Depreciation
- Straight-line
- (cost − salvage)/life
- Double-declining balance
- 2/life × book value at the start of the year
- Sum of the years’ digits
- (cost − salvage) × remaining life/SYD
- SYD
- n(n + 1)/2
- Book value
- cost − accumulated depreciation
Formula sheets, the key method steps for every topic and 4 practice problems, with full solutions at the back.
A project costs €100,000 and brings in €25,000 cash per year. What is its payback period?
A company switches to a depreciation method that gives higher charges. Ignoring tax, what happens to cash flow?
A production line costs €45 000, has a useful life of 6 years and a salvage value of €4 500. Using the double-declining-balance method (without switching to straight-line), find the depreciation charge D in year 2.
A computer system costs €60 000, has a useful life of 10 years and a salvage value of €0. Using the sum-of-the-years’-digits method, find the depreciation charge D in year 7.
Answer: C · 4 years
€100,000 ÷ €25,000 = 4 years. Payback is simple but ignores the time value of money and cash flows after payback.
Answer: D · Cash flow is unchanged, although profit falls
Depreciation allocates a cost already paid. Changing the method changes reported profit, but no extra cash leaves the business (tax effects aside).
Answer: D = 10000 €
Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).
Answer: D = 4364 €
Depreciation spreads the cost of an asset over its useful life. Straight-line: (cost − salvage value)/life every year. Double-declining balance: 2/life times the book value at the start of each year, so the charge falls each year (salvage is not subtracted, but the book value never goes below it). Sum-of-the-years’-digits: (cost − salvage) × remaining life/(1 + 2 + … + n).
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