Decide which form suits the operation: rectangular a + jb for adding and subtracting, polar r∠θ for multiplying, dividing, powers and roots.
Multiply out with j² = −1; divide by multiplying the top and bottom by the conjugate of the denominator.
Convert with r = √(a² + b²) and θ from a sketch of the point (check the quadrant), and back with a = r cos θ, b = r sin θ.
For powers use De Moivre, (r∠θ)ⁿ = rⁿ∠nθ; for zⁿ = R∠φ list all n roots R1/n∠((φ + 360°k)/n).
Differential equations
Exponential growth/decay
dy/dt = ky → y = y0ekt
Half-life
k = ln 2 / t½
Newton's law of cooling
T(t) = Ta + (T0 − Ta)e−kt
Integrating factor
y′ + p(x)y = q(x): μ = e∫p dx, (μy)′ = μq
Mixing tank
dm/dt = r·c − (r/V)·m
Matrices & determinants
2×2 determinant
det = ad − bc
2×2 inverse
A⁻¹ = (1/det)·[d −b; −c a]
Product
(AB)ij = Σk AikBkj
Eigenvalues
det(A − λI) = 0
Cramer’s rule
xi = det(Ai)/det(A)
Vectors: dot & cross product
Magnitude
|a| = √(ax² + ay² + az²)
Unit vector
û = a/|a|
Components from an angle
Fx = F·cos θ, Fy = F·sin θ
Dot product
a·b = axbx + ayby + azbz = |a||b|cos θ
Scalar projection of a onto b
a·b/|b|
Work
W = F·d
Cross product
a × b = (aybz − azby, azbx − axbz, axby − aybx)
Areas
parallelogram |a × b|, triangle ½|a × b|
Moment about O
MO = r × F, r = A − O
Volume of a parallelepiped
V = |a·(b × c)|
Method
Write every vector in components; for a force given by a magnitude and an angle, use F·cos θ and F·sin θ.
For lengths and directions use the magnitude √(x² + y² + z²) and the unit vector a/|a|.
Use the dot product for angles, projections, perpendicularity and work: a·b = |a||b|cos θ.
Use the cross product for perpendicular vectors, areas and moments: write the three components carefully, keeping the order a × b.
Probability
Complement
P(not A) = 1 − P(A)
Addition rule
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Independent events
P(A ∩ B) = P(A)·P(B)
Conditional probability
P(A|B) = P(A ∩ B)/P(B)
Binomial
P(X = k) = C(n,k)·pk(1 − p)n−k
Descriptive statistics
Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ
Normal distribution
z-score
z = (x − μ)/σ
Below x
P(X < x) = Φ(z)
Above x
P(X > x) = 1 − Φ(z)
Between
Φ(z2) − Φ(z1)
Percentile
x = μ + z·σ
Method
Convert the value to a z-score: z = (x − μ)/σ.
Look up Φ(z), the area to the left of z.
For the area to the right use 1 − Φ(z); for an interval subtract the two left areas.
For a percentile, work backwards: find z for the area, then x = μ + z·σ.
2Practice problems
1.LimitsMedium
Find the limit L = limx→∞ (1 − 2/x)3x. Give a decimal value.
f(x) = (1 − 2/x)3xx → ∞
L =
2.LimitsHard
Find the limit L = limx→0 ln(1 + 5x)/sin(x), with x in radians.
f(x) = ln(1 + 5x)/sin(x)x → 0
L =
3.DerivativesMedium
Let f(x) = (4x − 3)3. Find f′(0).
f(x) = (4x − 3)3x = 0
f′(0) =
4.DerivativesHard
The tangent line to f(x) = 3x2 − 5x − 5 at x = −1 crosses the y-axis at y = b. Find b.
f(x) = 3x2 − 5x − 5x = −1
b =
5.IntegralsMedium
Evaluate I = ∫₀2 x·cos x dx (x in radians).
∫₀2 x·cos x dx
I =
6.IntegralsHard
The region between the line y = 2x and the parabola y = x² is rotated about the x-axis. Find the volume V of the solid.
y = 2xy = x²
V =
7.Complex numbersMedium
Write z = 12∠160° in rectangular form a + jb and give the real part a.
r = 12θ = 160°
a =
8.Complex numbersHard
The roots of zⁿ = w with n = 6 and w = 64∠0° are zk = R1/n∠((φ + 360°·k)/n), k = 0, 1, …, 5. Find the imaginary part of z₁.
w = 64∠0°n = 6k = 1
Im(z₁) =
9.Differential equationsMedium
Solve y″ + 8y′ + 16y = 0 with y(0) = 1 and y′(0) = 2. Find y(1.5).
y″ + 8y′ + 16y = 0y(0) = 1y′(0) = 2
y(1.5) =
10.Differential equationsHard
Solve the initial value problem y′ + 2y/x = 2x2 for x > 0, with y(1) = 3. Find y(3).
y′ + 2y/x = 2x2y(1) = 3
y(3) =
11.Matrices & determinantsMedium
Find the determinant det A of the 3×3 matrix A shown.
A = [−1 −3 −1; 1 2 −5; 5 0 1]
det A =
12.Matrices & determinantsHard
Solve the system 5x + 6y = 7 and −3x − 2y = 11. Find x.
5x + 6y = 7−3x − 2y = 11
x =
13.Vectors: dot & cross productMedium
Find the dot product a·b of a = (3, 1, −7) and b = (−7, 1, 7).
a = (3, 1, −7)b = (−7, 1, 7)
a·b =
14.Vectors: dot & cross productHard
For a = (3, 4, −6) and b = (−2, 3, −5), find the x-component (a × b)x of the cross product a × b.
a = (3, 4, −6)b = (−2, 3, −5)
(a × b)x =
15.ProbabilityMedium
A fair die is rolled 7 times. What is the probability P of getting at least one six?
n = 7
P =
16.ProbabilityHard
X has the distribution shown, and Y = −2X + 10. Find the standard deviation σY of Y.
x: 0, 1, 2p(x): 0.35, 0.3, 0.35Y = −2X + 10
σY =
17.Descriptive statisticsMedium
Find the sample standard deviation s of the data: 24, 28, 40, 11, 37.
n = 5
s =
18.Descriptive statisticsHard
Exam scores are normally distributed with mean 100 and standard deviation 12. Find the z-score z of a score of 88.
μ = 100σ = 12x = 88
z =
19.Normal distributionMedium
The heights of adult men are normally distributed with mean 178 cm and standard deviation 7 cm. What fraction lies between 167.5 and 190.95 cm? Give P as a decimal.
μ = 178σ = 7x1 = 167.5x2 = 190.95
P =
20.Normal distributionHard
Hole diameters D are normal with mean 25.03 mm and standard deviation 0.01 mm. Shaft diameters d are independent and normal with mean 25 mm and standard deviation 0.01 mm. A randomly chosen shaft fits when D − d > 0. Find the probability P that it fits. Round z to two decimals.
hole: μ = 25.03 mm, σ = 0.01 mmshaft: μ = 25 mm, σ = 0.01 mm
P =
3Solutions
1.Limits
Answer: L = 0.002479
Limits: first try direct substitution. If it gives 0/0, simplify first: factor and cancel the common factor, or multiply by the conjugate. As x → ∞, divide numerator and denominator by the highest power of x. L'Hôpital's rule: if f/g gives 0/0 or ∞/∞, then lim f/g = lim f′/g′, differentiating the numerator and the denominator separately (not with the quotient rule).
Take the logarithm
ln L = limx→∞ 3·x·ln(1 − 2/x)
Evaluate
ln(1 + u)/u → 1 as u → 0, so x·ln(1 + a/x) → a.
ln L = 3·(−2) = −6
Undo the logarithm
L = e−6 = 0.002479
Answer
L = 0.002479
2.Limits
Answer: L = 5
Limits: first try direct substitution. If it gives 0/0, simplify first: factor and cancel the common factor, or multiply by the conjugate. As x → ∞, divide numerator and denominator by the highest power of x. L'Hôpital's rule: if f/g gives 0/0 or ∞/∞, then lim f/g = lim f′/g′, differentiating the numerator and the denominator separately (not with the quotient rule).
L'Hôpital's rule
L = limx→0 [5/(1 + 5x)]/[cos x]
Substitute x = 0
L = 5/1 = 5
Answer
L = 5
3.Derivatives
Answer: f′(0) = 108
Differentiation: the derivative f′(x) is the slope of the graph at x. Power rule: (xⁿ)′ = n·xⁿ⁻¹. Product rule: (uv)′ = u′v + uv′. Chain rule: (f(g(x)))′ = f′(g(x))·g′(x). Where f′(x) = 0 the graph has a horizontal tangent: a maximum, minimum or saddle point.
Chain rule
f′(x) = 3·(4x − 3)2·4
Substitute
f′(0) = 3·(−3)2·4 = 108
Answer
f′(0) = 108
4.Derivatives
Answer: b = −8
Differentiation: the derivative f′(x) is the slope of the graph at x. Power rule: (xⁿ)′ = n·xⁿ⁻¹. Product rule: (uv)′ = u′v + uv′. Chain rule: (f(g(x)))′ = f′(g(x))·g′(x). Where f′(x) = 0 the graph has a horizontal tangent: a maximum, minimum or saddle point.
Point and slope
f(−1) = 3
f′(x) = 6x − 5 → f′(−1) = −11
Tangent line at x = 0
b = f(x₀) − f′(x₀)·x₀ = 3 − (−11)·(−1) = −8
Answer
b = −8
5.Integrals
Answer: I = 0.4024
Integration by parts: ∫u·dv = u·v − ∫v·du, from the product rule. Choose u as the factor that gets simpler when you differentiate it (a power of x, or ln x), and dv as the factor you can integrate (eˣ, sin x, cos x, or x when u = ln x). For a definite integral, evaluate u·v at both limits: ∫ₐᵇ u dv = [u·v]ₐᵇ − ∫ₐᵇ v du. A factor x² needs two rounds.
Choose u and dv
u = x, du = dx; dv = cos x dx, v = sin x
Antiderivative
∫x cos x dx = x sin x − ∫sin x dx = x sin x + cos x
Limits
(2·sin 2 + cos 2) − (0 + 1) = 0.4024
Answer
I = 0.4024
6.Integrals
Answer: V = 13.4
Volumes of revolution: rotating the region under y = f(x) from x = a to x = b about the x-axis makes a solid whose cross-section at x is a disc of radius f(x). Adding the discs gives V = π∫ₐᵇ f(x)² dx. When the region lies between an outer curve R(x) and an inner curve r(x), each slice is a washer: V = π∫ₐᵇ (R(x)² − r(x)²) dx. Square the radii before you subtract them.
Intersection points
2x = 1x² → x = 0, x = 2
Washer method
V = π∫₀2 ((2x)² − (1x²)²) dx
Integrate
V = π(4·2³/3 − 1·2⁵/5) = π·4.267 = 13.4
Answer
V = 13.4
7.Complex numbers
Answer: a = −11.28
Polar form: z = r∠θ = r(cos θ + j sin θ) = r·ejθ, with r = |z| and θ = arg z. Back to rectangular form: a = r cos θ, b = r sin θ. The argument needs the quadrant: θ = atan(b/a) only when a > 0; for a < 0 add or subtract 180°. In polar form multiplication is easy: multiply the moduli and add the arguments; for division divide the moduli and subtract the arguments.
Components
a = 12·cos(160°) = −11.28
b = 12·sin(160°) = 4.104
Rectangular form
z = −11.28 + j4.104
a = −11.28
Answer
a = −11.28
8.Complex numbers
Answer: Im(z₁) = 1.732
De Moivre and roots: (r∠θ)ⁿ = rⁿ∠nθ. The equation zⁿ = R∠φ has exactly n roots, all with modulus R1/n, at the arguments (φ + 360°·k)/n for k = 0, 1, …, n − 1: they lie evenly spaced on a circle, 360°/n apart. A quadratic z² + pz + q = 0 with p² < 4q has the complex roots z = −p/2 ± j√(q − p²/4); a polynomial with real coefficients always has its complex roots in conjugate pairs a ± jb.
Modulus of the roots
641/6 = 2
Argument of the root
θ₁ = (0° + 360°·1)/6 = 60°
Rectangular form
z₁ = 2·(cos 60° + j sin 60°) = 1 + j1.732
Im(z₁) = 1.732
Answer
Im(z₁) = 1.732
The 6 roots lie on the circle of radius 2, 60° apart.
9.Differential equations
Answer: y(1.5) = 0.02479
Second-order linear equations: for y″ + b·y′ + c·y = 0 try y = ert: this gives the characteristic equation r² + b·r + c = 0. Two real roots r₁ ≠ r₂ give y = A·er₁t + B·er₂t (overdamped); a double root r gives y = (A + Bt)·ert (critically damped); complex roots −α ± jω give y = e−αt(A cos ωt + B sin ωt) (underdamped, oscillating). The initial values y(0) and y′(0) fix A and B. Written as y″ + 2ζωny′ + ωn²y = 0, ωn is the natural frequency and ζ the damping ratio: ζ < 1 oscillates. With a constant input, y″ + by′ + cy = c·K, the solution is the steady value K plus the free response.
Double root
(r + 4)² = 0 → r = −4
Constants
A = y(0) = 1
y′(0) = B − 4A → B = 2 + 4 = 6
Evaluate
y(1.5) = (1 + 6·1.5)·e−6 = 0.02479
Answer
y(1.5) = 0.02479
10.Differential equations
Answer: y(3) = 11.09
First-order differential equations: dy/dt = k·y has the solution y = y₀·ekt (growth for k > 0, decay for k < 0); a half-life T gives k = ln 2/T. Newton's law of cooling, dT/dt = −k·(T − Tₐ), gives T(t) = Tₐ + (T₀ − Tₐ)·e−kt. A linear equation y′ + p(x)·y = q(x) is solved with the integrating factor μ = e∫p dx: (μy)′ = μq, so μy = ∫μq dx + C.
Integrating factor
μ = e∫2/x dx = x2
Integrate
(x2y)′ = 2x4 → x2y = 2x5/5 + C
Initial condition
3 = 2/5 + C → C = 2.6
Evaluate
y(3) = (2·35/5 + 2.6)/32 = 11.09
Answer
y(3) = 11.09
11.Matrices & determinants
Answer: det A = 86
Matrices: the determinant of a 2×2 matrix is ad − bc. For 3×3, expand along a row: each entry times the determinant of the 2×2 matrix left after removing its row and column, with alternating signs + − +. Eigenvalues λ solve det(A − λI) = 0; for 2×2 that is λ² − (trace)·λ + det = 0.
2×2 minors of the first row
M₁₁ = 2, M₁₂ = 26, M₁₃ = −10
Cofactor expansion
det A = (−1)·2 − (−3)·26 + (−1)·(−10) = 86
Answer
det A = 86
12.Matrices & determinants
Answer: x = −10
Matrices: the determinant of a 2×2 matrix is ad − bc. For 3×3, expand along a row: each entry times the determinant of the 2×2 matrix left after removing its row and column, with alternating signs + − +. Eigenvalues λ solve det(A − λI) = 0; for 2×2 that is λ² − (trace)·λ + det = 0.
Determinant of the coefficient matrix
det A = 5·(−2) − 6·(−3) = 8
Replace the x column
det Aₓ = 7·(−2) − 6·11 = −80
x = −80/8 = −10
Answer
x = −10
y = 9.5
13.Vectors: dot & cross product
Answer: a·b = −69
Dot product:a·b = axbx + ayby + azbz = |a|·|b|·cos θ, a scalar. It gives the angle between two vectors, cos θ = a·b/(|a|·|b|), and it is zero when they are perpendicular. The scalar projection of a onto b is a·b/|b|, and a constant force F moving through a displacement d does work W = F·d.
Negative: the angle between the vectors is more than 90°.
14.Vectors: dot & cross product
Answer: (a × b)x = −2
Cross product:a × b = (aybz − azby, azbx − axbz, axby − aybx) is perpendicular to both vectors, and |a × b| = |a|·|b|·sin θ is the area of the parallelogram they span (the triangle has half of it). Order matters: b × a = −(a × b). The moment of a force F applied at point A about point O is MO = r × F, with r = A − O.
Cross product, component by component
(a × b)x = aybz − azby = 4·(−5) − (−6)·3 = −2
(a × b)y = azbx − axbz = (−6)·(−2) − 3·(−5) = 27
(a × b)z = axby − aybx = 3·3 − 4·(−2) = 17
Requested component
(a × b)x = −2
Answer
(a × b)x = −2
Check: a × b is perpendicular to both vectors, so its dot product with a and with b is zero.
15.Probability
Answer: P = 0.7209
Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.
Complement
P(no six) = (5/6)7 = 0.2791
P = 1 − 0.2791 = 0.7209
Answer
P = 0.7209
16.Probability
Answer: σY = 1.673
Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.
Spread of X
μ = 1, Var(X) = 0.7, σX = 0.8367
Linear change
σY = |−2|·0.8367 = 1.673
Answer
σY = 1.673
The mean does move: E(Y) = −2·1 + 10 = 8.
17.Descriptive statistics
Answer: s = 11.51
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Mean
x̄ = 140/5 = 28
Squared deviations
Σ(x − x̄)² = (−4)² + 0² + 12² + (−17)² + 9² = 530
Standard deviation
s = √(530/4) = 11.51
Answer
s = 11.51
18.Descriptive statistics
Answer: z = −1
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Standardise
z = (88 − 100)/12 = −1
Answer
z = −1
19.Normal distribution
Answer: P = 0.901
Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.
z-scores
z₁ = (167.5 − 178)/7 = −1.5
z₂ = (190.95 − 178)/7 = 1.85
Area between
P = Φ(1.85) − Φ(−1.5) = 0.9678 − 0.06681 = 0.901
Answer
P = 0.901
20.Normal distribution
Answer: P = 0.983
Sums and differences of normal variables: if X and Y are independent and normal, X + Y and X − Y are normal too. Means add or subtract: E(X ± Y) = μX ± μY. Variances always add, also for a difference: Var(X ± Y) = σX² + σY², so σ = √(σX² + σY²). Standard deviations never add directly. The total of n independent items with the same distribution has mean n·μ and standard deviation σ·√n. Then standardise as usual: z = (x − mean)/σ and read Φ(z).