Financial Accounting: cram pack

Formula sheets, the key method steps for every topic and 4 practice problems, with full solutions at the back.

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1Formulas and methods

Depreciation

Straight-line
(cost − salvage)/life
Double-declining balance
2/life × book value at the start of the year
Sum of the years’ digits
(cost − salvage) × remaining life/SYD
SYD
n(n + 1)/2
Book value
cost − accumulated depreciation

2Practice problems

1.Financial accountingMedium

At 31 December, electricity used in December (€800) has not yet been billed. Which year-end entry is correct?

  1. ADebit prepayments, credit cash
  2. BDebit electricity expense, credit accruals
  3. CNo entry until the bill arrives
  4. DDebit accruals, credit electricity expense
2.Financial accountingHard

The standard is 2 labour hours per unit at €20 an hour. 500 units are made in 1,100 hours. What is the labour efficiency variance?

  1. A€1,000 adverse
  2. B€22,000 adverse
  3. C€2,000 adverse
  4. D€2,000 favourable
3.DepreciationMedium
0€50 00012345salvage €10 000D = ?yearBook value at the end of each year

A machine costs €50 000, has a useful life of 5 years and a salvage value of €10 000. Using the double-declining-balance method (without switching to straight-line), find the depreciation charge D in year 2.

cost = €50 000life = 5salvage = €10 000year = 2
D = €
4.DepreciationHard
0€12 00012345678salvage €1 000D = ?yearBook value at the end of each year

A delivery van costs €12 000, has a useful life of 8 years and a salvage value of €1 000. Using the sum-of-the-years’-digits method, find the depreciation charge D in year 2.

cost = €12 000life = 8salvage = €1 000year = 2
D = €

3Solutions

1.Financial accounting

Answer: B · Debit electricity expense, credit accruals

Why this is the answer

The accrual records December's cost as an expense this year with a current liability, so expenses match the period of use.

Answer

B · Debit electricity expense, credit accruals
2.Financial accounting

Answer: C · €2,000 adverse

Why this is the answer

Standard hours = 500 × 2 = 1,000. Extra 100 hours × €20 = €2,000 adverse, because more hours were used than the standard allows.

Answer

C · €2,000 adverse
3.Depreciation

Answer: D = 12000 €

Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).

Rate

2/5 = 0.4

Year by year

year 1: 0.4·50 000.00 = €20 000.00
year 2: 0.4·30 000.00 = €12 000.00

Answer

D = €12 000.00
4.Depreciation

Answer: D = 2139 €

Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).

Fraction for year 2

(8 − 2 + 1)/36 = 7/36

Depreciation

D = 11 000·7/36 = €2 138.89

Answer

D = €2 138.89

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