Evidence-Based Practice: cram pack

Formula sheets, the key method steps for every topic and 8 practice problems, with full solutions at the back.

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1Formulas and methods

Evidence-based practice statistics

Sensitivity and specificity
Se = a/(a + c), Sp = d/(b + d)
Predictive values
PPV = a/(a + b), NPV = d/(c + d)
Accuracy
(a + d)/n
Likelihood ratios
LR+ = Se/(1 − Sp), LR− = (1 − Se)/Sp
PPV at prevalence p
Se·p / (Se·p + (1 − Sp)(1 − p))
Odds
odds = p/(1 − p); p = odds/(1 + odds); post-test odds = pre-test odds × LR
Risk measures
RR = EER/CER, ARR = CER − EER, RRR = ARR/CER
Number needed to treat
NNT = 1/ARR, rounded up; NNH = 1/(EER − CER)
Odds ratio
OR = ad/(bc)
Incidence rate
new cases / person-time

Method

  1. Draw the 2 × 2 table and label a, b, c and d before you calculate.
  2. Read sensitivity and specificity down the columns, predictive values along the rows.
  3. For another prevalence, imagine 10 000 people and fill the table with Se, Sp and the prevalence.
  4. For a likelihood ratio, convert the probability to odds, multiply, and convert back.
  5. For a trial, find EER and CER first; then RR = EER/CER, ARR = CER − EER and NNT = 1/ARR rounded up.

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

2Practice problems

1.Evidence-based practice statisticsMedium
Se89%Sp88%LR+ = ?

Practice exercise (made-up values, not clinical guidance). A test has a sensitivity of 89% and a specificity of 88%. Find the positive likelihood ratio LR+. Round to two decimal places.

Se = 89%Sp = 88%
LR+ =
2.Evidence-based practice statisticsHard
p (%)PPV (%)1%PPV = ?100

Practice exercise (made-up values, not clinical guidance). A screening test has a sensitivity of 97% and a specificity of 80%. It is used in a population where the prevalence is 1%. Find the positive predictive value PPV as a percentage. Round to one decimal place.

Se = 97%Sp = 80%p = 1%
PPV = %
3.Descriptive statisticsMedium
303132333435363738

Find the sample standard deviation s of the data: 30, 38, 32, 32, 30.

n = 5
s =
4.Descriptive statisticsHard
z −2−1012

A quantity is normally distributed with mean 50 and standard deviation 8. What proportion P of values is below 58?

μ = 50σ = 8x = 58
P =
5.Confidence intervalsMedium
μ₁ − μ₂0LUx̄₁ − x̄₂E = ?95%

The battery life of two phone models is compared. Model 1: 100 phones, mean 96.5 h, known standard deviation 13 h. Model 2: 50 phones, mean 91.5 h, known standard deviation 13 h. Find the margin of error E of the 95% confidence interval for μ₁ − μ₂.

n₁ = 100x̄₁ = 96.5 hσ₁ = 13 hn₂ = 50x̄₂ = 91.5 hσ₂ = 13 h95%
E = h
6.Confidence intervalsHard
σ = 28, n = ?x̄ − Ex̄ + Ex̄E = 1.599%

The population standard deviation is 28. How large a sample n do you need so that a 99% confidence interval for the mean has a margin of error of at most 1.5?

σ = 28E = 1.599%
n =
7.Hypothesis tests & confidence intervalsMedium
t −1.9901.99

A sample of 81 students has a mean score of 101.3 and a sample standard deviation of 4. Find the test statistic t for H₀: μ = 100.

μ₀ = 100x̄ = 101.3s = 4n = 81
t =
8.Hypothesis tests & confidence intervalsHard
μ₀x̄c

A one-sided z test of H₀: μ = 50 against H₁: μ < 50 is done at α = 0.05 with a sample of 25; the standard deviation is known to be 7.5. In reality the mean is 48.5. Find the power 1 − β of the test in percent.

μ₀ = 50μ = 48.5σ = 7.5n = 25α = 0.05
1 − β = %

3Solutions

1.Evidence-based practice statistics

Answer: LR+ = 7.42

Likelihood ratios and risk measures: LR+ = sensitivity/(1 − specificity), LR− = (1 − sensitivity)/specificity. In a trial, EER and CER are the event rates with and without treatment: RR = EER/CER, ARR = CER − EER, RRR = ARR/CER and NNT = 1/ARR, rounded up. In a case-control study only the odds ratio OR = ad/(bc) can be used. An incidence rate = new cases/person-time.

Positive likelihood ratio

LR+ = 0.89/(1 − 0.88) = 7.417 ≈ 7.42

Answer

LR+ = 7.42
2.Evidence-based practice statistics

Answer: PPV = 4.7 %

Predictive values depend on prevalence: PPV = Se·p/(Se·p + (1 − Sp)(1 − p)) and NPV = Sp(1 − p)/(Sp(1 − p) + (1 − Se)p). With likelihood ratios: pre-test odds = p/(1 − p), post-test odds = pre-test odds × LR, probability = odds/(1 + odds). For a population of N, true positives = N·p·Se and false positives = N·(1 − p)·(1 − Sp). NNT = 1/(CER × RRR), rounded up.

True and false positives (per person)

Se·p = 0.97·0.01 = 0.0097
(1 − Sp)·(1 − p) = 0.2·0.99 = 0.198

Positive predictive value

PPV = 0.0097/(0.0097 + 0.198) = 0.0467 ≈ 4.7%

Answer

PPV = 4.7%

The lower the prevalence, the lower the PPV of the same test.

3.Descriptive statistics

Answer: s = 3.286

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 162/5 = 32.4

Squared deviations

Σ(x − x̄)² = (−2.4)² + 5.6² + (−0.4)² + (−0.4)² + (−2.4)² = 43.2

Standard deviation

s = √(43.2/4) = 3.286

Answer

s = 3.286
4.Descriptive statistics

Answer: P = 0.8413

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = 1

Standard normal table

Φ(1) = 0.8413
P = 0.8413

Answer

P = 0.8413
5.Confidence intervals

Answer: E = 4.413 h

Interval for a difference: estimate ± critical value × standard error. For two independent means with known σ: SE = √(σ₁²/n₁ + σ₂²/n₂) and z. With equal unknown variances: pooled s_p and t with n₁ + n₂ − 2 degrees of freedom. For paired data, work with the differences: d̄ ± t·s_d/√n.

Point estimate

x̄₁ − x̄₂ = 96.5 − 91.5 = 5

Standard error

SE = √(13²/100 + 13²/50) = 2.252

Margin of error

E = 1.96·2.252 = 4.413

Answer

E = 4.413 h

The interval does not contain 0, so the means differ significantly.

6.Confidence intervals

Answer: n = 2313

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Solve for n

n = (2.576·28/1.5)² = 2312

Round up

A sample size is a whole number, and rounding down would make the margin too large.

n = 2313

Answer

n = 2313
7.Hypothesis tests & confidence intervals

Answer: t = 2.925

Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).

Standard error

SE = 4/√81 = 4/9 = 0.4444

Test statistic

t = (101.3 − 100)/0.4444 = 2.925

Answer

t = 2.925
t0.025; df = 80 = 1.99

|t| > 1.99, so H₀ is rejected at the 5% level (two-sided).

8.Hypothesis tests & confidence intervals

Answer: 1 − β = 25.95 %

Power of a test: power = 1 − β is the probability of rejecting H₀ when it is false. Find the cutoff x̄c from μ₀ and z_α, then compute the probability of landing beyond x̄c using the true mean: z = (x̄c − μ)/(σ/√n).

Critical sample mean

SE = 7.5/√25 = 1.5
x̄c = 50 − 1.645·1.5 = 47.53

z under the true mean

z = (47.53 − 48.5)/1.5 = −0.645

Power

power = P(Z < −0.645) = 25.95%
1 − β = 25.95%

Answer

1 − β = 25.95%

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