Evidence-Based Practice: cram pack

Formula sheets, the key method steps for every topic and 8 practice problems, with full solutions at the back.

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1Formulas and methods

Evidence-based practice statistics

Sensitivity and specificity
Se = a/(a + c), Sp = d/(b + d)
Predictive values
PPV = a/(a + b), NPV = d/(c + d)
Accuracy
(a + d)/n
Likelihood ratios
LR+ = Se/(1 − Sp), LR− = (1 − Se)/Sp
PPV at prevalence p
Se·p / (Se·p + (1 − Sp)(1 − p))
Odds
odds = p/(1 − p); p = odds/(1 + odds); post-test odds = pre-test odds × LR
Risk measures
RR = EER/CER, ARR = CER − EER, RRR = ARR/CER
Number needed to treat
NNT = 1/ARR, rounded up; NNH = 1/(EER − CER)
Odds ratio
OR = ad/(bc)
Incidence rate
new cases / person-time

Method

  1. Draw the 2 × 2 table and label a, b, c and d before you calculate.
  2. Read sensitivity and specificity down the columns, predictive values along the rows.
  3. For another prevalence, imagine 10 000 people and fill the table with Se, Sp and the prevalence.
  4. For a likelihood ratio, convert the probability to odds, multiply, and convert back.
  5. For a trial, find EER and CER first; then RR = EER/CER, ARR = CER − EER and NNT = 1/ARR rounded up.

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

2Practice problems

1.Evidence-based practice statisticsMedium
testdisease presentdisease absenttotalpositive353381734abnegative27849876cdtotal38012301610

Practice exercise (made-up values, not clinical guidance). A new test was compared with the reference standard in a study (see the 2 × 2 table). Find the negative likelihood ratio LR−. Round to two decimal places.

a = 353b = 381c = 27d = 849
LR− =
2.Evidence-based practice statisticsHard
p (%)NPV (%)20%NPV = ?100

Practice exercise (made-up values, not clinical guidance). A screening test has a sensitivity of 97% and a specificity of 97%. It is used in a population where the prevalence is 20%. Find the negative predictive value NPV as a percentage. Round to one decimal place.

Se = 97%Sp = 97%p = 20%
NPV = %
3.Descriptive statisticsMedium
152025303540455055

Find the sample standard deviation s of the data: 32, 56, 29, 30, 28, 13.

n = 6
s =
4.Descriptive statisticsHard
z −2−1012

Exam scores are normally distributed with mean 60 and standard deviation 12. Find the z-score z of a score of 67.2.

μ = 60σ = 12x = 67.2
z =
5.Confidence intervalsMedium
n = 21, s = 15LUx̄ = 28.5E = ?99%

A sample of 21 items has mean 28.5 and standard deviation s = 15. The population is roughly normal. Find the margin of error E of a 99% confidence interval for the mean.

n = 21x̄ = 28.5s = 1599%t(20) = 2.845
E =
6.Confidence intervalsHard
σ = 18, n = ?x̄ − Ex̄ + Ex̄E = 495%

The population standard deviation is 18. How large a sample n do you need so that a 95% confidence interval for the mean has a margin of error of at most 4?

σ = 18E = 495%
n =
7.Hypothesis tests & confidence intervalsMedium
1.08p = ?

The mean of a population is claimed to be 120; the population standard deviation is known to be 3. A random sample of 36 observations has a mean of 120.54. Test H₀: μ = 120 against H₁: μ > 120. Find the p-value p.

μ₀ = 120σ = 3n = 36x̄ = 120.54H₁: μ > μ₀
p =
8.Hypothesis tests & confidence intervalsHard
H₀H₁μ₀x̄cμ₀ + 1.5α = 0.05βσ = 4, power 80%, n = ?

A one-sided z test at α = 0.05 must detect a shift of the mean of 1.5 units with a power of 80%. The standard deviation is 4. Find the minimum sample size n.

α = 0.05power = 80%δ = 1.5σ = 4zα = 1.645zβ = 0.842
n =

3Solutions

1.Evidence-based practice statistics

Answer: LR− = 0.1

Likelihood ratios and risk measures: LR+ = sensitivity/(1 − specificity), LR− = (1 − sensitivity)/specificity. In a trial, EER and CER are the event rates with and without treatment: RR = EER/CER, ARR = CER − EER, RRR = ARR/CER and NNT = 1/ARR, rounded up. In a case-control study only the odds ratio OR = ad/(bc) can be used. An incidence rate = new cases/person-time.

Sensitivity and specificity

Se = 353/380 = 0.9289
Sp = 849/1230 = 0.6902

Negative likelihood ratio

LR− = (1 − 0.9289)/0.6902 = 0.1029 ≈ 0.1

Answer

LR− = 0.1
2.Evidence-based practice statistics

Answer: NPV = 99.2 %

Predictive values depend on prevalence: PPV = Se·p/(Se·p + (1 − Sp)(1 − p)) and NPV = Sp(1 − p)/(Sp(1 − p) + (1 − Se)p). With likelihood ratios: pre-test odds = p/(1 − p), post-test odds = pre-test odds × LR, probability = odds/(1 + odds). For a population of N, true positives = N·p·Se and false positives = N·(1 − p)·(1 − Sp). NNT = 1/(CER × RRR), rounded up.

True and false negatives (per person)

Sp·(1 − p) = 0.97·0.8 = 0.776
(1 − Se)·p = 0.03·0.2 = 0.006

Negative predictive value

NPV = 0.776/(0.776 + 0.006) = 0.9923 ≈ 99.2%

Answer

NPV = 99.2%
3.Descriptive statistics

Answer: s = 13.88

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 188/6 = 31.33

Squared deviations

Σ(x − x̄)² = 0.6667² + 24.67² + (−2.333)² + (−1.333)² + (−3.333)² + (−18.33)² = 963.3

Standard deviation

s = √(963.3/5) = 13.88

Answer

s = 13.88
4.Descriptive statistics

Answer: z = 0.6

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = (67.2 − 60)/12 = 0.6

Answer

z = 0.6
5.Confidence intervals

Answer: E = 9.312

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Critical value

df = n − 1 = 20, t = 2.845

Margin of error

E = 2.845·15/√21 = 9.312

Answer

E = 9.312
6.Confidence intervals

Answer: n = 78

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Solve for n

n = (1.96·18/4)² = 77.79

Round up

A sample size is a whole number, and rounding down would make the margin too large.

n = 78

Answer

n = 78
7.Hypothesis tests & confidence intervals

Answer: p = 0.1401

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Test statistic

SE = σ/√n = 3/√36 = 0.5
z = (120.54 − 120)/0.5 = 1.08

Tail area

Φ(1.08) = 0.8599
1 − Φ(1.08) = 0.1401

p-value

p = 0.1401

Answer

p = 0.1401

p > 0.05, so H₀ is not rejected at the 5% level.

8.Hypothesis tests & confidence intervals

Answer: n = 44

Sample size for a test: to detect a true shift δ with power 1 − β in a one-sided z test at level α, the standard error must satisfy δ = (z_α + z_β)·σ/√n, so n = ((z_α + z_β)·σ/δ)², rounded up.

Solve for n

n = ((1.645 + 0.842)·4/1.5)² = 43.98

Round up

n = 44

Answer

n = 44

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