Computer Networks: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

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1Formulas and methods

IPv4 subnetting

Hosts per subnet
2(32 − prefix) − 2 (/31: 2, /32: 1)
Block size
256 − (mask octet)
Network address
IP AND mask
Broadcast address
IP OR (NOT mask): all host bits set to 1
Subnets from n borrowed bits
2n

Number systems

Place values
binary 2k, octal 8k, hex 16k
To decimal
Σ dk·bk
From decimal
divide by the base, read the remainders bottom-up
Hex ↔ binary
one hex digit = 4 bits
Two’s complement
invert the bits and add 1

2Practice problems

1.IPv4 subnettingMedium
/24 → /2611111111111111111111111111000000network bitshost bits

The network 192.168.10.0/24 must be divided into at least 4 equal subnets. If you borrow as few bits as possible, how many usable hosts H does each subnet have?

192.168.10.0/244 subnets
H =
2.IPv4 subnettingHard
last octet = 185112806413211618040211networkhost

A host has the address 10.20.37.185/27. What is the last number (fourth octet) x of its subnet's broadcast address?

10.20.37.185/27
x =
3.Computer networksMedium

A browser receives HTTP status code 404. What does it mean?

  1. AThe server had an internal error
  2. BThe requested resource was not found
  3. CThe client must log in first
  4. DThe request succeeded
4.Computer networksHard

By the Nyquist formula, what is the maximum bit rate of a noiseless 3 kHz channel using 4 signal levels?

  1. A3 kbit/s
  2. B12 kbit/s
  3. C6 kbit/s
  4. D24 kbit/s
5.Number systemsMedium
8-bit two's complement0−12806403201608040201

Set the bits so they store −3 in 8-bit two's complement. Read as an unsigned number, what is the pattern's value U?

N = −38 bit
U =
6.Number systemsHard
10-bit two's complement, N = ??sign?????????

What is the most negative integer N that can be stored in 10-bit two's complement?

10 bit
N =

3Solutions

1.IPv4 subnetting

Answer: H = 62

IPv4 subnetting: an address has 32 bits. The prefix /p says how many leading bits identify the network; the remaining 32 − p bits number the hosts. A subnet has 2³²⁻ᵖ addresses, but the first (network address) and last (broadcast address) cannot be given to hosts, so 2³²⁻ᵖ − 2 hosts fit. Exceptions: a /31 (point-to-point link, RFC 3021) uses both of its 2 addresses for hosts, and a /32 is one single address (a single host or a loopback).

Bits to borrow

22 = 4 ≥ 4 → b = 2, /26

Hosts per subnet

26 − 2 = 62

Answer

H = 62
2.IPv4 subnetting

Answer: x = 191

IPv4 subnetting: an address has 32 bits. The prefix /p says how many leading bits identify the network; the remaining 32 − p bits number the hosts. A subnet has 2³²⁻ᵖ addresses, but the first (network address) and last (broadcast address) cannot be given to hosts, so 2³²⁻ᵖ − 2 hosts fit. Exceptions: a /31 (point-to-point link, RFC 3021) uses both of its 2 addresses for hosts, and a /32 is one single address (a single host or a loopback).

Block size

25 = 32

Subnet of this host

network: ⌊185/32⌋·32 = 160
broadcast: 160 + 32 − 1 = 191
usable hosts: 161 … 190

Answer

x = 191
3.Computer networks

Answer: B · The requested resource was not found

Why this is the answer

404 Not Found means the server has no resource at that URL. 200 is OK, 401 is Unauthorized and 500 is Internal Server Error.

Answer

B · The requested resource was not found
4.Computer networks

Answer: B · 12 kbit/s

Why this is the answer

2 × 3000 × log₂ 4 = 2 × 3000 × 2 = 12,000 bit/s. More levels raise the rate, but noise limits how many can be told apart.

Answer

B · 12 kbit/s
5.Number systems

Answer: U = 253

Setting bits: each bit is worth a power of two (128, 64, …, 1). One hex digit is exactly four bits, and in 8-bit two's complement the leftmost bit is worth −128. Bitwise operations work on each bit position separately.

Invert and add one

3 = 0000 0011
inverted: 1111 1100
+1 → 1111 1101

Read it as unsigned

1111 1101₂ = 256 − 3 = 253

Answer

U = 253
6.Number systems

Answer: N = −512

Positional number systems: each digit is worth its value times a power of the base. In binary the places are worth 1, 2, 4, 8, 16, …; in hexadecimal 1, 16, 256, …, with A–F standing for 10–15. In 8-bit two's complement the leftmost bit is worth −128 instead of +128, which is how negative numbers are stored.

Most negative value

−29 = −512

Answer

N = −512

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