Financial Accounting: cram pack

Formula sheets, the key method steps for every topic and 4 practice problems, with full solutions at the back.

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1Formulas and methods

Depreciation

Straight-line
(cost − salvage)/life
Double-declining balance
2/life × book value at the start of the year
Sum of the years’ digits
(cost − salvage) × remaining life/SYD
SYD
n(n + 1)/2
Book value
cost − accumulated depreciation

2Practice problems

1.Financial accountingMedium

A project costs €100,000 and brings in €25,000 cash per year. What is its payback period?

  1. A4 years
  2. B25 years
  3. C5 years
  4. D2.5 years
2.Financial accountingHard

The standard price of material is €5 per kg. The company buys 1,000 kg for €5,400. What is the material price variance?

  1. A€400 favourable
  2. B€5,400 adverse
  3. C€0.40 adverse
  4. D€400 adverse
3.DepreciationMedium
0€120 0001234salvage €6 000D = ?yearBook value at the end of each year

A machine costs €120 000, has a useful life of 4 years and a salvage value of €6 000. Using the double-declining-balance method (without switching to straight-line), find the depreciation charge D in year 2.

cost = €120 000life = 4salvage = €6 000year = 2
D = €
4.DepreciationHard
0€60 00012345678910D = ?yearBook value at the end of each year

A machine costs €60 000, has a useful life of 10 years and a salvage value of €0. Using the sum-of-the-years’-digits method, find the depreciation charge D in year 7.

cost = €60 000life = 10salvage = €0year = 7
D = €

3Solutions

1.Financial accounting

Answer: A · 4 years

Why this is the answer

€100,000 ÷ €25,000 = 4 years. Payback is simple but ignores the time value of money and cash flows after payback.

Answer

A · 4 years
2.Financial accounting

Answer: D · €400 adverse

Why this is the answer

Standard cost of 1,000 kg = €5,000; actual cost = €5,400. Paying more than standard gives a €400 adverse price variance.

Answer

D · €400 adverse
3.Depreciation

Answer: D = 30000 €

Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).

Rate

2/4 = 0.5

Year by year

year 1: 0.5·120 000.00 = €60 000.00
year 2: 0.5·60 000.00 = €30 000.00

Answer

D = €30 000.00
4.Depreciation

Answer: D = 4364 €

Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).

Fraction for year 7

(10 − 7 + 1)/55 = 4/55

Depreciation

D = 60 000·4/55 = €4 363.64

Answer

D = €4 363.64

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