Lab Values for Nurses: cram pack

Formula sheets, the key method steps for every topic and 8 practice problems, with full solutions at the back.

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1Formulas and methods

Lab values & electrolytes

Method

  1. Compare the value with the laboratory’s own reference range, then with the patient’s baseline and trend.
  2. Check the sample: hemolysis, a delay, or blood drawn near an IV can give false results.
  3. Link the value to its typical signs and to the drugs and conditions that cause it.
  4. Look for interactions: low potassium or magnesium increases digoxin toxicity; dehydration raises lithium.
  5. Act on the patient: assess, hold a drug if the level is unsafe, read back critical values and inform the prescriber.

Arterial blood gas interpretation

Normal ranges
pH 7.35–7.45, PaCO₂ 35–45 mmHg (4.7–6.0 kPa), HCO₃⁻ 22–26 mmol/L
ROME
Respiratory: PaCO₂ opposite to pH; Metabolic: HCO₃⁻ equal to pH
Winter’s formula
PaCO₂ = 1.5·HCO₃⁻ + 8 ± 2
Metabolic alkalosis
PaCO₂ ≈ 0.7·HCO₃⁻ + 21
Anion gap
AG = Na⁺ − (Cl⁻ + HCO₃⁻) ≈ 8–12
Albumin-corrected gap
AG + 2.5·(4.0 − alb g/dL) = AG + 0.25·(40 − alb g/L)
Delta ratio
(AG − 12)/(24 − HCO₃⁻)
P/F ratio
PaO₂/FiO₂
Alveolar gas equation
PAO₂ = FiO₂·(760 − 47) − PaCO₂/0.8
Serum osmolality
2·Na⁺ + glucose + urea (2·Na⁺ + glucose/18 + BUN/2.8)

Method

  1. Read the pH: below 7.35 is acidosis, above 7.45 alkalosis.
  2. Find the value that explains it: PaCO₂ moving opposite to the pH is respiratory, HCO₃⁻ moving with the pH is metabolic.
  3. Look at the other value: normal means uncompensated, abnormal in the compensating direction means partial compensation, and a normal pH with both abnormal means full compensation.
  4. In a metabolic acidosis, compare PaCO₂ with Winter’s formula, 1.5·HCO₃⁻ + 8 ± 2, and calculate the anion gap Na⁺ − (Cl⁻ + HCO₃⁻).
  5. Check a high anion gap with the delta ratio and, when albumin is low, with the corrected gap.

Clinical pharmacokinetics

Rate constant and half-life
k = ln 2/t½ = 0.693/t½
First-order decay
C = C₀·e−kt = C₀·(1/2)t/t½
Two levels
k = ln(C₁/C₂)/Δt
Volume and clearance
Vd = dose/C₀, CL = k·Vd
Loading dose
LD = Vd·C/(S·F)
Maintenance rate
R = CL·Css/(S·F)
Average steady state
Css,avg = S·F·D/(CL·τ)
Steady state
1 − (1/2)ⁿ after n half-lives; ≈ 97% after 5
Infusion
C = (R/CL)(1 − e−kt)
Interval and dose from peak and trough
τ = ln(Cpeak/Ctrough)/k, D = Vd·(Cpeak − Ctrough)
Cockcroft–Gault
CrCl = (140 − age) × kg/(72 × SCr mg/dL), × 0.85 for women
Renal adjustment
dose × CrCl/normal; Dettli Q = 1 − fe·(1 − CrCl/normal)

Method

  1. Convert the half-life to a rate constant: k = 0.693/t½.
  2. Turn per-kg values into totals: Vd (L) = L/kg × weight, CL (L/h) = L/kg/h × weight.
  3. Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
  4. For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
  5. Check the result: levels fall by half every half-life, and steady state takes about five half-lives.

2Practice problems

1.Lab values & electrolytesMedium

When should blood cultures be taken for a patient with suspected sepsis?

  1. AAfter the first three doses of antibiotics
  2. BBefore the first antibiotic dose, without delaying it much
  3. COnly if the fever lasts more than three days
  4. DAt any time, since antibiotics do not affect the result
2.Lab values & electrolytesHard

A lithium level of 1.0 mEq/L was drawn 2 hours after the patient’s morning dose, and the prescriber plans to raise the dose. What should the nurse point out?

  1. ALithium levels can be drawn at any time of day without affecting the result
  2. BThe level is toxic, so lithium should be stopped for good
  3. CThe sample was taken too soon after the dose, so it is not a valid level
  4. DThe level is too low, so a large increase is clearly safe
3.Arterial blood gas interpretationMedium
pH7.357.457.53PaCO₂mmHg354551HCO₃⁻mmol/L222641uncompensatedpartially compensatedfully compensated

A practice arterial blood gas shows pH 7.53, PaCO₂ 51 mmHg (6.8 kPa) and HCO₃⁻ 41 mmol/L. The primary disorder is metabolic alkalosis. How far is it compensated? Click your answer.

pH 7.53PaCO₂ 51 mmHg (6.8 kPa)HCO₃⁻ 41 mmol/L
  1. 1uncompensated
  2. 2partially compensated
  3. 3fully compensated
4.Arterial blood gas interpretationHard

At sea level, a practice gas taken on 35% oxygen shows PaO₂ 89 mmHg (11.9 kPa) and PaCO₂ 38 mmHg (5.1 kPa). Use PAO₂ = FiO₂·(760 − 47) − PaCO₂/0.8 to find the A–a gradient.

FiO₂ 35%PaO₂ 89 mmHg (11.9 kPa)PaCO₂ 38 mmHg (5.1 kPa)
A–a gradient = mmHg
5.Clinical pharmacokineticsMedium
VCss​ = 25 mg/LR = ? mg/hCL = 80 mL/min

Practice exercise (made-up values, not clinical guidance). Vancomycin is given as a continuous infusion to a patient whose vancomycin clearance is 80 mL/min. What infusion rate R in mg/h gives a steady-state level of 25 mg/L?

CL = 80 mL/minCss = 25 mg/L
R = mg/h
6.Clinical pharmacokineticsHard
0.1110t (h)C (mg/L)Cpeak​ = 7τ = ?Ctrough​ = 1

Practice exercise (made-up values, not clinical guidance). A patient's gentamicin half-life is 2.5 h. The target is a peak of 7 mg/L and a trough of 1 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 2.5 hCpeak = 7 mg/LCtrough = 1 mg/L
τ = h
7.Clinical nursingMedium

A patient is newly confused, has a respiratory rate of 24/min and a systolic blood pressure of 95 mmHg. What should you suspect first?

  1. AAnxiety
  2. BAlcohol intoxication
  3. CNormal postoperative recovery
  4. DSepsis
8.Clinical nursingHard

A patient with small cell lung cancer has hyponatraemia, concentrated urine and no signs of dehydration. Which condition and first measure fit best?

  1. ADiabetes insipidus, managed with extra fluids
  2. BSIADH, often managed first with fluid restriction
  3. CDehydration, managed with an IV fluid bolus
  4. DCushing's syndrome, managed with potassium

3Solutions

1.Lab values & electrolytes

Answer: B · Before the first antibiotic dose, without delaying it much

Why this is the answer

Blood cultures are taken before antibiotics, because even one dose can prevent bacteria from growing and hide the cause. Antibiotics should still be started quickly, ideally within an hour.Checked against: Sepsis · MedlinePlus (NIH) (2024)

Answer

B · Before the first antibiotic dose, without delaying it much
2.Lab values & electrolytes

Answer: C · The sample was taken too soon after the dose, so it is not a valid level

Why this is the answer

Lithium levels are standardized at about 12 hours after the last dose, usually just before the morning dose. A sample 2 hours after a dose catches the absorption peak and is not comparable with the target range, so the dose should not be changed on it.

Answer

C · The sample was taken too soon after the dose, so it is not a valid level
3.Arterial blood gas interpretation

Answer: partially compensated

Reading a blood gas (ROME): first the pH: below 7.35 is acidaemia, above 7.45 alkalaemia. Then find the value that explains it. PaCO₂ (normal 35–45 mmHg, 4.7–6.0 kPa) is the respiratory part and moves Opposite to the pH in a respiratory disorder; HCO₃⁻ (normal 22–26 mmol/L) is the metabolic part and moves in the same direction as the pH (Respiratory Opposite, Metabolic Equal). The other value shows the compensation: normal means uncompensated; abnormal in the direction that pulls the pH back while the pH is still abnormal means partially compensated; a normal pH with both values abnormal means fully compensated. Ranges differ slightly between laboratories; these are practice values.

ROME, value by value

pH 7.53: alkalaemia (above 7.45)
PaCO₂ 51 mmHg: high (35–45)
HCO₃⁻ 41 mmol/L: high (22–26)

Compensation

partially compensated

Answer

partially compensated
4.Arterial blood gas interpretation

Answer: A–a gradient = 113 mmHg

Derived values: calculated serum osmolality is 2·Na⁺ + glucose + urea with all values in mmol/L (2·Na⁺ + glucose/18 + BUN/2.8 with glucose and BUN in mg/dL); normal is about 275–295 mOsm/kg. The P/F ratio is PaO₂ divided by FiO₂ as a fraction. The alveolar oxygen pressure is PAO₂ = FiO₂·(760 − 47) − PaCO₂/0.8 mmHg at sea level, and the A–a gradient is PAO₂ − PaO₂.

Alveolar oxygen

PAO₂ = 0.35·713 − 38/0.8 = 249.5 − 47.5 = 202 mmHg

Gradient

A–a = 202 − 89 = 113 mmHg

Answer

A–a gradient = 113 mmHg
5.Clinical pharmacokinetics

Answer: R = 120 mg/h

Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Clearance in L/h

80·60/1000 = 4.8 L/h

Infusion rate

R = 4.8·25 = 120 mg/h

Answer

R = 120 mg/h
6.Clinical pharmacokinetics

Answer: τ = 7 h

Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Rate constant

k = 0.693/2.5 = 0.2773 h⁻¹

Dosing interval

τ = ln(7/1)/0.2773 = 1.946/0.2773 = 7.018 ≈ 7 h

Answer

τ = 7 h

In practice the interval is rounded to a convenient value such as 8, 12, 24 or 36 h, and the levels are checked again.

7.Clinical nursing

Answer: D · Sepsis

Why this is the answer

These three signs form the qSOFA criteria and suggest a high risk of poor outcome from sepsis. Escalate urgently and start the sepsis pathway.

Answer

D · Sepsis
8.Clinical nursing

Answer: B · SIADH, often managed first with fluid restriction

Why this is the answer

In SIADH, excess ADH makes the kidneys retain water, so blood sodium is diluted while urine is concentrated. Small cell lung cancer is a classic cause; fluid restriction is a common first step.

Answer

B · SIADH, often managed first with fluid restriction

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