Evidence-Based Practice: cram pack

Formula sheets, the key method steps for every topic and 8 practice problems, with full solutions at the back.

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1Formulas and methods

Evidence-based practice statistics

Sensitivity and specificity
Se = a/(a + c), Sp = d/(b + d)
Predictive values
PPV = a/(a + b), NPV = d/(c + d)
Accuracy
(a + d)/n
Likelihood ratios
LR+ = Se/(1 − Sp), LR− = (1 − Se)/Sp
PPV at prevalence p
Se·p / (Se·p + (1 − Sp)(1 − p))
Odds
odds = p/(1 − p); p = odds/(1 + odds); post-test odds = pre-test odds × LR
Risk measures
RR = EER/CER, ARR = CER − EER, RRR = ARR/CER
Number needed to treat
NNT = 1/ARR, rounded up; NNH = 1/(EER − CER)
Odds ratio
OR = ad/(bc)
Incidence rate
new cases / person-time

Method

  1. Draw the 2 × 2 table and label a, b, c and d before you calculate.
  2. Read sensitivity and specificity down the columns, predictive values along the rows.
  3. For another prevalence, imagine 10 000 people and fill the table with Se, Sp and the prevalence.
  4. For a likelihood ratio, convert the probability to odds, multiply, and convert back.
  5. For a trial, find EER and CER first; then RR = EER/CER, ARR = CER − EER and NNT = 1/ARR rounded up.

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

2Practice problems

1.Evidence-based practice statisticsMedium
casescontrolsexposed90310abnot exposed30310cd

Practice exercise (made-up values, not clinical guidance). A case-control study compares 120 patients with a disease (cases) and 620 people without it (controls). The table shows how many in each group were exposed to a risk factor. Find the odds ratio OR for the exposure. Round to two decimal places.

a = 90b = 310c = 30d = 310
OR =
2.Evidence-based practice statisticsHard
testdisease presentdisease absenttotalpositive?negativetotal10 000

Practice exercise (made-up values, not clinical guidance). 10 000 people are screened with a test of sensitivity 75% and specificity 90%. The prevalence of the disease is 14%. How many true-positive results TP are expected?

N = 10 000p = 14%Se = 75%Sp = 90%
TP =
3.Descriptive statisticsMedium
202530354045505560

Find the sample standard deviation s of the data: 60, 18, 18, 27, 16, 50, 29.

n = 7
s =
4.Descriptive statisticsHard
z −2−1012

Exam scores are normally distributed with mean 100 and standard deviation 12. Find the z-score z of a score of 112.

μ = 100σ = 12x = 112
z =
5.Confidence intervalsMedium
x̄E₁ = 4.890%, n = 64x̄E₂ = ?99%, n = 128

A 90% confidence interval for a mean, based on 64 observations and a known σ, has a margin of error of 4.8. What is the margin of error E₂ of a 99% interval based on 128 observations?

90%n₁ = 64E₁ = 4.899%n₂ = 128
E₂ =
6.Confidence intervalsHard
p ≈ 0.6, n = ?p̂ − Ep̂ + Ep̂E = 0.02599%

A pilot study suggests that about 0.6 of products are defective. How many products n must be inspected so that a 99% confidence interval for the proportion has a margin of error of at most 0.025?

p ≈ 0.6E = 0.02599%
n =
7.Hypothesis tests & confidence intervalsMedium
−1.961.96z = ?

Two production lines make the same part. Line 1: a sample of 100 parts has mean length 142.5 mm, and the line's known standard deviation is 11 mm. Line 2: a sample of 50 parts has mean 146.9 mm, known standard deviation 8 mm. Find the test statistic z for H₀: μ₁ = μ₂, taking the difference as x̄₁ − x̄₂ (line 1 minus line 2).

n₁ = 100x̄₁ = 142.5 mmσ₁ = 11 mmn₂ = 50x̄₂ = 146.9 mmσ₂ = 8 mm
z =
8.Hypothesis tests & confidence intervalsHard
z −1.9601.96

A sample of 16 measurements has mean 51.2. The population standard deviation is 4. Find the upper limit U of the 95% confidence interval for the mean.

x̄ = 51.2σ = 4n = 1695%
U =

3Solutions

1.Evidence-based practice statistics

Answer: OR = 3

Likelihood ratios and risk measures: LR+ = sensitivity/(1 − specificity), LR− = (1 − sensitivity)/specificity. In a trial, EER and CER are the event rates with and without treatment: RR = EER/CER, ARR = CER − EER, RRR = ARR/CER and NNT = 1/ARR, rounded up. In a case-control study only the odds ratio OR = ad/(bc) can be used. An incidence rate = new cases/person-time.

Odds of exposure

cases: 90/30 = 3
controls: 310/310 = 1

Odds ratio

OR = (90·310)/(310·30) = 3

Answer

OR = 3

OR above 1: exposure is more common among the cases.

2.Evidence-based practice statistics

Answer: TP = 1050

Predictive values depend on prevalence: PPV = Se·p/(Se·p + (1 − Sp)(1 − p)) and NPV = Sp(1 − p)/(Sp(1 − p) + (1 − Se)p). With likelihood ratios: pre-test odds = p/(1 − p), post-test odds = pre-test odds × LR, probability = odds/(1 + odds). For a population of N, true positives = N·p·Se and false positives = N·(1 − p)·(1 − Sp). NNT = 1/(CER × RRR), rounded up.

With and without the disease

10 000·0.14 = 1400
10 000 − 1400 = 8600

True positives

TP = 1400·0.75 = 1050

Answer

TP = 1050
3.Descriptive statistics

Answer: s = 17.25

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 218/7 = 31.14

Squared deviations

Σ(x − x̄)² = 28.86² + (−13.14)² + (−13.14)² + (−4.143)² + (−15.14)² + 18.86² + (−2.143)² = 1785

Standard deviation

s = √(1785/6) = 17.25

Answer

s = 17.25
4.Descriptive statistics

Answer: z = 1

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = (112 − 100)/12 = 1

Answer

z = 1
5.Confidence intervals

Answer: E₂ = 5.315

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Ratio of margins

E₂/E₁ = (2.576/1.645)·√(64/128) = 1.107

New margin

E₂ = 4.8·1.107 = 5.315

Answer

E₂ = 5.315
6.Confidence intervals

Answer: n = 2549

Confidence interval for a proportion: p̂ ± z·√(p̂(1 − p̂)/n), where p̂ = x/n. To reach a margin E you need n ≥ z²·p(1 − p)/E², rounded up; without a prior estimate use p = 0.5, which gives the largest n.

Solve for n

n = 2.576²·0.6·0.4/0.025² = 2548

Round up

n = 2549

Answer

n = 2549
7.Hypothesis tests & confidence intervals

Answer: z = −2.788

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Standard error of the difference

SE = √(11²/100 + 8²/50) = √2.49 = 1.578

Test statistic

z = (142.5 − 146.9)/1.578 = −2.788

Answer

z = −2.788

|z| > 1.96, so H₀ is rejected at the 5% level (two-sided).

8.Hypothesis tests & confidence intervals

Answer: U = 53.16

Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).

Margin of error

E = 1.96·4/√16 = 1.96

Interval limit

U = 51.2 + 1.96 = 53.16

Answer

U = 53.16

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