Depreciation
- Straight-line
- (cost − salvage)/life
- Double-declining balance
- 2/life × book value at the start of the year
- Sum of the years’ digits
- (cost − salvage) × remaining life/SYD
- SYD
- n(n + 1)/2
- Book value
- cost − accumulated depreciation
Formula sheets, the key method steps for every topic and 4 practice problems, with full solutions at the back.
A company is being sued. Its lawyers say losing is possible but not probable. How is this treated under IAS 37?
The standard price of material is €5 per kg. The company buys 1,000 kg for €5,400. What is the material price variance?
A delivery van costs €24 000, has a useful life of 5 years and a salvage value of €3 500. Using the double-declining-balance method (without switching to straight-line), find the depreciation charge D in year 2.
A computer system costs €120 000, has a useful life of 4 years and a salvage value of €0. Using the sum-of-the-years’-digits method, find the depreciation charge D in year 2.
Answer: A · Disclosed as a contingent liability in the notes
A possible obligation is not recognised but disclosed, unless the chance of outflow is remote. A probable, measurable outflow would require a provision.
Answer: B · €400 adverse
Standard cost of 1,000 kg = €5,000; actual cost = €5,400. Paying more than standard gives a €400 adverse price variance.
Answer: D = 5760 €
Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).
Answer: D = 36000 €
Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).
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