Computer Networks: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

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1Formulas and methods

IPv4 subnetting

Hosts per subnet
2(32 − prefix) − 2 (/31: 2, /32: 1)
Block size
256 − (mask octet)
Network address
IP AND mask
Broadcast address
IP OR (NOT mask): all host bits set to 1
Subnets from n borrowed bits
2n

Number systems

Place values
binary 2k, octal 8k, hex 16k
To decimal
Σ dk·bk
From decimal
divide by the base, read the remainders bottom-up
Hex ↔ binary
one hex digit = 4 bits
Two’s complement
invert the bits and add 1

2Practice problems

1.IPv4 subnettingMedium
255.255.248.011111111111111111111100000000000network bitshost bits

A subnet uses the mask 255.255.248.0. How many usable host addresses H does it have?

255.255.248.0
H =
2.IPv4 subnettingHard
last octet = 103012816413201608141211networkhost

A host has the address 10.20.74.103/29. What is the fourth octet x of its network address?

10.20.74.103/29
x =
3.Computer networksMedium

Which subnet mask corresponds to /20?

  1. A255.255.224.0
  2. B255.255.240.0
  3. C255.255.248.0
  4. D255.255.255.240
4.Computer networksHard

What does BGP mainly do on the internet?

  1. AExchanges routing information between autonomous systems
  2. BAssigns IP addresses to home users through their internet providers
  3. CEncrypts data between routers
  4. DResolves names to addresses
5.Number systemsMedium
8-bit two's complement0−12806403201608040201

Set the bits so they store −106 in 8-bit two's complement. Read as an unsigned number, what is the pattern's value U?

N = −1068 bit
U =
6.Number systemsHard
click the bits to set them012806403201608040201

Set the bits to the 8-bit result of 1011 0011 OR 1001 0110. What is the result's value R in decimal?

1011 0011OR1001 0110
R =

3Solutions

1.IPv4 subnetting

Answer: H = 2046

IPv4 subnetting: an address has 32 bits. The prefix /p says how many leading bits identify the network; the remaining 32 − p bits number the hosts. A subnet has 2³²⁻ᵖ addresses, but the first (network address) and last (broadcast address) cannot be given to hosts, so 2³²⁻ᵖ − 2 hosts fit. Exceptions: a /31 (point-to-point link, RFC 3021) uses both of its 2 addresses for hosts, and a /32 is one single address (a single host or a loopback).

Prefix length

255.255.248.0 = /21

Usable hosts

211 − 2 = 2046

Answer

H = 2046
2.IPv4 subnetting

Answer: x = 96

IPv4 subnetting: an address has 32 bits. The prefix /p says how many leading bits identify the network; the remaining 32 − p bits number the hosts. A subnet has 2³²⁻ᵖ addresses, but the first (network address) and last (broadcast address) cannot be given to hosts, so 2³²⁻ᵖ − 2 hosts fit. Exceptions: a /31 (point-to-point link, RFC 3021) uses both of its 2 addresses for hosts, and a /32 is one single address (a single host or a loopback).

Block size

23 = 8

Subnet of this host

network: ⌊103/8⌋·8 = 96
broadcast: 96 + 8 − 1 = 103
usable hosts: 97 … 102

Answer

x = 96
3.Computer networks

Answer: B · 255.255.240.0

Why this is the answer

/20 means 8 + 8 + 4 one-bits. Four one-bits in the third octet are 11110000 = 240, so the mask is 255.255.240.0.

Answer

B · 255.255.240.0
4.Computer networks

Answer: A · Exchanges routing information between autonomous systems

Why this is the answer

BGP is the inter-domain routing protocol; autonomous systems advertise reachable prefixes and select paths based on policies.

Answer

A · Exchanges routing information between autonomous systems
5.Number systems

Answer: U = 150

Setting bits: each bit is worth a power of two (128, 64, …, 1). One hex digit is exactly four bits, and in 8-bit two's complement the leftmost bit is worth −128. Bitwise operations work on each bit position separately.

Invert and add one

106 = 0110 1010
inverted: 1001 0101
+1 → 1001 0110

Read it as unsigned

1001 0110₂ = 256 − 106 = 150

Answer

U = 150
6.Number systems

Answer: R = 183

Setting bits: each bit is worth a power of two (128, 64, …, 1). One hex digit is exactly four bits, and in 8-bit two's complement the leftmost bit is worth −128. Bitwise operations work on each bit position separately.

Bit by bit

OR gives 1 where at least one bit is 1.

1011 0011
OR 1001 0110
= 1011 0111

Value of the result

1011 0111₂ = 183

Answer

R = 183

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