Depreciation
- Straight-line
- (cost − salvage)/life
- Double-declining balance
- 2/life × book value at the start of the year
- Sum of the years’ digits
- (cost − salvage) × remaining life/SYD
- SYD
- n(n + 1)/2
- Book value
- cost − accumulated depreciation
Formula sheets, the key method steps for every topic and 4 practice problems, with full solutions at the back.
Operating profit is €120,000 and interest expense is €30,000. What is interest cover?
Production exceeds sales this period, so inventory rises. How does absorption costing profit compare with marginal costing profit?
A computer system costs €50 000, has a useful life of 5 years and a salvage value of €10 000. Using the double-declining-balance method (without switching to straight-line), find the depreciation charge D in year 3.
A production line costs €120 000, has a useful life of 10 years and a salvage value of €0. Using the sum-of-the-years’-digits method, find the depreciation charge D in year 4.
Answer: A · 4 times
€120,000 ÷ €30,000 = 4. The company earns its interest four times over; low cover signals a risk of not meeting interest payments.
Answer: A · Absorption costing profit is higher
Under absorption costing part of this period's fixed overhead sits in closing inventory instead of being expensed, so reported profit is higher when inventory rises.
Answer: D = 7200 €
Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).
Answer: D = 15273 €
Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).
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