Financial Accounting: cram pack

Formula sheets, the key method steps for every topic and 4 practice problems, with full solutions at the back.

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1Formulas and methods

Depreciation

Straight-line
(cost − salvage)/life
Double-declining balance
2/life × book value at the start of the year
Sum of the years’ digits
(cost − salvage) × remaining life/SYD
SYD
n(n + 1)/2
Book value
cost − accumulated depreciation

2Practice problems

1.Financial accountingMedium

Trade receivables are €50,000 and annual credit sales are €365,000. What are the receivable days?

  1. A73 days
  2. B7.3 days
  3. C36.5 days
  4. D50 days
2.Financial accountingHard

The standard is 2 labour hours per unit at €20 an hour. 500 units are made in 1,100 hours. What is the labour efficiency variance?

  1. A€22,000 adverse
  2. B€2,000 favourable
  3. C€2,000 adverse
  4. D€1,000 adverse
3.DepreciationMedium
0€45 0001234salvage €4 500D = ?yearBook value at the end of each year

A machine costs €45 000, has a useful life of 4 years and a salvage value of €4 500. Using the double-declining-balance method (without switching to straight-line), find the depreciation charge D in year 2.

cost = €45 000life = 4salvage = €4 500year = 2
D = €
4.DepreciationHard
0€100 00012345678salvage €20 000D = ?yearBook value at the end of each year

A machine costs €100 000, has a useful life of 8 years and a salvage value of €20 000. Using the sum-of-the-years’-digits method, find the depreciation charge D in year 6.

cost = €100 000life = 8salvage = €20 000year = 6
D = €

3Solutions

1.Financial accounting

Answer: D · 50 days

Why this is the answer

€50,000 ÷ €365,000 × 365 = 50 days. This is the average time customers take to pay.

Answer

D · 50 days
2.Financial accounting

Answer: C · €2,000 adverse

Why this is the answer

Standard hours = 500 × 2 = 1,000. Extra 100 hours × €20 = €2,000 adverse, because more hours were used than the standard allows.

Answer

C · €2,000 adverse
3.Depreciation

Answer: D = 11250 €

Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).

Rate

2/4 = 0.5

Year by year

year 1: 0.5·45 000.00 = €22 500.00
year 2: 0.5·22 500.00 = €11 250.00

Answer

D = €11 250.00
4.Depreciation

Answer: D = 6667 €

Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).

Fraction for year 6

(8 − 6 + 1)/36 = 3/36

Depreciation

D = 80 000·3/36 = €6 666.67

Answer

D = €6 666.67

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