Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.PharmacologyMedium
How long does it take, approximately, for a drug given at regular intervals to reach a steady state?
A1 half-life
BIt depends only on the dose size
C4 to 5 half-lives
D10 half-lives
2.PharmacologyHard
Which strategy is most effective at preventing errors with IV insulin infusions?
APreparing insulin infusions in advance and leaving them unlabelled
BAn independent double check and a smart pump with a drug library
CWriting "U" for units on the order
DUsing insulin syringes to measure large IV volumes
3.Dosage calculationsMedium
A dose of 1000 mg is needed from a 20% (w/v) solution. What volume V contains this dose?
1000 mg20% w/v
V = mL
4.Dosage calculationsHard
A patient is 111 cm tall and weighs 30 kg. The prescription is 25 mg/m². Using the Mosteller formula BSA = √(height (cm) × weight (kg)/3600), find the dose D in mg.
111 cm30 kg25 mg/m²
D = mg
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 230 mg of gentamicin. The level back-extrapolated to time zero is 12 mg/L and the half-life is 2 h. Find the volume of distribution Vd.
D = 230 mgC₀ = 12 mg/Lt½ = 2 h
Vd = L
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). A 49-year-old woman weighs 62 kg and has a serum creatinine of 3.3 mg/dL (292 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual tobramycin regimen is 120 mg every 8 h for a creatinine clearance of 100 mL/min. Keeping the dose, the interval is lengthened in proportion to the fall in clearance. Find the new dosing interval τ. Round to one decimal place.
With repeated dosing, the level approaches steady state after about 4–5 half-lives, whatever the dose. A loading dose can be used to reach it faster.
Answer
C · 4 to 5 half-lives
2.Pharmacology
Answer: B · An independent double check and a smart pump with a drug library
Why this is the answer
Independent double checks, standard concentrations and smart pumps with dose limits reduce insulin errors. "U" for units is avoided because it can be misread as a zero.
Answer
B · An independent double check and a smart pump with a drug library
3.Dosage calculations
Answer: V = 5 mL
Solution strengths: a percentage strength is grams per 100 mL, so 1% = 1 g/100 mL = 10 mg/mL. A ratio strength 1:1000 means 1 g in 1000 mL = 1 mg/mL; 1:10 000 is 0.1 mg/mL. For a dilution the amount of drug stays the same: C₁·V₁ = C₂·V₂.
Concentration
20% = 200 mg/mL
Volume
V = 1000/200 = 5 mL
Answer
V = 5 mL
4.Dosage calculations
Answer: D = 24.04 mg
Body-surface-area dosing: many cytotoxic and some paediatric doses are prescribed per square metre of body surface area: dose (mg) = dose per m² × BSA (m²). The Mosteller formula estimates BSA = √(height (cm) × weight (kg)/3600).
Body surface area
BSA = √(111·30/3600) = √0.925 = 0.9618 m²
Dose
D = 25·0.9618 = 24.04 mg
Answer
D = 24.04 mg
5.Clinical pharmacokinetics
Answer: Vd = 19.17 L
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Volume of distribution
Vd = 230/12 = 19.17 L
Answer
Vd = 19.17 L
6.Clinical pharmacokinetics
Answer: τ = 39.6 h
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Creatinine clearance (Cockcroft–Gault)
CrCl = (140 − 49)·62/(72·3.3)·0.85 = 20.18 mL/min
New interval
τ = 8·100/20.18 = 39.64 ≈ 39.6 h
Answer
τ = 39.6 h
In practice the interval is rounded to a convenient value such as 12, 24, 36 or 48 h.