Computer Networks: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

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1Formulas and methods

IPv4 subnetting

Hosts per subnet
2(32 − prefix) − 2 (/31: 2, /32: 1)
Block size
256 − (mask octet)
Network address
IP AND mask
Broadcast address
IP OR (NOT mask): all host bits set to 1
Subnets from n borrowed bits
2n

Number systems

Place values
binary 2k, octal 8k, hex 16k
To decimal
Σ dk·bk
From decimal
divide by the base, read the remainders bottom-up
Hex ↔ binary
one hex digit = 4 bits
Two’s complement
invert the bits and add 1

2Practice problems

1.IPv4 subnettingMedium
/24 → /2811111111111111111111111111110000network bitshost bits

The network 192.168.152.0/24 is divided into /28 subnets, numbered 1, 2, 3, … from the lowest address (subnet 1 starts at .0). What is the fourth octet x of the broadcast address of subnet 3?

192.168.152.0/24/28subnet 3 (subnet 1 starts at .0)
x =
2.IPv4 subnettingHard
third octet 32 … 33012806413201608040201commonvaries

A router has routes to these networks: 10.153.32.0/24, 10.153.33.0/24. What is the longest prefix length p of a single summary route that covers all of them?

10.153.32.0/24 … 10.153.33.0/24
p =
3.Computer networksMedium

How many usable host addresses does a /26 IPv4 subnet have?

  1. A30
  2. B64
  3. C62
  4. D126
4.Computer networksHard

A DNS cache poisoning attack aims to:

  1. AOverload a server with traffic so that it stops answering queries
  2. BDelete DNS servers
  3. CSteal Wi-Fi passwords
  4. DMake a resolver store a false IP address for a domain
5.Number systemsMedium
8-bit two's complement0−12806403201608040201

Set the bits so they store −87 in 8-bit two's complement. Read as an unsigned number, what is the pattern's value U?

N = −878 bit
U =
6.Number systemsHard
click the bits to set them012806403201608040201

Set the bits to the 8-bit result of 0110 1110 >> 1. What is the result's value R in decimal?

0110 1110>> 1
R =

3Solutions

1.IPv4 subnetting

Answer: x = 47

IPv4 subnetting: an address has 32 bits. The prefix /p says how many leading bits identify the network; the remaining 32 − p bits number the hosts. A subnet has 2³²⁻ᵖ addresses, but the first (network address) and last (broadcast address) cannot be given to hosts, so 2³²⁻ᵖ − 2 hosts fit. Exceptions: a /31 (point-to-point link, RFC 3021) uses both of its 2 addresses for hosts, and a /32 is one single address (a single host or a loopback).

Block size

24 = 16

Subnet number 3

network: (3 − 1)·16 = 32
broadcast: 32 + 16 − 1 = 47

Answer

x = 47
2.IPv4 subnetting

Answer: p = 23

Route summarisation: a summary route a.b.c.0/p covers all networks whose first p bits match. Write the differing octet of the first and last network in binary; the number of common leading bits, plus the bits of the octets before it, is the longest summary prefix.

Compare the bits

32 = 00100000
33 = 00100001
common leading bits: 7

Prefix length

p = 16 + 7 = 23

Answer

p = /23

Summary route: 10.153.32.0/23

3.Computer networks

Answer: C · 62

Why this is the answer

A /26 has 6 host bits: 2⁶ = 64 addresses, minus the network and broadcast addresses, gives 62 usable hosts.

Answer

C · 62
4.Computer networks

Answer: D · Make a resolver store a false IP address for a domain

Why this is the answer

Poisoning inserts forged records into a resolver's cache. DNSSEC adds signatures so resolvers can verify records.

Answer

D · Make a resolver store a false IP address for a domain
5.Number systems

Answer: U = 169

Setting bits: each bit is worth a power of two (128, 64, …, 1). One hex digit is exactly four bits, and in 8-bit two's complement the leftmost bit is worth −128. Bitwise operations work on each bit position separately.

Invert and add one

87 = 0101 0111
inverted: 1010 1000
+1 → 1010 1001

Read it as unsigned

1010 1001₂ = 256 − 87 = 169

Answer

U = 169
6.Number systems

Answer: R = 55

Setting bits: each bit is worth a power of two (128, 64, …, 1). One hex digit is exactly four bits, and in 8-bit two's complement the leftmost bit is worth −128. Bitwise operations work on each bit position separately.

Bit by bit

Shifting right by 1 moves every bit 1 places to the right; bits that fall off the right end are lost and zeros come in on the left.

0110 1110 >> 1
= 0011 0111

Value of the result

0011 0111₂ = 55

Answer

R = 55

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