Evidence-Based Practice: cram pack

Formula sheets, the key method steps for every topic and 8 practice problems, with full solutions at the back.

New problemsBack to the course

In the print window, choose “Save as PDF” to keep a copy on your device.

1Formulas and methods

Evidence-based practice statistics

Sensitivity and specificity
Se = a/(a + c), Sp = d/(b + d)
Predictive values
PPV = a/(a + b), NPV = d/(c + d)
Accuracy
(a + d)/n
Likelihood ratios
LR+ = Se/(1 − Sp), LR− = (1 − Se)/Sp
PPV at prevalence p
Se·p / (Se·p + (1 − Sp)(1 − p))
Odds
odds = p/(1 − p); p = odds/(1 + odds); post-test odds = pre-test odds × LR
Risk measures
RR = EER/CER, ARR = CER − EER, RRR = ARR/CER
Number needed to treat
NNT = 1/ARR, rounded up; NNH = 1/(EER − CER)
Odds ratio
OR = ad/(bc)
Incidence rate
new cases / person-time

Method

  1. Draw the 2 × 2 table and label a, b, c and d before you calculate.
  2. Read sensitivity and specificity down the columns, predictive values along the rows.
  3. For another prevalence, imagine 10 000 people and fill the table with Se, Sp and the prevalence.
  4. For a likelihood ratio, convert the probability to odds, multiply, and convert back.
  5. For a trial, find EER and CER first; then RR = EER/CER, ARR = CER − EER and NNT = 1/ARR rounded up.

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

2Practice problems

1.Evidence-based practice statisticsMedium
Se77%Sp79%LR− = ?

Practice exercise (made-up values, not clinical guidance). A test has a sensitivity of 77% and a specificity of 79%. Find the negative likelihood ratio LR−. Round to two decimal places.

Se = 77%Sp = 79%
LR− =
2.Evidence-based practice statisticsHard
pre-test5%post-test?p′LR+

Practice exercise (made-up values, not clinical guidance). A patient has a pre-test probability of 5% for a disease. A test with sensitivity 72% and specificity 71% comes back positive. Find the post-test probability p′ of the disease as a percentage. Round to one decimal place.

pre-test 5%Se = 72%Sp = 71%positive
p′ = %
3.Descriptive statisticsMedium
1520253035404550

Find the sample standard deviation s of the data: 18, 29, 47, 12, 53.

n = 5
s =
4.Descriptive statisticsHard
z −2−1012

Exam scores are normally distributed with mean 100 and standard deviation 20. Find the z-score z of a score of 125.

μ = 100σ = 20x = 125
z =
5.Confidence intervalsMedium
μ₁ − μ₂0LU = ?x̄₁ − x̄₂E90%

The battery life of two phone models is compared. Model 1: 60 phones, mean 78.5 h, known standard deviation 9 h. Model 2: 40 phones, mean 73 h, known standard deviation 15 h. Find the upper limit of the 90% confidence interval for μ₁ − μ₂.

n₁ = 60x̄₁ = 78.5 hσ₁ = 9 hn₂ = 40x̄₂ = 73 hσ₂ = 15 h90%
upper limit = h
6.Confidence intervalsHard
σ = 31, n = ?x̄ − Ex̄ + Ex̄E = 2.599%

The population standard deviation is 31. How large a sample n do you need so that a 99% confidence interval for the mean has a margin of error of at most 2.5?

σ = 31E = 2.599%
n =
7.Hypothesis tests & confidence intervalsMedium
1.64p = ?

The mean of a population is claimed to be 50; the population standard deviation is known to be 15. A random sample of 100 observations has a mean of 52.46. Test H₀: μ = 50 against H₁: μ > 50. Find the p-value p.

μ₀ = 50σ = 15n = 100x̄ = 52.46H₁: μ > μ₀
p =
8.Hypothesis tests & confidence intervalsHard
z −1.9601.96

A sample of 64 measurements has mean 99.6. The population standard deviation is 4. Find the upper limit U of the 95% confidence interval for the mean.

x̄ = 99.6σ = 4n = 6495%
U =

3Solutions

1.Evidence-based practice statistics

Answer: LR− = 0.29

Likelihood ratios and risk measures: LR+ = sensitivity/(1 − specificity), LR− = (1 − sensitivity)/specificity. In a trial, EER and CER are the event rates with and without treatment: RR = EER/CER, ARR = CER − EER, RRR = ARR/CER and NNT = 1/ARR, rounded up. In a case-control study only the odds ratio OR = ad/(bc) can be used. An incidence rate = new cases/person-time.

Negative likelihood ratio

LR− = (1 − 0.77)/0.79 = 0.2911 ≈ 0.29

Answer

LR− = 0.29
2.Evidence-based practice statistics

Answer: p′ = 11.6 %

Predictive values depend on prevalence: PPV = Se·p/(Se·p + (1 − Sp)(1 − p)) and NPV = Sp(1 − p)/(Sp(1 − p) + (1 − Se)p). With likelihood ratios: pre-test odds = p/(1 − p), post-test odds = pre-test odds × LR, probability = odds/(1 + odds). For a population of N, true positives = N·p·Se and false positives = N·(1 − p)·(1 − Sp). NNT = 1/(CER × RRR), rounded up.

Likelihood ratio

LR+ = 0.72/(1 − 0.71) = 2.483

Pre-test odds

0.05/(1 − 0.05) = 0.05263

Post-test odds

0.05263·2.483 = 0.1307

Post-test probability

p′ = 0.1307/(1 + 0.1307) = 0.1156 ≈ 11.6%

Answer

p′ = 11.6%
3.Descriptive statistics

Answer: s = 17.82

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 159/5 = 31.8

Squared deviations

Σ(x − x̄)² = (−13.8)² + (−2.8)² + 15.2² + (−19.8)² + 21.2² = 1271

Standard deviation

s = √(1271/4) = 17.82

Answer

s = 17.82
4.Descriptive statistics

Answer: z = 1.25

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = (125 − 100)/20 = 1.25

Answer

z = 1.25
5.Confidence intervals

Answer: upper limit = 9.844 h

Interval for a difference: estimate ± critical value × standard error. For two independent means with known σ: SE = √(σ₁²/n₁ + σ₂²/n₂) and z. With equal unknown variances: pooled s_p and t with n₁ + n₂ − 2 degrees of freedom. For paired data, work with the differences: d̄ ± t·s_d/√n.

Point estimate

x̄₁ − x̄₂ = 78.5 − 73 = 5.5

Standard error

SE = √(9²/60 + 15²/40) = 2.641

Margin of error

E = 1.645·2.641 = 4.344

Interval

5.5 ± 4.344 → [1.156, 9.844]

Answer

upper limit = 9.844 h

The interval does not contain 0, so the means differ significantly.

6.Confidence intervals

Answer: n = 1021

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Solve for n

n = (2.576·31/2.5)² = 1020

Round up

A sample size is a whole number, and rounding down would make the margin too large.

n = 1021

Answer

n = 1021
7.Hypothesis tests & confidence intervals

Answer: p = 0.0505

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Test statistic

SE = σ/√n = 15/√100 = 1.5
z = (52.46 − 50)/1.5 = 1.64

Tail area

Φ(1.64) = 0.9495
1 − Φ(1.64) = 0.0505

p-value

p = 0.0505

Answer

p = 0.0505

p > 0.05, so H₀ is not rejected at the 5% level.

8.Hypothesis tests & confidence intervals

Answer: U = 100.6

Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).

Margin of error

E = 1.96·4/√64 = 0.98

Interval limit

U = 99.6 + 0.98 = 100.6

Answer

U = 100.6

ExamProblems · examproblems.com/courses/evidence-based-practice