Computer Networks: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

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1Formulas and methods

IPv4 subnetting

Hosts per subnet
2(32 − prefix) − 2 (/31: 2, /32: 1)
Block size
256 − (mask octet)
Network address
IP AND mask
Broadcast address
IP OR (NOT mask): all host bits set to 1
Subnets from n borrowed bits
2n

Number systems

Place values
binary 2k, octal 8k, hex 16k
To decimal
Σ dk·bk
From decimal
divide by the base, read the remainders bottom-up
Hex ↔ binary
one hex digit = 4 bits
Two’s complement
invert the bits and add 1

2Practice problems

1.IPv4 subnettingMedium
/24 → /2511111111111111111111111110000000network bitshost bits

The network 192.168.252.0/24 is divided into /25 subnets, numbered 1, 2, 3, … from the lowest address (subnet 1 starts at .0). What is the fourth octet x of the network address of subnet 2?

192.168.252.0/24/25subnet 2 (subnet 1 starts at .0)
x =
2.IPv4 subnettingHard
third octet 24 … 31012806403211618040201commonvaries

A router has routes to these networks: 10.171.24.0/24, 10.171.25.0/24, 10.171.26.0/24, 10.171.27.0/24, 10.171.28.0/24, 10.171.29.0/24, 10.171.30.0/24, 10.171.31.0/24. What is the longest prefix length p of a single summary route that covers all of them?

10.171.24.0/24 … 10.171.31.0/24
p =
3.Computer networksMedium

What is the role of a default gateway on a host?

  1. AIt is the switch port the host is connected to
  2. BIt assigns MAC addresses
  3. CIt is the router used for traffic to other networks
  4. DIt is the DNS server
4.Computer networksHard

What does BGP mainly do on the internet?

  1. AResolves names to addresses
  2. BAssigns IP addresses to home users through their internet providers
  3. CEncrypts data between routers
  4. DExchanges routing information between autonomous systems
5.Number systemsMedium
place values in two's complement1−12806403211618140211

The 8-bit pattern 1001 1101 stores a signed integer in two's complement. What is its value N in decimal?

1001 11018 bit
N =
6.Number systemsHard
2489 codes, b = ? bits?2ᵇ⁻¹…?4?2?1

A system must give every one of 2489 items its own binary code of the same length. What is the smallest number of bits b needed?

2489
b = bit

3Solutions

1.IPv4 subnetting

Answer: x = 128

IPv4 subnetting: an address has 32 bits. The prefix /p says how many leading bits identify the network; the remaining 32 − p bits number the hosts. A subnet has 2³²⁻ᵖ addresses, but the first (network address) and last (broadcast address) cannot be given to hosts, so 2³²⁻ᵖ − 2 hosts fit. Exceptions: a /31 (point-to-point link, RFC 3021) uses both of its 2 addresses for hosts, and a /32 is one single address (a single host or a loopback).

Block size

27 = 128

Subnet number 2

network: (2 − 1)·128 = 128
broadcast: 128 + 128 − 1 = 255

Answer

x = 128
2.IPv4 subnetting

Answer: p = 21

Route summarisation: a summary route a.b.c.0/p covers all networks whose first p bits match. Write the differing octet of the first and last network in binary; the number of common leading bits, plus the bits of the octets before it, is the longest summary prefix.

Compare the bits

24 = 00011000
31 = 00011111
common leading bits: 5

Prefix length

p = 16 + 5 = 21

Answer

p = /21

Summary route: 10.171.24.0/21

3.Computer networks

Answer: C · It is the router used for traffic to other networks

Why this is the answer

The host sends packets for non-local destinations to the default gateway, usually its local router.

Answer

C · It is the router used for traffic to other networks
4.Computer networks

Answer: D · Exchanges routing information between autonomous systems

Why this is the answer

BGP is the inter-domain routing protocol; autonomous systems advertise reachable prefixes and select paths based on policies.

Answer

D · Exchanges routing information between autonomous systems
5.Number systems

Answer: N = −99

Positional number systems: each digit is worth its value times a power of the base. In binary the places are worth 1, 2, 4, 8, 16, …; in hexadecimal 1, 16, 256, …, with A–F standing for 10–15. In 8-bit two's complement the leftmost bit is worth −128 instead of +128, which is how negative numbers are stored.

Add the place values

The other bits keep their normal positive values.

−128 + 16 + 8 + 4 + 1 = −99

Answer

N = −99
6.Number systems

Answer: b = 12 bit

Positional number systems: each digit is worth its value times a power of the base. In binary the places are worth 1, 2, 4, 8, 16, …; in hexadecimal 1, 16, 256, …, with A–F standing for 10–15. In 8-bit two's complement the leftmost bit is worth −128 instead of +128, which is how negative numbers are stored.

Powers of two

211 = 2048 < 2489
212 = 4096 ≥ 2489

Answer

b = 12

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