Depreciation
- Straight-line
- (cost − salvage)/life
- Double-declining balance
- 2/life × book value at the start of the year
- Sum of the years’ digits
- (cost − salvage) × remaining life/SYD
- SYD
- n(n + 1)/2
- Book value
- cost − accumulated depreciation
Formula sheets, the key method steps for every topic and 4 practice problems, with full solutions at the back.
Operating profit is €120,000 and interest expense is €30,000. What is interest cover?
A firm has spent €50,000 on market research for a new product and must decide whether to launch it. How should the €50,000 be treated in the decision?
A production line costs €60 000, has a useful life of 5 years and a salvage value of €12 000. Using the double-declining-balance method (without switching to straight-line), find the depreciation charge D in year 3.
A production line costs €20 000, has a useful life of 10 years and a salvage value of €2 000. Using the sum-of-the-years’-digits method, find the depreciation charge D in year 3.
Answer: C · 4 times
€120,000 ÷ €30,000 = 4. The company earns its interest four times over; low cover signals a risk of not meeting interest payments.
Answer: B · Ignored, because it is a sunk cost
The research money is spent whichever choice is made, so it is irrelevant. Only future incremental cash flows from launching should be compared.
Answer: D = 8640 €
Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).
Answer: D = 2618 €
Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).
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