Computer Networks: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

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1Formulas and methods

IPv4 subnetting

Hosts per subnet
2(32 − prefix) − 2 (/31: 2, /32: 1)
Block size
256 − (mask octet)
Network address
IP AND mask
Broadcast address
IP OR (NOT mask): all host bits set to 1
Subnets from n borrowed bits
2n

Number systems

Place values
binary 2k, octal 8k, hex 16k
To decimal
Σ dk·bk
From decimal
divide by the base, read the remainders bottom-up
Hex ↔ binary
one hex digit = 4 bits
Two’s complement
invert the bits and add 1

2Practice problems

1.IPv4 subnettingMedium
/24 → /2911111111111111111111111111111000network bitshost bits

The network 192.168.10.0/24 must be divided into at least 30 equal subnets. If you borrow as few bits as possible, how many usable hosts H does each subnet have?

192.168.10.0/2430 subnets
H =
2.IPv4 subnettingHard
last octet = 100012816413201608140201networkhost

A host has the address 10.20.253.100/26. What is the fourth octet x of its network address?

10.20.253.100/26
x =
3.Computer networksMedium

What characterises a distributed denial-of-service (DDoS) attack?

  1. AAn attacker reads unencrypted Wi-Fi traffic from a nearby car
  2. BA virus deletes files on a single PC
  3. CMany compromised machines flood a target with traffic
  4. DOne attacker guesses a user's password
4.Computer networksHard

In the TCP/IP model, which layer adds port numbers?

  1. AInternet layer
  2. BTransport layer
  3. CApplication layer
  4. DLink layer
5.Number systemsMedium
8-bit two's complement0−12806403201608040201

Set the bits so they store −40 in 8-bit two's complement. Read as an unsigned number, what is the pattern's value U?

N = −408 bit
U =
6.Number systemsHard
20-bit two's complement, N = ??sign???????????????????

What is the most negative integer N that can be stored in 20-bit two's complement?

20 bit
N =

3Solutions

1.IPv4 subnetting

Answer: H = 6

IPv4 subnetting: an address has 32 bits. The prefix /p says how many leading bits identify the network; the remaining 32 − p bits number the hosts. A subnet has 2³²⁻ᵖ addresses, but the first (network address) and last (broadcast address) cannot be given to hosts, so 2³²⁻ᵖ − 2 hosts fit. Exceptions: a /31 (point-to-point link, RFC 3021) uses both of its 2 addresses for hosts, and a /32 is one single address (a single host or a loopback).

Bits to borrow

25 = 32 ≥ 30 → b = 5, /29

Hosts per subnet

23 − 2 = 6

Answer

H = 6
2.IPv4 subnetting

Answer: x = 64

IPv4 subnetting: an address has 32 bits. The prefix /p says how many leading bits identify the network; the remaining 32 − p bits number the hosts. A subnet has 2³²⁻ᵖ addresses, but the first (network address) and last (broadcast address) cannot be given to hosts, so 2³²⁻ᵖ − 2 hosts fit. Exceptions: a /31 (point-to-point link, RFC 3021) uses both of its 2 addresses for hosts, and a /32 is one single address (a single host or a loopback).

Block size

26 = 64

Subnet of this host

network: ⌊100/64⌋·64 = 64
broadcast: 64 + 64 − 1 = 127
usable hosts: 65 … 126

Answer

x = 64
3.Computer networks

Answer: C · Many compromised machines flood a target with traffic

Why this is the answer

In a DDoS attack many sources overwhelm a server or link so legitimate users cannot be served. The many sources make simple blocking hard.

Answer

C · Many compromised machines flood a target with traffic
4.Computer networks

Answer: B · Transport layer

Why this is the answer

TCP and UDP headers contain source and destination ports; the internet layer (IP) adds addresses.

Answer

B · Transport layer
5.Number systems

Answer: U = 216

Setting bits: each bit is worth a power of two (128, 64, …, 1). One hex digit is exactly four bits, and in 8-bit two's complement the leftmost bit is worth −128. Bitwise operations work on each bit position separately.

Invert and add one

40 = 0010 1000
inverted: 1101 0111
+1 → 1101 1000

Read it as unsigned

1101 1000₂ = 256 − 40 = 216

Answer

U = 216
6.Number systems

Answer: N = −524288

Positional number systems: each digit is worth its value times a power of the base. In binary the places are worth 1, 2, 4, 8, 16, …; in hexadecimal 1, 16, 256, …, with A–F standing for 10–15. In 8-bit two's complement the leftmost bit is worth −128 instead of +128, which is how negative numbers are stored.

Most negative value

−219 = −524288

Answer

N = −524288

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