Depreciation
- Straight-line
- (cost − salvage)/life
- Double-declining balance
- 2/life × book value at the start of the year
- Sum of the years’ digits
- (cost − salvage) × remaining life/SYD
- SYD
- n(n + 1)/2
- Book value
- cost − accumulated depreciation
Formula sheets, the key method steps for every topic and 4 practice problems, with full solutions at the back.
A company increases its allowance for doubtful receivables. What is the effect?
In the indirect method of the cash flow statement, depreciation is:
A machine costs €60 000, has a useful life of 5 years and a salvage value of €9 000. Using the double-declining-balance method (without switching to straight-line), find the depreciation charge D in year 3.
A production line costs €20 000, has a useful life of 4 years and a salvage value of €0. Using the sum-of-the-years’-digits method, find the depreciation charge D in year 2.
Answer: B · An expense is recognised and net receivables fall
The increase is charged to profit, and the allowance is deducted from gross receivables, so the balance sheet shows the amount expected to be collected.
Answer: A · Added back to net profit because it is a non-cash expense
Starting from profit, non-cash charges like depreciation are added back, and changes in working capital are adjusted.
Answer: D = 8640 €
Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).
Answer: D = 6000 €
Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).
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