Evidence-Based Practice: cram pack

Formula sheets, the key method steps for every topic and 8 practice problems, with full solutions at the back.

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1Formulas and methods

Evidence-based practice statistics

Sensitivity and specificity
Se = a/(a + c), Sp = d/(b + d)
Predictive values
PPV = a/(a + b), NPV = d/(c + d)
Accuracy
(a + d)/n
Likelihood ratios
LR+ = Se/(1 − Sp), LR− = (1 − Se)/Sp
PPV at prevalence p
Se·p / (Se·p + (1 − Sp)(1 − p))
Odds
odds = p/(1 − p); p = odds/(1 + odds); post-test odds = pre-test odds × LR
Risk measures
RR = EER/CER, ARR = CER − EER, RRR = ARR/CER
Number needed to treat
NNT = 1/ARR, rounded up; NNH = 1/(EER − CER)
Odds ratio
OR = ad/(bc)
Incidence rate
new cases / person-time

Method

  1. Draw the 2 × 2 table and label a, b, c and d before you calculate.
  2. Read sensitivity and specificity down the columns, predictive values along the rows.
  3. For another prevalence, imagine 10 000 people and fill the table with Se, Sp and the prevalence.
  4. For a likelihood ratio, convert the probability to odds, multiply, and convert back.
  5. For a trial, find EER and CER first; then RR = EER/CER, ARR = CER − EER and NNT = 1/ARR rounded up.

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

2Practice problems

1.Evidence-based practice statisticsMedium
Se83%Sp65%LR+ = ?

Practice exercise (made-up values, not clinical guidance). A test has a sensitivity of 83% and a specificity of 65%. Find the positive likelihood ratio LR+. Round to two decimal places.

Se = 83%Sp = 65%
LR+ =
2.Evidence-based practice statisticsHard
testdisease presentdisease absenttotalpositivenegative?total10 000

Practice exercise (made-up values, not clinical guidance). 10 000 people are screened with a test of sensitivity 88% and specificity 99%. The prevalence of the disease is 4%. How many people with the disease are missed by the test (false negatives, FN)?

N = 10 000p = 4%Se = 88%Sp = 99%
FN =
3.Descriptive statisticsMedium
25303540455055

Find the sample standard deviation s of the data: 58, 25, 28, 26, 44, 50, 37.

n = 7
s =
4.Descriptive statisticsHard
z −2−1012

A quantity is normally distributed with mean 50 and standard deviation 15. What proportion P of values is below 65?

μ = 50σ = 15x = 65
P =
5.Confidence intervalsMedium
μ₁ − μ₂0LUx̄₁ − x̄₂E = ?99%

The battery life of two phone models is compared. Model 1: 50 phones, mean 95.5 h, known standard deviation 14 h. Model 2: 80 phones, mean 107 h, known standard deviation 9 h. Find the margin of error E of the 99% confidence interval for μ₁ − μ₂.

n₁ = 50x̄₁ = 95.5 hσ₁ = 14 hn₂ = 80x̄₂ = 107 hσ₂ = 9 h99%
E = h
6.Confidence intervalsHard
σ = 22, n = ?x̄ − Ex̄ + Ex̄E = 2.599%

The population standard deviation is 22. How large a sample n do you need so that a 99% confidence interval for the mean has a margin of error of at most 2.5?

σ = 22E = 2.599%
n =
7.Hypothesis tests & confidence intervalsMedium
2.28p = ?

The mean of a population is claimed to be 80; the population standard deviation is known to be 48. A random sample of 144 observations has a mean of 89.12. Test H₀: μ = 80 against H₁: μ > 80. Find the p-value p.

μ₀ = 80σ = 48n = 144x̄ = 89.12H₁: μ > μ₀
p =
8.Hypothesis tests & confidence intervalsHard
−1.961.96z = ?

In a trial, 70 of 100 patients on treatment A recover, and 183 of 300 patients on treatment B. Using the pooled proportion, find the test statistic z for H₀: p₁ = p₂.

x₁ = 70n₁ = 100x₂ = 183n₂ = 300
z =

3Solutions

1.Evidence-based practice statistics

Answer: LR+ = 2.37

Likelihood ratios and risk measures: LR+ = sensitivity/(1 − specificity), LR− = (1 − sensitivity)/specificity. In a trial, EER and CER are the event rates with and without treatment: RR = EER/CER, ARR = CER − EER, RRR = ARR/CER and NNT = 1/ARR, rounded up. In a case-control study only the odds ratio OR = ad/(bc) can be used. An incidence rate = new cases/person-time.

Positive likelihood ratio

LR+ = 0.83/(1 − 0.65) = 2.371 ≈ 2.37

Answer

LR+ = 2.37
2.Evidence-based practice statistics

Answer: FN = 48

Predictive values depend on prevalence: PPV = Se·p/(Se·p + (1 − Sp)(1 − p)) and NPV = Sp(1 − p)/(Sp(1 − p) + (1 − Se)p). With likelihood ratios: pre-test odds = p/(1 − p), post-test odds = pre-test odds × LR, probability = odds/(1 + odds). For a population of N, true positives = N·p·Se and false positives = N·(1 − p)·(1 − Sp). NNT = 1/(CER × RRR), rounded up.

With and without the disease

10 000·0.04 = 400
10 000 − 400 = 9600

False negatives

FN = 400·0.12 = 48

Answer

FN = 48
3.Descriptive statistics

Answer: s = 12.87

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 268/7 = 38.29

Squared deviations

Σ(x − x̄)² = 19.71² + (−13.29)² + (−10.29)² + (−12.29)² + 5.714² + 11.71² + (−1.286)² = 993.4

Standard deviation

s = √(993.4/6) = 12.87

Answer

s = 12.87
4.Descriptive statistics

Answer: P = 0.8413

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = 1

Standard normal table

Φ(1) = 0.8413
P = 0.8413

Answer

P = 0.8413
5.Confidence intervals

Answer: E = 5.721 h

Interval for a difference: estimate ± critical value × standard error. For two independent means with known σ: SE = √(σ₁²/n₁ + σ₂²/n₂) and z. With equal unknown variances: pooled s_p and t with n₁ + n₂ − 2 degrees of freedom. For paired data, work with the differences: d̄ ± t·s_d/√n.

Point estimate

x̄₁ − x̄₂ = 95.5 − 107 = −11.5

Standard error

SE = √(14²/50 + 9²/80) = 2.221

Margin of error

E = 2.576·2.221 = 5.721

Answer

E = 5.721 h

The interval does not contain 0, so the means differ significantly.

6.Confidence intervals

Answer: n = 514

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Solve for n

n = (2.576·22/2.5)² = 513.9

Round up

A sample size is a whole number, and rounding down would make the margin too large.

n = 514

Answer

n = 514
7.Hypothesis tests & confidence intervals

Answer: p = 0.0113

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Test statistic

SE = σ/√n = 48/√144 = 4
z = (89.12 − 80)/4 = 2.28

Tail area

Φ(2.28) = 0.9887
1 − Φ(2.28) = 0.0113

p-value

p = 0.0113

Answer

p = 0.0113

p ≤ 0.05, so H₀ is rejected at the 5% level.

8.Hypothesis tests & confidence intervals

Answer: z = 1.617

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Sample proportions

p̂₁ = 70/100 = 0.7
p̂₂ = 183/300 = 0.61
p̂ = 253/400 = 0.6325

Standard error under H₀

SE = √(0.6325·0.3675·(1/100 + 1/300)) = 0.05567

Test statistic

z = (0.7 − 0.61)/0.05567 = 1.617

Answer

z = 1.617

|z| < 1.96, so H₀ is not rejected at the 5% level (two-sided).

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