Evidence-Based Practice: cram pack

Formula sheets, the key method steps for every topic and 8 practice problems, with full solutions at the back.

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1Formulas and methods

Evidence-based practice statistics

Sensitivity and specificity
Se = a/(a + c), Sp = d/(b + d)
Predictive values
PPV = a/(a + b), NPV = d/(c + d)
Accuracy
(a + d)/n
Likelihood ratios
LR+ = Se/(1 − Sp), LR− = (1 − Se)/Sp
PPV at prevalence p
Se·p / (Se·p + (1 − Sp)(1 − p))
Odds
odds = p/(1 − p); p = odds/(1 + odds); post-test odds = pre-test odds × LR
Risk measures
RR = EER/CER, ARR = CER − EER, RRR = ARR/CER
Number needed to treat
NNT = 1/ARR, rounded up; NNH = 1/(EER − CER)
Odds ratio
OR = ad/(bc)
Incidence rate
new cases / person-time

Method

  1. Draw the 2 × 2 table and label a, b, c and d before you calculate.
  2. Read sensitivity and specificity down the columns, predictive values along the rows.
  3. For another prevalence, imagine 10 000 people and fill the table with Se, Sp and the prevalence.
  4. For a likelihood ratio, convert the probability to odds, multiply, and convert back.
  5. For a trial, find EER and CER first; then RR = EER/CER, ARR = CER − EER and NNT = 1/ARR rounded up.

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

2Practice problems

1.Evidence-based practice statisticsMedium
testdisease presentdisease absenttotalpositive46277323abnegative2415731597cdtotal7018501920

Practice exercise (made-up values, not clinical guidance). A new test was compared with the reference standard in a study (see the 2 × 2 table). Find the positive likelihood ratio LR+. Round to two decimal places.

a = 46b = 277c = 24d = 1573
LR+ =
2.Evidence-based practice statisticsHard
pre-test25%post-test?p′LR−

Practice exercise (made-up values, not clinical guidance). A patient has a pre-test probability of 25% for a disease. A test with sensitivity 62% and specificity 78% comes back negative. Find the post-test probability p′ of the disease as a percentage. Round to one decimal place.

pre-test 25%Se = 62%Sp = 78%negative
p′ = %
3.Descriptive statisticsMedium
152025303540455055

Find the sample standard deviation s of the data: 42, 13, 52, 24, 51, 55, 16.

n = 7
s =
4.Descriptive statisticsHard
z −2−1012

Exam scores are normally distributed with mean 50 and standard deviation 8. Find the z-score z of a score of 66.

μ = 50σ = 8x = 66
z =
5.Confidence intervalsMedium
x̄E₁ = 2.399%, n = 36x̄E₂ = ?95%, n = 324

A 99% confidence interval for a mean, based on 36 observations and a known σ, has a margin of error of 2.3. What is the margin of error E₂ of a 95% interval based on 324 observations?

99%n₁ = 36E₁ = 2.395%n₂ = 324
E₂ =
6.Confidence intervalsHard
σ = 32, n = ?x̄ − Ex̄ + Ex̄E = 499%

The population standard deviation is 32. How large a sample n do you need so that a 99% confidence interval for the mean has a margin of error of at most 4?

σ = 32E = 499%
n =
7.Hypothesis tests & confidence intervalsMedium
−2.2622.262t = ?df = 9

10 employees take a typing test before and after a training course. For each person the difference d = after − before (words per minute) is recorded. The mean difference is 6.24 and the standard deviation of the differences is 9.4. Find the paired test statistic t for H₀: μd = 0.

n = 10d̄ = 6.24sd = 9.4
t =
8.Hypothesis tests & confidence intervalsHard
σ = 10, n = ?x̄ − Ex̄ + Ex̄E = 395%

How large must a sample be so that the 95% confidence interval for a mean has a margin of error of at most 3? The standard deviation is 10. Find the smallest sample size n.

σ = 10E = 395%
n =

3Solutions

1.Evidence-based practice statistics

Answer: LR+ = 4.39

Likelihood ratios and risk measures: LR+ = sensitivity/(1 − specificity), LR− = (1 − sensitivity)/specificity. In a trial, EER and CER are the event rates with and without treatment: RR = EER/CER, ARR = CER − EER, RRR = ARR/CER and NNT = 1/ARR, rounded up. In a case-control study only the odds ratio OR = ad/(bc) can be used. An incidence rate = new cases/person-time.

Sensitivity and specificity

Se = 46/70 = 0.6571
Sp = 1573/1850 = 0.8503

Positive likelihood ratio

LR+ = 0.6571/(1 − 0.8503) = 4.389 ≈ 4.39

Answer

LR+ = 4.39
2.Evidence-based practice statistics

Answer: p′ = 14 %

Predictive values depend on prevalence: PPV = Se·p/(Se·p + (1 − Sp)(1 − p)) and NPV = Sp(1 − p)/(Sp(1 − p) + (1 − Se)p). With likelihood ratios: pre-test odds = p/(1 − p), post-test odds = pre-test odds × LR, probability = odds/(1 + odds). For a population of N, true positives = N·p·Se and false positives = N·(1 − p)·(1 − Sp). NNT = 1/(CER × RRR), rounded up.

Likelihood ratio

LR− = (1 − 0.62)/0.78 = 0.4872

Pre-test odds

0.25/(1 − 0.25) = 0.3333

Post-test odds

0.3333·0.4872 = 0.1624

Post-test probability

p′ = 0.1624/(1 + 0.1624) = 0.1397 ≈ 14%

Answer

p′ = 14%
3.Descriptive statistics

Answer: s = 18.03

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 253/7 = 36.14

Squared deviations

Σ(x − x̄)² = 5.857² + (−23.14)² + 15.86² + (−12.14)² + 14.86² + 18.86² + (−20.14)² = 1951

Standard deviation

s = √(1951/6) = 18.03

Answer

s = 18.03
4.Descriptive statistics

Answer: z = 2

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = (66 − 50)/8 = 2

Answer

z = 2
5.Confidence intervals

Answer: E₂ = 0.5833

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Ratio of margins

E₂/E₁ = (1.96/2.576)·√(36/324) = 0.2536

New margin

E₂ = 2.3·0.2536 = 0.5833

Answer

E₂ = 0.5833
6.Confidence intervals

Answer: n = 425

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Solve for n

n = (2.576·32/4)² = 424.7

Round up

A sample size is a whole number, and rounding down would make the margin too large.

n = 425

Answer

n = 425
7.Hypothesis tests & confidence intervals

Answer: t = 2.099

Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).

Standard error of the mean difference

SE = 9.4/√10 = 2.973

Test statistic

t = 6.24/2.973 = 2.099

Answer

t = 2.099

With df = 9, the two-sided 5% critical value is 2.262; |t| is smaller, so H₀ is not rejected.

8.Hypothesis tests & confidence intervals

Answer: n = 43

Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).

Solve for n

n = (1.96·10/3)² = 42.68

Round up

n = 43

Answer

n = 43

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