Differential Equations: practice problems and exam questions

First-order differential equations and their applications: growth and decay, Newton’s law of cooling, mixing problems and linear equations with an integrating factor, plus Euler’s and Heun’s methods for equations without a formula solution.

Cram pack (PDF)Formula sheets, method steps and practice problems with full solutions, ready to print.

Topics in this course

  1. Differential equationsexponential growth and decay · Newton's law of cooling · first-order linearcalculations
  2. Integralspolynomials · exponentials, logs and substitution · areas between curvescalculations
  3. Derivativespower rule · chain and product rules · tangents and extremacalculations
  4. Numerical methodsroots and interpolation · trapezoid and Simpson rules · Euler, Heun and Runge–Kuttacalculations

Exam tips for Differential Equations

  • Identify the type first: separable, linear, or a standard model such as growth or cooling.
  • Use the initial condition to find the constant at the end.
  • Check the answer by substituting it back into the equation.

Worked examples

Differential equationsEasy
rr² + br + c?

For the equation y″ + 4y′ + 3y = 0, find the root r of the characteristic equation that is closest to zero. It sets how slowly the solution dies out.

y″ + 4y′ + 3y = 0

Find r

Show hints
  1. Substitute y = ert.
  2. r² + 4r + 3 = 0.
  3. Factor it or use the quadratic formula.
Show the answer and the step-by-step solution

Second-order linear equations: for y″ + b·y′ + c·y = 0 try y = ert: this gives the characteristic equation r² + b·r + c = 0. Two real roots r₁ ≠ r₂ give y = A·er₁t + B·er₂t (overdamped); a double root r gives y = (A + Bt)·ert (critically damped); complex roots −α ± jω give y = e−αt(A cos ωt + B sin ωt) (underdamped, oscillating). The initial values y(0) and y′(0) fix A and B. Written as y″ + 2ζωny′ + ωn²y = 0, ωn is the natural frequency and ζ the damping ratio: ζ < 1 oscillates. With a constant input, y″ + by′ + cy = c·K, the solution is the steady value K plus the free response.

Characteristic equation

r² + 4r + 3 = (r + 1)(r + 3) = 0

Roots

r = −1, r = −3
closest to zero: r = −1

Answer

r = −1

The general solution is y = A·e−1t + B·e−3t.

IntegralsMedium
xy2y = x·cos x

Evaluate I = ∫₀2 x·cos x dx (x in radians).

∫₀2 x·cos x dx

Find I

Show hints
  1. Take u = x and dv = cos x dx.
  2. v = sin x.
  3. ∫x cos x dx = x sin x + cos x.
Show the answer and the step-by-step solution

Integration by parts: ∫u·dv = u·v − ∫v·du, from the product rule. Choose u as the factor that gets simpler when you differentiate it (a power of x, or ln x), and dv as the factor you can integrate (eˣ, sin x, cos x, or x when u = ln x). For a definite integral, evaluate u·v at both limits: ∫ₐᵇ u dv = [u·v]ₐᵇ − ∫ₐᵇ v du. A factor x² needs two rounds.

Choose u and dv

u = x, du = dx; dv = cos x dx, v = sin x

Antiderivative

∫x cos x dx = x sin x − ∫sin x dx = x sin x + cos x

Limits

(2·sin 2 + cos 2) − (0 + 1) = 0.4024

Answer

I = 0.4024

How practising works

  • “Practise this course” mixes problems from all its topics, like a real exam.
  • Every problem has new values, so you learn the method instead of an answer.
  • Stuck? Open a small hint first, and the full explanation only when you need it.
  • Mock exams are timed and have no hints, and you get your score and a full review at the end.

Calculators for this course

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