Lab Values for Nurses: cram pack

Formula sheets, the key method steps for every topic and 8 practice problems, with full solutions at the back.

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1Formulas and methods

Lab values & electrolytes

Method

  1. Compare the value with the laboratory’s own reference range, then with the patient’s baseline and trend.
  2. Check the sample: hemolysis, a delay, or blood drawn near an IV can give false results.
  3. Link the value to its typical signs and to the drugs and conditions that cause it.
  4. Look for interactions: low potassium or magnesium increases digoxin toxicity; dehydration raises lithium.
  5. Act on the patient: assess, hold a drug if the level is unsafe, read back critical values and inform the prescriber.

Arterial blood gas interpretation

Normal ranges
pH 7.35–7.45, PaCO₂ 35–45 mmHg (4.7–6.0 kPa), HCO₃⁻ 22–26 mmol/L
ROME
Respiratory: PaCO₂ opposite to pH; Metabolic: HCO₃⁻ equal to pH
Winter’s formula
PaCO₂ = 1.5·HCO₃⁻ + 8 ± 2
Metabolic alkalosis
PaCO₂ ≈ 0.7·HCO₃⁻ + 21
Anion gap
AG = Na⁺ − (Cl⁻ + HCO₃⁻) ≈ 8–12
Albumin-corrected gap
AG + 2.5·(4.0 − alb g/dL) = AG + 0.25·(40 − alb g/L)
Delta ratio
(AG − 12)/(24 − HCO₃⁻)
P/F ratio
PaO₂/FiO₂
Alveolar gas equation
PAO₂ = FiO₂·(760 − 47) − PaCO₂/0.8
Serum osmolality
2·Na⁺ + glucose + urea (2·Na⁺ + glucose/18 + BUN/2.8)

Method

  1. Read the pH: below 7.35 is acidosis, above 7.45 alkalosis.
  2. Find the value that explains it: PaCO₂ moving opposite to the pH is respiratory, HCO₃⁻ moving with the pH is metabolic.
  3. Look at the other value: normal means uncompensated, abnormal in the compensating direction means partial compensation, and a normal pH with both abnormal means full compensation.
  4. In a metabolic acidosis, compare PaCO₂ with Winter’s formula, 1.5·HCO₃⁻ + 8 ± 2, and calculate the anion gap Na⁺ − (Cl⁻ + HCO₃⁻).
  5. Check a high anion gap with the delta ratio and, when albumin is low, with the corrected gap.

Clinical pharmacokinetics

Rate constant and half-life
k = ln 2/t½ = 0.693/t½
First-order decay
C = C₀·e−kt = C₀·(1/2)t/t½
Two levels
k = ln(C₁/C₂)/Δt
Volume and clearance
Vd = dose/C₀, CL = k·Vd
Loading dose
LD = Vd·C/(S·F)
Maintenance rate
R = CL·Css/(S·F)
Average steady state
Css,avg = S·F·D/(CL·τ)
Steady state
1 − (1/2)ⁿ after n half-lives; ≈ 97% after 5
Infusion
C = (R/CL)(1 − e−kt)
Interval and dose from peak and trough
τ = ln(Cpeak/Ctrough)/k, D = Vd·(Cpeak − Ctrough)
Cockcroft–Gault
CrCl = (140 − age) × kg/(72 × SCr mg/dL), × 0.85 for women
Renal adjustment
dose × CrCl/normal; Dettli Q = 1 − fe·(1 − CrCl/normal)

Method

  1. Convert the half-life to a rate constant: k = 0.693/t½.
  2. Turn per-kg values into totals: Vd (L) = L/kg × weight, CL (L/h) = L/kg/h × weight.
  3. Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
  4. For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
  5. Check the result: levels fall by half every half-life, and steady state takes about five half-lives.

2Practice problems

1.Lab values & electrolytesMedium

A patient has a sodium of 124 mEq/L, a headache and new confusion. Which nursing measure is most appropriate?

  1. AEncourage the patient to drink plenty of plain water
  2. BPut seizure precautions in place and monitor neurological status
  3. CGive the next dose of the prescribed thiazide diuretic early
  4. DKeep the patient flat and limit neurological checks to once a shift
2.Lab values & electrolytesHard

An older adult has bone pain, fatigue and frequent infections. Results show anemia, a calcium of 12.4 mg/dL (3.1 mmol/L), a raised total protein and a rising creatinine. Which condition should be suspected?

  1. AMultiple myeloma
  2. BPrimary hypothyroidism
  3. CIron-deficiency anemia
  4. DAcute viral hepatitis
3.Arterial blood gas interpretationMedium

Practice values: Na⁺ 130 mmol/L, glucose 5.7 mmol/L and urea 9 mmol/L. Calculate the serum osmolality Osm = 2·Na⁺ + glucose + urea to the nearest whole number.

Na⁺ 130 mmol/Lglucose 5.7 mmol/Lurea 9 mmol/L
Osm = mOsm/kg
4.Arterial blood gas interpretationHard

At sea level, a practice gas taken on 35% oxygen shows PaO₂ 89 mmHg (11.9 kPa) and PaCO₂ 54 mmHg (7.2 kPa). Use PAO₂ = FiO₂·(760 − 47) − PaCO₂/0.8 to find the A–a gradient.

FiO₂ 35%PaO₂ 89 mmHg (11.9 kPa)PaCO₂ 54 mmHg (7.2 kPa)
A–a gradient = mmHg
5.Clinical pharmacokineticsMedium
Vd = 0.5 L/kgC = 10 mg/LLD = ? mg79 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 79 kg patient is to be loaded intravenously with aminophylline to reach a theophylline level of 10 mg/L. The volume of distribution is 0.5 L/kg and the salt factor is S = 0.8. Find the loading dose LD of aminophylline in mg.

79 kgVd = 0.5 L/kgC = 10 mg/LS = 0.8
LD = mg
6.Clinical pharmacokineticsHard
Vd = 0.7 L/kg12 → 20 mg/LLD = ? mg77 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 77 kg patient has a phenytoin level of 12 mg/L; the target is 20 mg/L. The drug is given intravenously as phenytoin sodium (S = 0.92), and the volume of distribution is 0.7 L/kg. What extra loading dose LD raises the level to the target?

77 kgVd = 0.7 L/kgC = 12 → 20 mg/LS = 0.92
LD = mg
7.Clinical nursingMedium

A nurse suspects that an older patient is being financially abused by a relative. What should the nurse do?

  1. AConfront the relative directly at the bedside about it
  2. BKeep it secret because it is a family matter
  3. CWait until the patient has been discharged
  4. DRaise the concern through the local safeguarding (adult protection) procedure
8.Clinical nursingHard

A patient starting a DOAC is taught about missed doses. Which statement shows a need for further teaching?

  1. A"I will report any blood in my urine."
  2. B"If I forget a dose, I'll take two the next day to catch up."
  3. C"I will take it at the same time each day."
  4. D"I will tell other doctors and my dentist I take an anticoagulant."

3Solutions

1.Lab values & electrolytes

Answer: B · Put seizure precautions in place and monitor neurological status

Why this is the answer

Hyponatremia can cause cerebral edema and seizures. The nurse monitors neurological status, takes seizure precautions and reports the result. Extra water and thiazides can lower the sodium further.Checked against: Low blood sodium · MedlinePlus (NIH) (2025)

Answer

B · Put seizure precautions in place and monitor neurological status
2.Lab values & electrolytes

Answer: A · Multiple myeloma

Why this is the answer

Multiple myeloma typically causes high calcium from bone destruction, kidney damage, anemia and bone lesions, plus a raised protein from a monoclonal antibody. Recurrent infections reflect poor production of normal antibodies.Checked against: Multiple Myeloma · StatPearls (NCBI Bookshelf) (2023)

Answer

A · Multiple myeloma
3.Arterial blood gas interpretation

Answer: Osm = 275 mOsm/kg

Derived values: calculated serum osmolality is 2·Na⁺ + glucose + urea with all values in mmol/L (2·Na⁺ + glucose/18 + BUN/2.8 with glucose and BUN in mg/dL); normal is about 275–295 mOsm/kg. The P/F ratio is PaO₂ divided by FiO₂ as a fraction. The alveolar oxygen pressure is PAO₂ = FiO₂·(760 − 47) − PaCO₂/0.8 mmHg at sea level, and the A–a gradient is PAO₂ − PaO₂.

Calculated osmolality

Osm = 2·130 + 5.7 + 9 = 274.7 ≈ 275 mOsm/kg

Answer

Osm = 275 mOsm/kg
4.Arterial blood gas interpretation

Answer: A–a gradient = 93.05 mmHg

Derived values: calculated serum osmolality is 2·Na⁺ + glucose + urea with all values in mmol/L (2·Na⁺ + glucose/18 + BUN/2.8 with glucose and BUN in mg/dL); normal is about 275–295 mOsm/kg. The P/F ratio is PaO₂ divided by FiO₂ as a fraction. The alveolar oxygen pressure is PAO₂ = FiO₂·(760 − 47) − PaCO₂/0.8 mmHg at sea level, and the A–a gradient is PAO₂ − PaO₂.

Alveolar oxygen

PAO₂ = 0.35·713 − 54/0.8 = 249.5 − 67.5 = 182 mmHg

Gradient

A–a = 182 − 89 = 93.05 mmHg

Answer

A–a gradient = 93.05 mmHg
5.Clinical pharmacokinetics

Answer: LD = 493.8 mg

Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Volume of distribution

Vd = 0.5·79 = 39.5 L

Amount of active drug needed

Vd·C = 39.5·10 = 395 mg

Loading dose

LD = 395/(0.8·1) = 493.8 mg

Answer

LD = 493.8 mg

In practice the dose is rounded to a convenient amount.

6.Clinical pharmacokinetics

Answer: LD = 468.7 mg

Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Volume of distribution

Vd = 0.7·77 = 53.9 L

Rise needed

20 − 12 = 8 mg/L

Loading dose

LD = 53.9·8/(0.92·1) = 468.7 mg

Answer

LD = 468.7 mg

In practice the dose is rounded to a convenient amount.

7.Clinical nursing

Answer: D · Raise the concern through the local safeguarding (adult protection) procedure

Why this is the answer

Financial abuse is a form of adult abuse. Nurses report concerns through safeguarding procedures, document facts accurately and involve the patient as appropriate.

Answer

D · Raise the concern through the local safeguarding (adult protection) procedure
8.Clinical nursing

Answer: B · "If I forget a dose, I'll take two the next day to catch up."

Why this is the answer

Doubling up on an anticoagulant increases the bleeding risk. Patients follow the specific missed-dose advice for their drug and never take a double dose.

Answer

B · "If I forget a dose, I'll take two the next day to catch up."

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