Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.PharmacologyMedium
In which patient is bupropion contraindicated?
AA patient who wants to stop smoking
BA patient with seasonal allergies
CA patient with a seizure disorder or an eating disorder
DA patient with high blood cholesterol and a family history of it
2.PharmacologyHard
A nurse calculates a child's dose and finds it is ten times higher than the usual range in the drug reference. What should the nurse do?
AGive the dose, because the prescriber is responsible for the order
BWithhold it, recheck the calculation and clarify with the prescriber
CGive half the dose as a compromise
DGive one tenth of the dose without telling anyone
3.Dosage calculationsMedium
A patient weighs 60 kg and is prescribed 10 mg/kg as a single dose. Find the dose D in mg.
60 kg10 mg/kg
D = mg
4.Dosage calculationsHard
A patient is 163 cm tall and weighs 77 kg. The prescription is 60 mg/m². Using the Mosteller formula BSA = √(height (cm) × weight (kg)/3600), find the dose D in mg.
163 cm77 kg60 mg/m²
D = mg
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). A 68 kg patient is to be loaded with digoxin tablets to reach a level of 0.8 mcg/L. The volume of distribution is 7 L/kg and the tablets have a bioavailability F = 0.7. Find the total oral loading dose LD in mcg.
68 kgVd = 7 L/kgC = 0.8 mcg/LF = 0.7
LD = mcg
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). A patient receives vancomycin IV every 12 h; the vancomycin clearance is 6 L/h. What dose D in mg gives an average steady-state level of 20 mg/L?
CL = 6 L/hτ = 12 hS = 1F = 1Css,avg = 20 mg/L
D = mg
3Solutions
1.Pharmacology
Answer: C · A patient with a seizure disorder or an eating disorder
Why this is the answer
Bupropion increases the risk of seizures, especially with bulimia or anorexia, where electrolyte disturbances are common. It is used for depression and as a smoking cessation aid.
Answer
C · A patient with a seizure disorder or an eating disorder
2.Pharmacology
Answer: B · Withhold it, recheck the calculation and clarify with the prescriber
Why this is the answer
Doses outside the safe range must be questioned before administration. The nurse holds the dose, rechecks the weight and calculation and contacts the prescriber or pharmacist.
Answer
B · Withhold it, recheck the calculation and clarify with the prescriber
3.Dosage calculations
Answer: D = 600 mg
Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.
Dose
10·60 = 600 mg
Answer
D = 600 mg
4.Dosage calculations
Answer: D = 112 mg
Body-surface-area dosing: many cytotoxic and some paediatric doses are prescribed per square metre of body surface area: dose (mg) = dose per m² × BSA (m²). The Mosteller formula estimates BSA = √(height (cm) × weight (kg)/3600).
Body surface area
BSA = √(163·77/3600) = √3.486 = 1.867 m²
Dose
D = 60·1.867 = 112 mg
Answer
D = 112 mg
5.Clinical pharmacokinetics
Answer: LD = 544 mcg
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Volume of distribution
Vd = 7·68 = 476 L
Amount of active drug needed
Vd·C = 476·0.8 = 380.8 mcg
Loading dose
LD = 380.8/(1·0.7) = 544 mcg
Answer
LD = 544 mcg
In practice the dose is rounded to a convenient amount.
6.Clinical pharmacokinetics
Answer: D = 1440 mg
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.