

Answer

x = 240
3.Computer networks

Answer: A · Hop count

Why this is the answer

RIP is a distance-vector protocol that counts hops, with 16 meaning unreachable. This limits it to small networks.

Answer

A · Hop count
4.Computer networks

Answer: C · 8 collision domains, 1 broadcast domain

Why this is the answer

Each switch port is its own collision domain, but broadcasts are forwarded to all ports, so the whole switch is one broadcast domain. A hub would give one of each.

Answer

C · 8 collision domains, 1 broadcast domain
5.Number systems

Answer: U = 179

Setting bits: each bit is worth a power of two (128, 64, …, 1). One hex digit is exactly four bits, and in 8-bit two's complement the leftmost bit is worth −128. Bitwise operations work on each bit position separately.

Invert and add one

77 = 0100 1101
inverted: 1011 0010
+1 → 1011 0011

Read it as unsigned

1011 0011₂ = 256 − 77 = 179

Answer

U = 179
6.Number systems

Answer: R = 28

Setting bits: each bit is worth a power of two (128, 64, …, 1). One hex digit is exactly four bits, and in 8-bit two's complement the leftmost bit is worth −128. Bitwise operations work on each bit position separately.

Bit by bit

Shifting right by 3 moves every bit 3 places to the right; bits that fall off the right end are lost and zeros come in on the left.

1110 0011 >> 3
= 0001 1100

Value of the result

0001 1100₂ = 28

Answer

R = 28

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