Evidence-Based Practice: cram pack

Formula sheets, the key method steps for every topic and 8 practice problems, with full solutions at the back.

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1Formulas and methods

Evidence-based practice statistics

Sensitivity and specificity
Se = a/(a + c), Sp = d/(b + d)
Predictive values
PPV = a/(a + b), NPV = d/(c + d)
Accuracy
(a + d)/n
Likelihood ratios
LR+ = Se/(1 − Sp), LR− = (1 − Se)/Sp
PPV at prevalence p
Se·p / (Se·p + (1 − Sp)(1 − p))
Odds
odds = p/(1 − p); p = odds/(1 + odds); post-test odds = pre-test odds × LR
Risk measures
RR = EER/CER, ARR = CER − EER, RRR = ARR/CER
Number needed to treat
NNT = 1/ARR, rounded up; NNH = 1/(EER − CER)
Odds ratio
OR = ad/(bc)
Incidence rate
new cases / person-time

Method

  1. Draw the 2 × 2 table and label a, b, c and d before you calculate.
  2. Read sensitivity and specificity down the columns, predictive values along the rows.
  3. For another prevalence, imagine 10 000 people and fill the table with Se, Sp and the prevalence.
  4. For a likelihood ratio, convert the probability to odds, multiply, and convert back.
  5. For a trial, find EER and CER first; then RR = EER/CER, ARR = CER − EER and NNT = 1/ARR rounded up.

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

2Practice problems

1.Evidence-based practice statisticsMedium
casescontrolsexposed300262abnot exposed100348cd

Practice exercise (made-up values, not clinical guidance). A case-control study compares 400 patients with a disease (cases) and 610 people without it (controls). The table shows how many in each group were exposed to a risk factor. Find the odds ratio OR for the exposure. Round to two decimal places.

a = 300b = 262c = 100d = 348
OR =
2.Evidence-based practice statisticsHard
p (%)PPV (%)1%PPV = ?100

Practice exercise (made-up values, not clinical guidance). A screening test has a sensitivity of 91% and a specificity of 85%. It is used in a population where the prevalence is 1%. Find the positive predictive value PPV as a percentage. Round to one decimal place.

Se = 91%Sp = 85%p = 1%
PPV = %
3.Descriptive statisticsMedium
3035404550

Find the sample standard deviation s of the data: 54, 26, 52, 39, 53.

n = 5
s =
4.Descriptive statisticsHard
z −2−1012

Exam scores are normally distributed with mean 100 and standard deviation 12. Find the z-score z of a score of 90.4.

μ = 100σ = 12x = 90.4
z =
5.Confidence intervalsMedium
μ₁ − μ₂0L = ?Ux̄₁ − x̄₂E99%

The battery life of two phone models is compared. Model 1: 30 phones, mean 144 h, known standard deviation 4 h. Model 2: 80 phones, mean 136.5 h, known standard deviation 11 h. Find the lower limit of the 99% confidence interval for μ₁ − μ₂.

n₁ = 30x̄₁ = 144 hσ₁ = 4 hn₂ = 80x̄₂ = 136.5 hσ₂ = 11 h99%
lower limit = h
6.Confidence intervalsHard
μ₁ − μ₂, t(29) = 2.7560LU = ?x̄₁ − x̄₂E99%

Two fertilisers are tested. Plot group 1: 13 plots, mean yield 40.5 kg, standard deviation 1.5 kg. Plot group 2: 18 plots, mean 35 kg, standard deviation 2 kg. Assume equal variances (pooled t, df = n₁ + n₂ − 2). Find the upper limit of the 99% confidence interval for μ₁ − μ₂.

n₁ = 13x̄₁ = 40.5s₁ = 1.5n₂ = 18x̄₂ = 35s₂ = 299%t(29) = 2.756
upper limit = kg
7.Hypothesis tests & confidence intervalsMedium
−1.961.96z = ?

Two production lines make the same part. Line 1: a sample of 30 parts has mean length 70 mm, and the line's known standard deviation is 9 mm. Line 2: a sample of 30 parts has mean 76.7 mm, known standard deviation 9 mm. Find the test statistic z for H₀: μ₁ = μ₂, taking the difference as x̄₁ − x̄₂ (line 1 minus line 2).

n₁ = 30x̄₁ = 70 mmσ₁ = 9 mmn₂ = 30x̄₂ = 76.7 mmσ₂ = 9 mm
z =
8.Hypothesis tests & confidence intervalsHard
z −1.9601.96

A sample of 49 measurements has mean 101.6. The population standard deviation is 8. Find the lower limit L of the 95% confidence interval for the mean.

x̄ = 101.6σ = 8n = 4995%
L =

3Solutions

1.Evidence-based practice statistics

Answer: OR = 3.98

Likelihood ratios and risk measures: LR+ = sensitivity/(1 − specificity), LR− = (1 − sensitivity)/specificity. In a trial, EER and CER are the event rates with and without treatment: RR = EER/CER, ARR = CER − EER, RRR = ARR/CER and NNT = 1/ARR, rounded up. In a case-control study only the odds ratio OR = ad/(bc) can be used. An incidence rate = new cases/person-time.

Odds of exposure

cases: 300/100 = 3
controls: 262/348 = 0.7529

Odds ratio

OR = (300·348)/(262·100) = 3.985 ≈ 3.98

Answer

OR = 3.98

OR above 1: exposure is more common among the cases.

2.Evidence-based practice statistics

Answer: PPV = 5.8 %

Predictive values depend on prevalence: PPV = Se·p/(Se·p + (1 − Sp)(1 − p)) and NPV = Sp(1 − p)/(Sp(1 − p) + (1 − Se)p). With likelihood ratios: pre-test odds = p/(1 − p), post-test odds = pre-test odds × LR, probability = odds/(1 + odds). For a population of N, true positives = N·p·Se and false positives = N·(1 − p)·(1 − Sp). NNT = 1/(CER × RRR), rounded up.

True and false positives (per person)

Se·p = 0.91·0.01 = 0.0091
(1 − Sp)·(1 − p) = 0.15·0.99 = 0.1485

Positive predictive value

PPV = 0.0091/(0.0091 + 0.1485) = 0.05774 ≈ 5.8%

Answer

PPV = 5.8%

The lower the prevalence, the lower the PPV of the same test.

3.Descriptive statistics

Answer: s = 12.15

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 224/5 = 44.8

Squared deviations

Σ(x − x̄)² = 9.2² + (−18.8)² + 7.2² + (−5.8)² + 8.2² = 590.8

Standard deviation

s = √(590.8/4) = 12.15

Answer

s = 12.15
4.Descriptive statistics

Answer: z = −0.8

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = (90.4 − 100)/12 = −0.8

Answer

z = −0.8
5.Confidence intervals

Answer: lower limit = 3.815 h

Interval for a difference: estimate ± critical value × standard error. For two independent means with known σ: SE = √(σ₁²/n₁ + σ₂²/n₂) and z. With equal unknown variances: pooled s_p and t with n₁ + n₂ − 2 degrees of freedom. For paired data, work with the differences: d̄ ± t·s_d/√n.

Point estimate

x̄₁ − x̄₂ = 144 − 136.5 = 7.5

Standard error

SE = √(4²/30 + 11²/80) = 1.43

Margin of error

E = 2.576·1.43 = 3.685

Interval

7.5 ± 3.685 → [3.815, 11.18]

Answer

lower limit = 3.815 h

The interval does not contain 0, so the means differ significantly.

6.Confidence intervals

Answer: upper limit = 7.316 kg

Interval for a difference: estimate ± critical value × standard error. For two independent means with known σ: SE = √(σ₁²/n₁ + σ₂²/n₂) and z. With equal unknown variances: pooled s_p and t with n₁ + n₂ − 2 degrees of freedom. For paired data, work with the differences: d̄ ± t·s_d/√n.

Pooled standard deviation

sp² = (12·1.5² + 17·2²)/29 = 3.276
sp = 1.81

Margin of error

E = 2.756·1.81·√(1/13 + 1/18) = 1.816

Interval

5.5 ± 1.816 → [3.684, 7.316]

Answer

upper limit = 7.316 kg
7.Hypothesis tests & confidence intervals

Answer: z = −2.883

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Standard error of the difference

SE = √(9²/30 + 9²/30) = √5.4 = 2.324

Test statistic

z = (70 − 76.7)/2.324 = −2.883

Answer

z = −2.883

|z| > 1.96, so H₀ is rejected at the 5% level (two-sided).

8.Hypothesis tests & confidence intervals

Answer: L = 99.36

Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).

Margin of error

E = 1.96·8/√49 = 2.24

Interval limit

L = 101.6 − 2.24 = 99.36

Answer

L = 99.36

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