Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.PharmacologyMedium
Combining an SSRI with which drug most increases the risk of serotonin syndrome?
AOmeprazole
BAmoxicillin
CParacetamol
DA monoamine oxidase inhibitor
2.PharmacologyHard
A patient with myasthenia gravis took extra pyridostigmine doses. She now has increasing weakness, heavy salivation, sweating, small pupils and diarrhoea. What is the most likely cause?
ACholinergic crisis from too much anticholinesterase drug
BMyasthenic crisis from too little anticholinesterase drug
CAn allergic reaction to pyridostigmine
DA stroke unrelated to the medication
3.Dosage calculationsMedium
A child weighing 12 kg is prescribed 7.5 mg/kg of a drug. The stock solution contains 25 mg/mL. Draw up the dose: what volume V do you give?
12 kg7.5 mg/kg25 mg/mL
V = mL
4.Dosage calculationsHard
The prescription is 660 micrograms. The ampoule contains 2 mg/mL. Draw up the dose in the 1 mL syringe: what volume V do you give?
660 mcg2 mg/mL
V = mL
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). After an IV dose of gentamicin, the level is 6 mg/L at 2 h and 1.1 mg/L at 7 h. Assume first-order elimination. Find the elimination rate constant k.
C1 = 6 mg/L (2 h)C2 = 1.1 mg/L (7 h)
k = h⁻¹
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). A patient receives vancomycin IV every 12 h; the vancomycin clearance is 5 L/h. Each dose is 1250 mg of vancomycin. Find the average steady-state level Css,avg.
CL = 5 L/hτ = 12 hS = 1F = 1D = 1250 mg
Css,avg = mg/L
3Solutions
1.Pharmacology
Answer: D · A monoamine oxidase inhibitor
Why this is the answer
SSRIs block serotonin reuptake and MAO inhibitors block its breakdown. Together they can cause serotonin syndrome with agitation, hyperthermia, tremor and clonus.
Answer
D · A monoamine oxidase inhibitor
2.Pharmacology
Answer: A · Cholinergic crisis from too much anticholinesterase drug
Why this is the answer
Excess acetylcholine causes muscarinic signs (salivation, sweating, miosis, diarrhoea) and depolarising weakness. In myasthenic crisis, weakness occurs without these cholinergic signs; both can cause respiratory failure.
Answer
A · Cholinergic crisis from too much anticholinesterase drug
3.Dosage calculations
Answer: V = 3.6 mL
Drawing up a dose: volume = (prescribed dose/stock strength) × stock volume. Convert to the same units first, then check that the volume fits the syringe and lands on one of its graduations.
Dose from body weight
D = 7.5·12 = 90 mg
Volume
V = 90/25 = 3.6 mL
On the syringe
On this 10 mL syringe every small line is 0.2 mL.
Answer
V = 3.6 mL
4.Dosage calculations
Answer: V = 0.33 mL
Drawing up a dose: volume = (prescribed dose/stock strength) × stock volume. Convert to the same units first, then check that the volume fits the syringe and lands on one of its graduations.
Same units
2 mg/mL = 2000 mcg/mL
Volume
V = 660/2000 = 0.33 mL
Answer
V = 0.33 mL
5.Clinical pharmacokinetics
Answer: k = 0.3393 h⁻¹
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Elimination rate constant
k = ln(6/1.1)/5 = 1.696/5 = 0.3393 h⁻¹
Answer
k = 0.3393 h⁻¹
6.Clinical pharmacokinetics
Answer: Css,avg = 20.83 mg/L
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.