Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.PharmacologyMedium
How do SGLT2 inhibitors such as empagliflozin lower blood glucose?
AThey stimulate insulin release from beta cells
BThey make the liver store more glycogen
CThey increase the loss of glucose in the urine
DThey slow the emptying of the stomach
2.PharmacologyHard
Two days after starting chemotherapy for a leukaemia with a high white cell count, a patient has reduced urine output. Which lab pattern suggests tumour lysis syndrome?
AHigh potassium, high phosphate, high uric acid and low calcium
BHigh sodium, high glucose and low potassium
CNormal electrolytes with a high haemoglobin
DLow potassium, low phosphate, low uric acid and high calcium
3.Dosage calculationsMedium
A child weighing 8 kg is prescribed 2.5 mg/kg of a drug. The stock solution contains 20 mg/mL. Draw up the dose: what volume V do you give?
8 kg2.5 mg/kg20 mg/mL
V = mL
4.Dosage calculationsHard
The prescription is 1600 units of a drug that comes as 5000 units/mL. Draw up the dose in the 1 mL syringe: what volume V do you give?
1600 units5000 units/mL
V = mL
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). A 77 kg patient is to be loaded intravenously with phenytoin sodium to reach a phenytoin level of 15 mg/L. The volume of distribution is 0.7 L/kg and the salt factor is S = 0.92. Find the loading dose LD of phenytoin sodium in mg.
77 kgVd = 0.7 L/kgC = 15 mg/LS = 0.92
LD = mg
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). A 51-year-old man weighs 64 kg and has a serum creatinine of 2.8 mg/dL (248 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual digoxin dose is 250 mcg for a creatinine clearance of 120 mL/min, and a fraction fe = 0.7 of the drug is excreted unchanged by the kidneys. Using the Dettli dose fraction Q = 1 − fe·(1 − CrCl/normal CrCl), find the adjusted dose D. Round to the nearest whole number.
Answer: C · They increase the loss of glucose in the urine
Why this is the answer
SGLT2 reabsorbs most filtered glucose in the proximal tubule. Blocking it lets glucose leave in the urine, which also explains the higher risk of genital fungal infections.
Answer
C · They increase the loss of glucose in the urine
2.Pharmacology
Answer: A · High potassium, high phosphate, high uric acid and low calcium
Why this is the answer
Rapid tumour cell death releases potassium, phosphate and nucleic acids (which become uric acid). Phosphate binds calcium, lowering it; prevention includes IV fluids and drugs that lower uric acid.
Answer
A · High potassium, high phosphate, high uric acid and low calcium
3.Dosage calculations
Answer: V = 1 mL
Drawing up a dose: volume = (prescribed dose/stock strength) × stock volume. Convert to the same units first, then check that the volume fits the syringe and lands on one of its graduations.
Dose from body weight
D = 2.5·8 = 20 mg
Volume
V = 20/20 = 1 mL
On the syringe
On this 10 mL syringe every small line is 0.2 mL.
Answer
V = 1 mL
4.Dosage calculations
Answer: V = 0.32 mL
Drawing up a dose: volume = (prescribed dose/stock strength) × stock volume. Convert to the same units first, then check that the volume fits the syringe and lands on one of its graduations.
Volume
V = 1600/5000 = 0.32 mL
On the syringe
On this 1 mL syringe every small line is 0.01 mL.
Answer
V = 0.32 mL
5.Clinical pharmacokinetics
Answer: LD = 878.8 mg
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Volume of distribution
Vd = 0.7·77 = 53.9 L
Amount of active drug needed
Vd·C = 53.9·15 = 808.5 mg
Loading dose
LD = 808.5/(0.92·1) = 878.8 mg
Answer
LD = 878.8 mg
In practice the dose is rounded to a convenient amount.
6.Clinical pharmacokinetics
Answer: D = 116 mcg
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Creatinine clearance (Cockcroft–Gault)
CrCl = (140 − 51)·64/(72·2.8) = 28.25 mL/min
Dose fraction (Dettli)
Q = 1 − 0.7·(1 − 28.25/120) = 0.4648
Adjusted dose
D = 0.4648·250 = 116.2 ≈ 116 mcg
Answer
D = 116 mcg
In practice the dose is rounded to a convenient amount and checked against the product information.