Depreciation
- Straight-line
- (cost − salvage)/life
- Double-declining balance
- 2/life × book value at the start of the year
- Sum of the years’ digits
- (cost − salvage) × remaining life/SYD
- SYD
- n(n + 1)/2
- Book value
- cost − accumulated depreciation
Formula sheets, the key method steps for every topic and 4 practice problems, with full solutions at the back.
Trade receivables are €50,000 and annual credit sales are €365,000. What are the receivable days?
A company borrows at 5% interest to invest in assets that earn 12%. What is the likely effect on return on equity?
A computer system costs €100 000, has a useful life of 5 years and a salvage value of €20 000. Using the double-declining-balance method (without switching to straight-line), find the depreciation charge D in year 3.
A production line costs €24 000, has a useful life of 8 years and a salvage value of €5 000. Using the sum-of-the-years’-digits method, find the depreciation charge D in year 5.
Answer: C · 50 days
€50,000 ÷ €365,000 × 365 = 50 days. This is the average time customers take to pay.
Answer: B · ROE rises, but financial risk also increases
Positive financial leverage: assets earn more than the debt costs, so profit per euro of equity rises. If returns drop below 5%, leverage works against shareholders.
Answer: D = 14400 €
Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).
Answer: D = 2111 €
Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).
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