Read the pH: below 7.35 is acidosis, above 7.45 alkalosis.
Find the value that explains it: PaCO₂ moving opposite to the pH is respiratory, HCO₃⁻ moving with the pH is metabolic.
Look at the other value: normal means uncompensated, abnormal in the compensating direction means partial compensation, and a normal pH with both abnormal means full compensation.
In a metabolic acidosis, compare PaCO₂ with Winter’s formula, 1.5·HCO₃⁻ + 8 ± 2, and calculate the anion gap Na⁺ − (Cl⁻ + HCO₃⁻).
Check a high anion gap with the delta ratio and, when albumin is low, with the corrected gap.
Write down what is asked: a pump rate, a volume, kilocalories, grams of protein or water.
Turn energy into volume with mL = kcal/(kcal/mL), and volume into protein with litres × g/L.
Divide by the hours the feed actually runs for a rate, or by the number of feeds for a bolus.
For needs, multiply kcal/kg or g/kg by the weight the rule names; find the ideal body weight with Devine: 50 or 45.5 + 2.3 × (inches − 60).
For PN, find grams as % × mL/100, then use 3.4 kcal/g for dextrose, 4 kcal/g for amino acids and the stated kcal/mL for lipid.
ECG rhythm strip interpretation
Paper (25 mm/s, 10 mm/mV)
1 small box = 0.04 s, 1 large box = 0.20 s, 10 mm = 1 mV
Heart rate, regular rhythm
300 ÷ large boxes = 1500 ÷ small boxes = 60 ÷ RR (s)
Heart rate, irregular rhythm
QRS complexes in 6 s × 10
Normal PR interval
0.12–0.20 s
Normal QRS duration
< 0.12 s
QTc (Bazett)
QT/√RR
QTc (Fridericia)
QT/∛RR
QTc (Framingham)
QT + 154·(1 − RR)
Sinus rates
bradycardia < 60, normal 60–100, tachycardia > 100 /min
Escape rates
junctional 40–60, ventricular 20–40 /min
Fast rhythms
SVT 150–250 /min (narrow), VT > 100 /min (wide)
Method
Rate: for a regular rhythm divide 300 by the large boxes or 1500 by the small boxes between two R waves; for an irregular rhythm count the QRS complexes in 6 seconds and multiply by 10.
Rhythm: compare the R–R intervals. Equal is regular; a repeating pattern is regularly irregular; no pattern at all is irregularly irregular.
P waves: is there an upright P wave in lead II before every QRS, all alike? Look for fibrillatory or sawtooth waves, inverted P waves and P waves without a QRS.
PR interval: from the start of P to the start of the QRS, normally 0.12–0.20 s and constant. Watch whether it lengthens, stays fixed before a dropped beat, or varies at random.
QRS duration: below 0.12 s is narrow; 0.12 s or more is wide. Then name the rhythm, and for the QT use QTc = QT/√RR (Bazett) with times in seconds.
Prioritization & delegation
Method
Ask what will harm the patient soonest if nothing is done.
Apply ABC (C-A-B in cardiac arrest), then Maslow: physiological needs before safety, safety before psychological needs.
Compare the options: acute before chronic, unstable before stable, unexpected before expected, systemic before local, and check each finding against the patient’s baseline.
Assess before you act unless it is an emergency; then choose the step the others depend on.
For delegation, check the five rights: task, circumstance, person, directions and supervision. Assessment, teaching and evaluation stay with the RN.
Infection control & patient safety
Method
Start with standard precautions for every patient: hand hygiene, PPE for the expected exposure, safe sharps.
Keep sterile items sterile: if in doubt, it is not sterile; replace, never wipe.
Prevent harm in the environment: fall measures, restraints only as a last resort, RACE and PASS for fire.
Check the rights of medication administration, two identifiers and extra safeguards for high-alert drugs; report errors and near misses.
Lab values & electrolytes
Method
Compare the value with the laboratory’s own reference range, then with the patient’s baseline and trend.
Check the sample: hemolysis, a delay, or blood drawn near an IV can give false results.
Link the value to its typical signs and to the drugs and conditions that cause it.
Look for interactions: low potassium or magnesium increases digoxin toxicity; dehydration raises lithium.
Act on the patient: assess, hold a drug if the level is unsafe, read back critical values and inform the prescriber.
2Practice problems
1.Nursing fundamentalsMedium
In adult basic life support, how long should the rescuer take to check for normal breathing?
AAs long as it takes to be certain
BAt least one minute
CAbout 30 seconds
DNo more than 10 seconds
2.Nursing fundamentalsHard
Vaccinating staff against influenza breaks the chain of infection at which link?
AThe susceptible host
BThe reservoir
CThe mode of transmission
DThe portal of exit
3.Clinical nursingMedium
Why is blood pressure monitored closely in a patient with an epidural infusion?
AThe local anaesthetic can block sympathetic nerves and cause hypotension
BThe epidural pump uses the blood pressure to set the rate
CBlood pressure readings show whether the catheter is infected
DEpidurals always cause severe hypertension that needs regular treatment
4.Clinical nursingHard
A patient after major surgery has a falling blood pressure, rising heart rate and a swollen, tense abdomen, though the wound dressing is dry. What should you suspect?
AInternal bleeding
BUrinary tract infection
CNormal postoperative swelling with no concern
DConstipation
5.Arterial blood gas interpretationMedium
A practice arterial blood gas shows pH 7.55, PaCO₂ 40 mmHg (5.3 kPa) and HCO₃⁻ 34 mmol/L. The primary disorder is metabolic alkalosis. How far is it compensated? Click your answer.
pH 7.55PaCO₂ 40 mmHg (5.3 kPa)HCO₃⁻ 34 mmol/L
1uncompensated
2partially compensated
3fully compensated
6.Arterial blood gas interpretationHard
A practice gas shows a metabolic alkalosis with HCO₃⁻ 45 mmol/L. Use expected PaCO₂ = 0.7·HCO₃⁻ + 21 to find the expected PaCO₂.
HCO₃⁻ 45 mmol/L
PaCO₂ = mmHg
7.Clinical assessment scoresMedium
Practice exercise (made-up values, not clinical guidance). A patient has a pulse of 92/min and a blood pressure of 149/82 mmHg. Find the shock index SI = HR/SBP. Round to two decimal places.
HR 92/minBP 149/82 mmHg
SI =
8.Clinical assessment scoresHard
Practice exercise (made-up values, not clinical guidance). An adult weighs 108 kg and is 173 cm tall. Calculate the BMI and click the WHO weight category.
Practice exercise (made-up values, not clinical guidance). A woman is 176 cm tall and weighs 53 kg. Find the actual weight as a percentage of the ideal body weight, %IBW, using the Devine formula (1 in = 2.54 cm). Round to the nearest whole number.
Practice exercise (made-up values, not clinical guidance). A critically ill woman is 164 cm tall and weighs 131 kg. The practice protocol gives 2 g of protein per kg of ideal body weight (Devine) per day if the BMI is 30 to under 40 kg/m², and 2.5 g/kg of ideal body weight per day if the BMI is 40 kg/m² or more. Find the protein goal P in g/day. Round to the nearest whole number.
Measure the QT interval and the R–R interval on this regular lead II strip, then calculate the rate-corrected QTc with Bazett’s formula QTc = QT/√RR (both in seconds). Give the answer in seconds to three decimals.
lead II, 25 mm/s, 10 mm/mV1 small box = 0.04 s, 1 large box = 0.20 sstrip length 6 s
QTc = s
12.ECG rhythm strip interpretationHard
Identify the rhythm on this lead II strip. Click your answer.
lead II, 25 mm/s, 10 mm/mV1 small box = 0.04 s, 1 large box = 0.20 sstrip length 6 s
1ventricular tachycardia
2ventricular fibrillation
3atrial fibrillation
4torsades de pointes
13.Prioritization & delegationMedium
An older patient becomes confused over a few hours, with attention that comes and goes. What does this suggest?
ANormal aging that needs no action
BLong-standing dementia that is expected
CDelirium, which needs the cause found quickly
DA personality change that is permanent and expected
14.Prioritization & delegationHard
A patient with severe sepsis starts oozing blood from IV sites and the gums, and bruises appear on the skin. What should the nurse suspect?
AAn allergic reaction to the adhesive tape
BVitamin C deficiency
CDisseminated intravascular coagulation (DIC)
DNormal bruising from blood tests
15.Infection control & patient safetyMedium
In the US (EPA/OSHA) hazmat system, which level of PPE gives the highest level of protection?
ALevel C
BLevel D
CLevel B
DLevel A
16.Infection control & patient safetyHard
Only one airborne infection isolation room (negative pressure) is free. Which newly admitted patient should be placed in it?
AA patient with confirmed seasonal influenza and a cough
BA patient with C. difficile diarrhea
CA patient with suspected active pulmonary tuberculosis
DA patient with an MRSA wound infection
17.Lab values & electrolytesMedium
The heparin infusion rate was changed according to protocol. When is the aPTT usually rechecked?
AAbout 6 hours after the change
BAbout 3 days after the change
CAbout 30 minutes after the change
DOnly after the infusion is stopped
18.Lab values & electrolytesHard
A patient's low calcium does not improve despite several days of calcium replacement. Which other electrolyte should be checked and corrected?
AChloride
BBicarbonate
CSodium
DMagnesium
3Solutions
1.Nursing fundamentals
Answer: D · No more than 10 seconds
Why this is the answer
Rescuers look, listen and feel for normal breathing for no more than 10 seconds. If breathing is absent or not normal, they call for help and start CPR.
Answer
D · No more than 10 seconds
2.Nursing fundamentals
Answer: A · The susceptible host
Why this is the answer
Immunisation makes a person no longer susceptible, so the infection cannot establish itself in them. Hand hygiene, by contrast, breaks the mode of transmission.
Answer
A · The susceptible host
3.Clinical nursing
Answer: A · The local anaesthetic can block sympathetic nerves and cause hypotension
Why this is the answer
Epidural local anaesthetic can cause vasodilation and hypotension. Nurses also monitor sedation, respiratory rate, block height, motor function and the catheter site.
Answer
A · The local anaesthetic can block sympathetic nerves and cause hypotension
4.Clinical nursing
Answer: A · Internal bleeding
Why this is the answer
Haemodynamic signs of shock with abdominal distension suggest intra-abdominal haemorrhage, even without visible blood loss. Urgent surgical review is required.
Answer
A · Internal bleeding
5.Arterial blood gas interpretation
Answer: uncompensated
Reading a blood gas (ROME): first the pH: below 7.35 is acidaemia, above 7.45 alkalaemia. Then find the value that explains it. PaCO₂ (normal 35–45 mmHg, 4.7–6.0 kPa) is the respiratory part and moves Opposite to the pH in a respiratory disorder; HCO₃⁻ (normal 22–26 mmol/L) is the metabolic part and moves in the same direction as the pH (Respiratory Opposite, Metabolic Equal). The other value shows the compensation: normal means uncompensated; abnormal in the direction that pulls the pH back while the pH is still abnormal means partially compensated; a normal pH with both values abnormal means fully compensated. Ranges differ slightly between laboratories; these are practice values.
ROME, value by value
pH 7.55: alkalaemia (above 7.45)
PaCO₂ 40 mmHg: normal (35–45)
HCO₃⁻ 34 mmol/L: high (22–26)
Compensation
Clinically, also check the expected compensation: for a metabolic alkalosis PaCO₂ ≈ 0.7·HCO₃⁻ + 21 = 42.8–46.8 mmHg, so the measured 40 mmHg points to an additional respiratory alkalosis (a mixed disorder). The answer above is the ROME exam classification.
uncompensated
Answer
uncompensated
6.Arterial blood gas interpretation
Answer: PaCO₂ = 52.5 mmHg
Expected compensation: in metabolic acidosis Winter’s formula predicts PaCO₂ = 1.5·HCO₃⁻ + 8 ± 2 mmHg; a measured value above that range points to an additional respiratory acidosis, below it to an additional respiratory alkalosis. The anion gap AG = Na⁺ − (Cl⁻ + HCO₃⁻), normally about 8–12 mmol/L, separates high-gap from normal-gap metabolic acidosis; low albumin hides a high gap (add 2.5 per g/dL that albumin is below 4.0). The delta ratio (AG − 12)/(24 − HCO₃⁻) between about 0.8 and 2 fits a pure high-gap acidosis (some texts use 1 instead of 0.8), below that an added normal-gap acidosis, and above 2 an added metabolic alkalosis.
Expected PaCO₂
0.7·45 + 21 = 52.5 mmHg
Answer
PaCO₂ = 52.5 mmHg
The rise has a limit: PaCO₂ rarely goes above about 55 mmHg from compensation alone.
7.Clinical assessment scores
Answer: SI = 0.62
Blood pressure values: pulse pressure PP = SBP − DBP. Mean arterial pressure MAP ≈ (SBP + 2·DBP)/3 = DBP + PP/3, an estimate based on the heart spending about two thirds of each beat in diastole at a normal heart rate (less accurate when the heart rate is fast); a MAP of at least about 65 mmHg is a common target for organ perfusion. The shock index SI = heart rate/SBP is normally about 0.5–0.7; a value above about 1 is a warning sign of shock.
Shock index
SI = 92/149 = 0.6174 ≈ 0.62
Answer
SI = 0.62
Within or below the usual 0.5–0.7.
8.Clinical assessment scores
Answer: obesity class II
Body mass index: BMI = weight (kg)/height (m)², with the height converted to metres first. With pounds and inches, BMI = 703 × weight (lb)/height (in)². WHO adult categories: below 18.5 underweight, 18.5–24.9 healthy weight, 25.0–29.9 overweight, 30.0–34.9 obesity class I, 35.0–39.9 obesity class II and 40 or more obesity class III.
BMI
BMI = 108/1.73² = 36.09
Category
obesity class II
Answer
obesity class II
9.Enteral & parenteral nutrition calculations
Answer: %IBW = 79 %
Needs and free water: energy needs are often estimated as kcal/kg/day × weight and protein needs as g/kg/day × weight. A formula is only partly water, so its free water = volume × water fraction; water flushes make up the rest of the daily fluid goal. Ideal body weight (Devine): IBW = 50 kg + 2.3 kg for every inch over 5 feet (60 in) for men, and 45.5 kg + 2.3 kg per inch over 60 in for women; 1 in = 2.54 cm. The formula is meant for adults at least 152.4 cm (5 ft) tall. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Ideal body weight (Devine)
176 cm/2.54 = 69.29 in
IBW = 45.5 + 2.3·(69.29 − 60) = 66.87 kg
Percentage of ideal body weight
%IBW = 53/66.87·100 = 79.26 ≈ 79%
Answer
%IBW = 79%
10.Enteral & parenteral nutrition calculations
Answer: P = 140 g/day
Ideal body weight (Devine): IBW = 50 kg + 2.3 kg for every inch over 5 feet (60 in) for men, and 45.5 kg + 2.3 kg per inch over 60 in for women; 1 in = 2.54 cm. The formula is meant for adults at least 152.4 cm (5 ft) tall. Obesity in critical illness (ASPEN/SCCM 2016): BMI = weight/height² (kg/m²). The protein goal is 2 g/kg of ideal body weight per day for BMI 30–40 and up to 2.5 g/kg of ideal body weight per day for BMI 40 and above. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Body mass index
BMI = 131/1.64² = 48.71 kg/m²
Ideal body weight (Devine)
164 cm/2.54 = 64.57 in
IBW = 45.5 + 2.3·(64.57 − 60) = 56 kg
Protein goal
BMI 40 or more: 2.5 g per kg of ideal body weight.
P = 2.5·56 = 140 g/day
Answer
P = 140 g/day
11.ECG rhythm strip interpretation
Answer: QTc = 0.48 s
QT and QTc: the QT interval runs from the start of the QRS complex to the end of the T wave. It shortens as the heart rate rises, so it is corrected for rate with the R–R interval in seconds: Bazett QTc = QT/√RR and Fridericia QTc = QT/∛RR. Bazett is the formula most textbooks use; it over-corrects at fast rates, where Fridericia is preferred. Limits differ between references: a QTc above about 0.45 s in men or 0.46 s in women is usually called prolonged, and above 0.50 s markedly prolonged.
Measure
QT = 12 × 0.04 = 0.48 s
RR = 25 × 0.04 = 1.00 s
Bazett’s formula
QTc = 0.48/√1.00 = 0.48/1 = 0.48 s
Answer
QTc = 0.48 s
Above the usual limits for both men (about 0.45 s) and women (about 0.46 s): prolonged. (480 ms)
12.ECG rhythm strip interpretation
Answer: ventricular tachycardia
Ventricular rhythms: ventricular tachycardia is a run of three or more wide (0.12 s or more) complexes in a row at more than 100/min, usually 150–250/min, regular, without related P waves. Ventricular fibrillation is a chaotic, irregular waveform with no identifiable P waves, QRS complexes or T waves and no countable rate. Asystole is an almost flat line with no ventricular activity; a flat line is always confirmed by checking the patient, the leads and the gain and a second lead. In resuscitation guidelines VF and pulseless VT are the shockable rhythms and asystole is not.
Five steps
1. Rate: R–R = 10 small boxes, 1500 ÷ 10 ≈ 150 per minute.
2. Rhythm: regular, every R–R is 0.40 s.
3. P waves: none identifiable.
4. PR interval: not measurable.
5. QRS: 0.16 s, wide (0.12 s or more).
Interpretation
ventricular tachycardia
Answer
ventricular tachycardia
In resuscitation guidelines VF and pulseless VT are the shockable rhythms. This is identification practice only.
13.Prioritization & delegation
Answer: C · Delirium, which needs the cause found quickly
Why this is the answer
Delirium starts suddenly, over hours or days, and attention fluctuates. It often has a treatable cause such as infection, hypoxia or medication, so it is a priority to assess.
Answer
C · Delirium, which needs the cause found quickly
14.Prioritization & delegation
Answer: C · Disseminated intravascular coagulation (DIC)
Why this is the answer
In DIC, widespread clotting uses up platelets and clotting factors, causing bleeding from many sites. It is a serious complication of sepsis that needs urgent escalation.
Answer
C · Disseminated intravascular coagulation (DIC)
15.Infection control & patient safety
Answer: D · Level A
Why this is the answer
Level A is a fully encapsulating, vapor-tight suit with self-contained breathing apparatus, used for unknown or highly toxic agents. Level D is ordinary work clothing with minimal protection.
Answer
D · Level A
16.Infection control & patient safety
Answer: C · A patient with suspected active pulmonary tuberculosis
Why this is the answer
Tuberculosis needs airborne precautions in a negative-pressure room. Influenza needs droplet precautions and MRSA and C. difficile need contact precautions, which can be given in an ordinary single room.
Answer
C · A patient with suspected active pulmonary tuberculosis
17.Lab values & electrolytes
Answer: A · About 6 hours after the change
Why this is the answer
Most weight-based heparin protocols check the aPTT (or anti-Xa level) about 6 hours after starting or changing the rate, because it takes this long to reach a new steady state. Checking too early can lead to wrong adjustments.
Answer
A · About 6 hours after the change
18.Lab values & electrolytes
Answer: D · Magnesium
Why this is the answer
Low magnesium reduces parathyroid hormone secretion and the body's response to it, so hypocalcemia does not correct until magnesium is replaced. The same applies to refractory hypokalemia.Checked against:Magnesium Blood Test · MedlinePlus (NIH) (2023)